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BIO 340 Final 2026/2027 Exam/ 491 Qs & Ans/ A+ Score
Solution/ .||Verified Exam||Sure Pass!!!
You are studying two linked genes that influence vine height
and fruit color in squash. Yellow color is dominant over green,
and tall height is dominant over short. You get the following
numbers of offspring from your test cross:
198 tall yellow, 192 short green, 54 tall green, and 56 short
yellow
which offspring are recombinants? - ANSWER-tall green and
short yellow
You are studying two linked genes that influence vine height
and fruit color in squash. Yellow color is dominant over green,
and tall height is dominant over short. You get the following
numbers of offspring from your test cross:
198 tall yellow, 192 short green, 54 tall green, and 56 short
yellow
What is the distance between these genes? - ANSWER-22 cM
54+56=110
198+192+54+56= 500
110/500=22
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You preform another test cross with these same squash plants.
What proportion of the offspring do you expect to have the
recombinant phenotype TALL GREEN? - ANSWER-11%
-22% of offspring will recombinants, half of those will be Tall
Green, therefore the answer is 11%
Three-Point Testcross - ANSWER-cross a trihybrid with an
individual that is homozygous recessive for all three genes
-this cross can tell not the order of the genes and the distance
between them
Interference - ANSWER-the presence of on crossover prevents
other crossovers from occurring nearby
Coefficient of Interference - ANSWER-1-observed frequency of
double crossover / expected frequency of double crossover
positive assortative mating - ANSWER-bias towards
phenotypically similar mates
negative assortative mating - ANSWER-bias towards
phenotypically different mates
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inbreeding - ANSWER-bias toward mating with relatives
outbreeding - ANSWER-bias against mating with relatives
Non- random mating - ANSWER-nonrandom mating affects
genotype frequencies not allele frequencies
By discouraging marriage between carries of the Tay-Sachs
Mutation, the disease has been virtually eliminated from
Ashkenazi jews in a generation. As a result the disease allele has
- ANSWER-stayed at roughly the same frequency
Identity by state (IBS) - ANSWER-two alleles are IBS if they re
functionally equivalent
-an individual is HOMOZYGOUS at a locus if its two alleles at the
locus are IBS
Identity by Descent (IBD) - ANSWER-two alleles are IBD if they
are both physical copies of the same ancestral allele in an
ancestral, reference population
-and individual is AUTOZYGOUS at a locus if its two copies at the
locus are IBD
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What is the inbreeding coefficient of D1? - ANSWER-0
What is the inbreeding coefficient of D2? - ANSWER-0.25
Inbreeding Coeffcients - ANSWER-Fs=0
Fd=0
FD1=0
FD2=0.25
FD3=0.375
Coefficient of kinship - ANSWER-of individuals I and J is the
probability that a randomly chosen pair of homologous genes
from I and J are IBD
Assuming NO population inbreeding, what is the coefficient f
kinship for a mother and a child? - ANSWER-25%
Parent-child Kinship - ANSWER-if there is no inbreeding in the
population, the child only shares one allele with his parents
Assuming NO population inbreeding, what its he coefficient of
kinship for full siblings - ANSWER-25%
BIO 340 Final 2026/2027 Exam/ 491 Qs & Ans/ A+ Score
Solution/ .||Verified Exam||Sure Pass!!!
You are studying two linked genes that influence vine height
and fruit color in squash. Yellow color is dominant over green,
and tall height is dominant over short. You get the following
numbers of offspring from your test cross:
198 tall yellow, 192 short green, 54 tall green, and 56 short
yellow
which offspring are recombinants? - ANSWER-tall green and
short yellow
You are studying two linked genes that influence vine height
and fruit color in squash. Yellow color is dominant over green,
and tall height is dominant over short. You get the following
numbers of offspring from your test cross:
198 tall yellow, 192 short green, 54 tall green, and 56 short
yellow
What is the distance between these genes? - ANSWER-22 cM
54+56=110
198+192+54+56= 500
110/500=22
,2|Page
You preform another test cross with these same squash plants.
What proportion of the offspring do you expect to have the
recombinant phenotype TALL GREEN? - ANSWER-11%
-22% of offspring will recombinants, half of those will be Tall
Green, therefore the answer is 11%
Three-Point Testcross - ANSWER-cross a trihybrid with an
individual that is homozygous recessive for all three genes
-this cross can tell not the order of the genes and the distance
between them
Interference - ANSWER-the presence of on crossover prevents
other crossovers from occurring nearby
Coefficient of Interference - ANSWER-1-observed frequency of
double crossover / expected frequency of double crossover
positive assortative mating - ANSWER-bias towards
phenotypically similar mates
negative assortative mating - ANSWER-bias towards
phenotypically different mates
,3|Page
inbreeding - ANSWER-bias toward mating with relatives
outbreeding - ANSWER-bias against mating with relatives
Non- random mating - ANSWER-nonrandom mating affects
genotype frequencies not allele frequencies
By discouraging marriage between carries of the Tay-Sachs
Mutation, the disease has been virtually eliminated from
Ashkenazi jews in a generation. As a result the disease allele has
- ANSWER-stayed at roughly the same frequency
Identity by state (IBS) - ANSWER-two alleles are IBS if they re
functionally equivalent
-an individual is HOMOZYGOUS at a locus if its two alleles at the
locus are IBS
Identity by Descent (IBD) - ANSWER-two alleles are IBD if they
are both physical copies of the same ancestral allele in an
ancestral, reference population
-and individual is AUTOZYGOUS at a locus if its two copies at the
locus are IBD
, 4|Page
What is the inbreeding coefficient of D1? - ANSWER-0
What is the inbreeding coefficient of D2? - ANSWER-0.25
Inbreeding Coeffcients - ANSWER-Fs=0
Fd=0
FD1=0
FD2=0.25
FD3=0.375
Coefficient of kinship - ANSWER-of individuals I and J is the
probability that a randomly chosen pair of homologous genes
from I and J are IBD
Assuming NO population inbreeding, what is the coefficient f
kinship for a mother and a child? - ANSWER-25%
Parent-child Kinship - ANSWER-if there is no inbreeding in the
population, the child only shares one allele with his parents
Assuming NO population inbreeding, what its he coefficient of
kinship for full siblings - ANSWER-25%
