NEET 2027
HIGH-WEIGHTAGE CHEMISTRY
PART 3
p-BLOCK • d & f-BLOCK • ALCOHOLS / PHENOLS / ETHERS CARBONYLS • AMINES •
BIOMOLECULES • POLYMERS
200 Unique High-Probability Practice Questions
No Repeat from Part 1 or Part 2 • Most Expected in NEET 2027
Special Features
✓ 200 fresh questions – zero overlap with previous parts
✓ Only high-weightage chapters still left for NEET
✓ Short theory + detailed why-correct / why-wrong
✓ Covers Inorganic + Organic + Biomolecules fully
✓ Professional colourful layout
, CONTENTS
1. p-Block Elements (Groups 15–18) — Theory + Q1 to Q40
2. d-Block & f-Block Elements — Theory + Q41 to Q65
3. Alcohols, Phenols and Ethers — Theory + Q66 to Q100
4. Aldehydes, Ketones and Carboxylic Acids — Theory + Q101 to Q140
5. Amines — Theory + Q141 to Q165
6. Biomolecules + Polymers + Everyday Chemistry — Theory + Q166 to Q200
Quick Revision Sheet — Last page
How to Use
1. Read short theory of each unit first.
2. Solve questions without looking at answers.
3. Study both why correct and why wrong options.
4. Revise the final formula/fact sheet before exam.
NEET 2027 | High-Weightage Chemistry | Part 3 Page 2
, 1. p-BLOCK ELEMENTS (GROUPS 15–18)
Group 15 (N family): Nitrogen shows catenation less than phosphorus; NH■ is basic, pyramidal; HNO■ is strong
acid; PCl■ has trigonal bipyramidal geometry. Group 16 (O family): Oxygen is diatomic; ozone is allotrope;
H■SO■ is dibasic; SF■ is octahedral and inert. Group 17 (Halogens): Reactivity F > Cl > Br > I; HF is liquid due to
H-bonding; interhalogen compounds exist. Group 18 (Noble gases): Inert due to stable octet; Xe forms compounds
with F and O (XeF■, XeF■, XeF■, XeO■). Inert pair effect increases down the group; oxidation states differ
accordingly.
Q1. The hybridisation of phosphorus in PCl■ is:
A. sp³
B. sp³d
C. sp³d²
D. dsp²
✓ Correct Answer: B
Why this is correct: PCl■ has five bond pairs and zero lone pairs. Steric number 5 → sp³d hybridisation → trigonal
bipyramidal shape.
✗ Why the other options are wrong:
• A is tetrahedral.
• C is octahedral.
• D is square planar.
Q2. Which of the following is the strongest reducing agent?
A. HF
B. HCl
C. HBr
D. HI
✓ Correct Answer: D
Why this is correct: Bond dissociation enthalpy decreases from HF to HI. HI has the weakest H–X bond and is therefore the
strongest reducing agent.
✗ Why the other options are wrong:
• A, B and C have stronger bonds and are weaker reducing agents.
Q3. The shape of XeF■ is:
A. Tetrahedral
B. Square planar
C. Trigonal bipyramidal
D. Octahedral
✓ Correct Answer: B
Why this is correct: XeF■ has 4 bond pairs and 2 lone pairs. Electron geometry is octahedral; molecular shape is square
planar (lone pairs opposite).
✗ Why the other options are wrong:
• A ignores lone pairs.
• C has wrong steric number.
• D is electron geometry, not molecular shape.
Q4. Ammonia is a Lewis base because it has:
A. Incomplete octet
B. A lone pair of electrons on nitrogen
C. Positive charge
D. Vacant d-orbitals
✓ Correct Answer: B
Why this is correct: Nitrogen in NH■ has one lone pair that can be donated to a Lewis acid; hence NH■ acts as a Lewis
base.
NEET 2027 | High-Weightage Chemistry | Part 3 Page 3
, ✗ Why the other options are wrong:
• A is false – N has complete octet.
