ENGINEERING CIRCUIT ANALYSIS FINAL PAPER
SOLVED QUESTIONS WITH COMPLETE
ANSWERS
◉ Current Divider.
Answer: i₁ = (Is·R₂)/(R₁+R₂)
◉ Voltage Divider.
Answer: V₁ = (Vs·R₁)/(R₁+R₂)
◉ Source Transformation.
Answer: Is = Vs/Rs; Vs = Is·Rs
◉ Maximum Power Transfer.
Answer: Rth = RL
◉ Inductor Voltage.
Answer: V = L(di/dt)
◉ Inductor Energy.
Answer: W_L = ½L(i² - i₀²)
, ◉ Inductors in Series.
Answer: L_T = L₁ + L₂ + L₃
◉ Inductors in Parallel.
Answer: 1/L_T = 1/L₁ + 1/L₂ + 1/L₃
◉ Capacitor Current.
Answer: i = C(dv/dt)
◉ Capacitor Energy.
Answer: W_C = ½C(v² - v₀²)
◉ Capacitors in Series.
Answer: 1/C_T = 1/C₁ + 1/C₂ + 1/C₃
◉ Capacitors in Parallel.
Answer: C_T = C₁ + C₂ + C₃
◉ Energy.
Answer: E = ∫p dt = ∫i(t)v(t) dt
SOLVED QUESTIONS WITH COMPLETE
ANSWERS
◉ Current Divider.
Answer: i₁ = (Is·R₂)/(R₁+R₂)
◉ Voltage Divider.
Answer: V₁ = (Vs·R₁)/(R₁+R₂)
◉ Source Transformation.
Answer: Is = Vs/Rs; Vs = Is·Rs
◉ Maximum Power Transfer.
Answer: Rth = RL
◉ Inductor Voltage.
Answer: V = L(di/dt)
◉ Inductor Energy.
Answer: W_L = ½L(i² - i₀²)
, ◉ Inductors in Series.
Answer: L_T = L₁ + L₂ + L₃
◉ Inductors in Parallel.
Answer: 1/L_T = 1/L₁ + 1/L₂ + 1/L₃
◉ Capacitor Current.
Answer: i = C(dv/dt)
◉ Capacitor Energy.
Answer: W_C = ½C(v² - v₀²)
◉ Capacitors in Series.
Answer: 1/C_T = 1/C₁ + 1/C₂ + 1/C₃
◉ Capacitors in Parallel.
Answer: C_T = C₁ + C₂ + C₃
◉ Energy.
Answer: E = ∫p dt = ∫i(t)v(t) dt