Radiology Exam 4 Chapters 3-33 Questions & Answers | Dental Radiology Exam Prep
Dental radiography requires the use of _____ to _____ kV. 65, 100
Less than 65 kV = inadequate penetration
More than 100 kV = over-penetration
In general, a voltage around ______kV works best in most 70
dental imaging.
When kilovoltage is increased, the image will appear Darker (denser)
overall _______.
When kilovoltage is decreased, the image will appear Lighter
overall _______.
What is how sharply dark and light areas are Contrast
differentiated on an image?
________ kilovolateg peak settings (65-70 kVp) create a Lower
higher contrast image.
**best for detection of caries**
_________ kilovoltage peak settings (100 kVp) create a Higher
lower contrast image.
***good for detection of periapical/ periodontal
disease***
What supplies a higher QUANTITY of electrons? Milliamperes
Quantity of the x-ray beam refers to: the number of electrons moving and ultimately the number of x-rays produced.
Increasing amperage results in: an increased number of electrons traveling from cathode to anode and
production of an increased number of x-rays
The greater number of x-rays that are able to penetrate The denser (darker) the radiograph
an object:
, Radiology Exam 4 Chapters 3-33 Questions & Answers | Dental Radiology Exam Prep
What is a unit of measure used to describe the number Ampere (A)
of electrons (or amount of current) flowing through the
cathode filament?
____-____ mA is the norm. 6-8
3 multiple choice options
What regulates the temperature of the cathode Milliamperage
filament? 1 multiple choice option
For a BW or PA, we need an electron pulse duration of 0.2
about ______ seconds.
3 multiple choice options
________ + ______ + ________ = Perfect image density time, mA, kVp
If I _______ or _______ any variables in radiation physics, the increase, decrease
image ______ is going to change
0.16 sec + 65 kVp + 7 mA = great dental imaging
When milliamperage is increased, exposure time must decreased
be _______ to maintain constant density
Intensity is also effected by: Distance; increase or decrease makes a difference
The product of the quantity and quality per unit of area creates and intensity
and per unit of time of exposure:
Target to surface = Source to patients skin
Target to object = source to patients tooth
Target to receptor source to receptor/film
The intensity of the x-ray beam is reduced as the increases
distance __________.
Dental radiography requires the use of _____ to _____ kV. 65, 100
Less than 65 kV = inadequate penetration
More than 100 kV = over-penetration
In general, a voltage around ______kV works best in most 70
dental imaging.
When kilovoltage is increased, the image will appear Darker (denser)
overall _______.
When kilovoltage is decreased, the image will appear Lighter
overall _______.
What is how sharply dark and light areas are Contrast
differentiated on an image?
________ kilovolateg peak settings (65-70 kVp) create a Lower
higher contrast image.
**best for detection of caries**
_________ kilovoltage peak settings (100 kVp) create a Higher
lower contrast image.
***good for detection of periapical/ periodontal
disease***
What supplies a higher QUANTITY of electrons? Milliamperes
Quantity of the x-ray beam refers to: the number of electrons moving and ultimately the number of x-rays produced.
Increasing amperage results in: an increased number of electrons traveling from cathode to anode and
production of an increased number of x-rays
The greater number of x-rays that are able to penetrate The denser (darker) the radiograph
an object:
, Radiology Exam 4 Chapters 3-33 Questions & Answers | Dental Radiology Exam Prep
What is a unit of measure used to describe the number Ampere (A)
of electrons (or amount of current) flowing through the
cathode filament?
____-____ mA is the norm. 6-8
3 multiple choice options
What regulates the temperature of the cathode Milliamperage
filament? 1 multiple choice option
For a BW or PA, we need an electron pulse duration of 0.2
about ______ seconds.
3 multiple choice options
________ + ______ + ________ = Perfect image density time, mA, kVp
If I _______ or _______ any variables in radiation physics, the increase, decrease
image ______ is going to change
0.16 sec + 65 kVp + 7 mA = great dental imaging
When milliamperage is increased, exposure time must decreased
be _______ to maintain constant density
Intensity is also effected by: Distance; increase or decrease makes a difference
The product of the quantity and quality per unit of area creates and intensity
and per unit of time of exposure:
Target to surface = Source to patients skin
Target to object = source to patients tooth
Target to receptor source to receptor/film
The intensity of the x-ray beam is reduced as the increases
distance __________.
