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Minnesota Class A Electrical Contractor Exam Practice Questions And Correct Answers (Verified Answers) Plus Rationales 2026 Q&A | Instant Download Pdf

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Minnesota Class A Electrical Contractor Exam Practice Questions And Correct Answers (Verified Answers) Plus Rationales 2026 Q&A | Instant Download Pdf

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Minnesota Class A Electrical Contractor
Exam Practice Questions And Correct
Answers (Verified Answers) Plus
Rationales 2026 Q&A | Instant
Download Pdf


1. A 240V single-phase load draws 30 amps. What is the power in watts?
A. 3,600 W
B. 7,200 W
C. 9,600 W
D. 12,000 W
The correct calculation is P = V × I, so 240 × 30 = 7,200 watts.
2. What is the primary purpose of equipment grounding conductors?
A. Carry normal load current
B. Provide a low-impedance fault current path
C. Increase system voltage stability
D. Reduce power consumption

, Equipment grounding conductors ensure fault current returns safely
to the source to facilitate overcurrent device operation.
3. According to NEC, the minimum depth for 120V residential branch
circuits in rigid metal conduit under a driveway is:
A. 6 inches
B. 18 inches
C. 24 inches
D. 36 inches
NEC burial depth requirements specify 18 inches for rigid metal
conduit under driveways in typical installations.
4. A transformer has 480V primary and 120V secondary. What is the
turns ratio?
A. 1:2
B. 4:1
C. 2:1
D. 1:4
Turns ratio equals voltage ratio; 480:120 simplifies to 4:1.
5. What device protects against overloads and short circuits?
A. Disconnect switch
B. Circuit breaker
C. Transformer
D. Capacitor

, Circuit breakers automatically open the circuit under overload or
fault conditions.
6. The resistance of a conductor increases when:
A. Temperature decreases
B. Temperature increases
C. Voltage decreases
D. Current decreases
Higher temperatures increase conductor resistance due to atomic
vibration.
7. What is the function of a neutral conductor?
A. Carry fault current only
B. Carry unbalanced load current
C. Ground the system
D. Increase voltage
Neutral conductors carry return current under normal unbalanced
conditions.
8. A 10 kW load at 240V requires how many amps?
A. 25 A
B. 41.7 A
C. 50 A
D. 60 A
I = P/V = 10,000/240 ≈ 41.7 amps.

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