• C is incorrect.
• D – nitrogen has no vacant d-orbitals.
Q5. Which oxide of nitrogen is used as an anaesthetic (laughing gas)?
A. NO
B. N■O
C. NO■
D. N■O■
✓ Correct Answer: B
Why this is correct: Nitrous oxide (N■O) is commonly known as laughing gas and is used as a mild anaesthetic.
✗ Why the other options are wrong:
• A, C and D have different properties and uses.
Q6. The hybridisation of sulphur in SF■ is:
A. sp³
B. sp³d
C. sp³d²
D. d²sp³
✓ Correct Answer: C
Why this is correct: SF■ has six bond pairs. Steric number 6 → sp³d² hybridisation → octahedral geometry.
✗ Why the other options are wrong:
• A and B have lower steric numbers.
• D is inner-orbital notation sometimes used for complexes.
Q7. Which of the following is not known?
A. XeF■
B. XeF■
C. XeF■
D. HeF■
✓ Correct Answer: D
Why this is correct: Helium does not form compounds under normal conditions because of its very high ionisation enthalpy
and complete n=1 shell. HeF■ is not known.
✗ Why the other options are wrong:
• A, B and C are well-characterised xenon fluorides.
Q8. The correct order of acidic strength is:
A. HF > HCl > HBr > HI
B. HI > HBr > HCl > HF
C. HCl > HF > HBr > HI
D. HBr > HI > HCl > HF
✓ Correct Answer: B
Why this is correct: Acidic strength of hydrogen halides increases down the group because bond strength decreases: HI is
the strongest acid and HF the weakest.
✗ Why the other options are wrong:
• A is the reverse order.
• C and D are incorrect sequences.
Q9. White phosphorus is stored under water because:
A. It is highly reactive towards air (catches fire)
B. It is soluble in water
C. It reacts with water
NEET 2027 | High-Weightage Chemistry | Part 3 Page 4
HIGH-WEIGHTAGE CHEMISTRY
PART 3
p-BLOCK • d & f-BLOCK • ALCOHOLS / PHENOLS / ETHERS CARBONYLS • AMINES •
BIOMOLECULES • POLYMERS
200 Unique High-Probability Practice Questions
No Repeat from Part 1 or Part 2 • Most Expected in NEET 2027
Special Features
✓ 200 fresh questions – zero overlap with previous parts
✓ Only high-weightage chapters still left for NEET
✓ Short theory + detailed why-correct / why-wrong
✓ Covers Inorganic + Organic + Biomolecules fully
✓ Professional colourful layout
, CONTENTS
1. p-Block Elements (Groups 15–18) — Theory + Q1 to Q40
2. d-Block & f-Block Elements — Theory + Q41 to Q65
3. Alcohols, Phenols and Ethers — Theory + Q66 to Q100
4. Aldehydes, Ketones and Carboxylic Acids — Theory + Q101 to Q140
5. Amines — Theory + Q141 to Q165
6. Biomolecules + Polymers + Everyday Chemistry — Theory + Q166 to Q200
Quick Revision Sheet — Last page
How to Use
1. Read short theory of each unit first.
2. Solve questions without looking at answers.
3. Study both why correct and why wrong options.
4. Revise the final formula/fact sheet before exam.
NEET 2027 | High-Weightage Chemistry | Part 3 Page 2
, 1. p-BLOCK ELEMENTS (GROUPS 15–18)
Group 15 (N family): Nitrogen shows catenation less than phosphorus; NH■ is basic, pyramidal; HNO■ is strong
acid; PCl■ has trigonal bipyramidal geometry. Group 16 (O family): Oxygen is diatomic; ozone is allotrope;
H■SO■ is dibasic; SF■ is octahedral and inert. Group 17 (Halogens): Reactivity F > Cl > Br > I; HF is liquid due to
H-bonding; interhalogen compounds exist. Group 18 (Noble gases): Inert due to stable octet; Xe forms compounds
with F and O (XeF■, XeF■, XeF■, XeO■). Inert pair effect increases down the group; oxidation states differ
accordingly.
Q1. The hybridisation of phosphorus in PCl■ is:
A. sp³
B. sp³d
C. sp³d²
D. dsp²
✓ Correct Answer: B
Why this is correct: PCl■ has five bond pairs and zero lone pairs. Steric number 5 → sp³d hybridisation → trigonal
bipyramidal shape.
✗ Why the other options are wrong:
• A is tetrahedral.
• C is octahedral.
• D is square planar.
Q2. Which of the following is the strongest reducing agent?
A. HF
B. HCl
C. HBr
D. HI
✓ Correct Answer: D
Why this is correct: Bond dissociation enthalpy decreases from HF to HI. HI has the weakest H–X bond and is therefore the
strongest reducing agent.
✗ Why the other options are wrong:
• A, B and C have stronger bonds and are weaker reducing agents.
Q3. The shape of XeF■ is:
A. Tetrahedral
B. Square planar
C. Trigonal bipyramidal
D. Octahedral
✓ Correct Answer: B
Why this is correct: XeF■ has 4 bond pairs and 2 lone pairs. Electron geometry is octahedral; molecular shape is square
planar (lone pairs opposite).
✗ Why the other options are wrong:
• A ignores lone pairs.
• C has wrong steric number.
• D is electron geometry, not molecular shape.
Q4. Ammonia is a Lewis base because it has:
A. Incomplete octet
B. A lone pair of electrons on nitrogen
C. Positive charge
D. Vacant d-orbitals
✓ Correct Answer: B
Why this is correct: Nitrogen in NH■ has one lone pair that can be donated to a Lewis acid; hence NH■ acts as a Lewis
base.
NEET 2027 | High-Weightage Chemistry | Part 3 Page 3
, ✗ Why the other options are wrong:
• A is false – N has complete octet.
• C is incorrect.
• D – nitrogen has no vacant d-orbitals.
Q5. Which oxide of nitrogen is used as an anaesthetic (laughing gas)?
A. NO
B. N■O
C. NO■
D. N■O■
✓ Correct Answer: B
Why this is correct: Nitrous oxide (N■O) is commonly known as laughing gas and is used as a mild anaesthetic.
✗ Why the other options are wrong:
• A, C and D have different properties and uses.
Q6. The hybridisation of sulphur in SF■ is:
A. sp³
B. sp³d
C. sp³d²
D. d²sp³
✓ Correct Answer: C
Why this is correct: SF■ has six bond pairs. Steric number 6 → sp³d² hybridisation → octahedral geometry.
✗ Why the other options are wrong:
• A and B have lower steric numbers.
• D is inner-orbital notation sometimes used for complexes.
Q7. Which of the following is not known?
A. XeF■
B. XeF■
C. XeF■
D. HeF■
✓ Correct Answer: D
Why this is correct: Helium does not form compounds under normal conditions because of its very high ionisation enthalpy
and complete n=1 shell. HeF■ is not known.
✗ Why the other options are wrong:
• A, B and C are well-characterised xenon fluorides.
Q8. The correct order of acidic strength is:
A. HF > HCl > HBr > HI
B. HI > HBr > HCl > HF
C. HCl > HF > HBr > HI
D. HBr > HI > HCl > HF
✓ Correct Answer: B
Why this is correct: Acidic strength of hydrogen halides increases down the group because bond strength decreases: HI is
the strongest acid and HF the weakest.
✗ Why the other options are wrong:
• A is the reverse order.
• C and D are incorrect sequences.
Q9. White phosphorus is stored under water because:
A. It is highly reactive towards air (catches fire)
B. It is soluble in water
C. It reacts with water
NEET 2027 | High-Weightage Chemistry | Part 3 Page 4
