CHEM 104 EXAM 12 ACTUAL TEST PAPER QUESTIONS CORRECT ANSWERS GRADED A
PLUS
CHEM 104 Exam12 Questions and Answers Verified
Solutions Latest Update 2026/2027
Question:
HBr (hydrobromic)
Answer:
Strong acid HI (Hydriodic) -✓✓strong acid HNO3 (nitric) -✓✓strong acid HClO4 (perchloric)
-✓✓strong acid H2SO4 (sulfuric) -✓✓strong acid HOCl (hypochlorous) -✓✓weak acid HF
(hydrofluoric) -✓✓weak acid HCN (hydrocyanic) -✓✓weak acid HNO2 (nitrous) -✓✓weak acid
HC2H3O2 (acetic) -✓✓weak acid HC7H5O2 (benzoic) -✓✓weak acid NaOH (sodium hydroxide)
-✓✓strong base KOH (potassium hydroxide) -✓✓strong base NH3 (ammonia) -✓✓weak base
CH3NH2 (methylamine) -✓✓weak base weaker acids produce. -✓✓stronger conjugate bases
stronger acids produce. -✓✓weaker conjugate bases weaker bases produce. -✓✓stronger conjugate
acids Keq > 1 -✓✓strong, product-favored Keq < 1 -✓✓weak, reactant-favored reversal of reaction
-✓✓1/K multiplying stoichiometry -✓✓K to the power of multiplier adding reactions -✓✓K x K
Change in n -✓✓sum (coefficients of the gaseous products) - sum (coefficients of the gaseous
reactants) Converting concentration to pressure -✓✓Kp=Kc(RT)^change in n Keq
-✓✓[products]^stoich./[reactants]^stoich. Le Chatelieu's Principle -✓✓equilibrium systems always
respond to disturbances by working in the opposite direction, establishing a new eq. adding product
shifts new eq. -✓✓left removing product shifts new eq. -✓✓right adding reactant shifts new eq.
-✓✓right removing reactant shifts new eq. -✓✓left if Q>Keq -✓✓shift left if Q<Keq -✓✓shift right
Q is dependent on. -✓✓concentration and pressure Keq is dependent on. -✓✓temperature adding
heat to an exothermic reaction. -✓✓shift left adding heat to an endothermic reaction. -✓✓shift right
removing heat from an exothermic reaction -✓✓shift right removing heat from an endothermic
reaction -✓✓shift left exothermic reaction -✓✓heat is a product endothermic reaction -✓✓heat is a
reactant if pressure is increased by decreasing volume. -✓✓shift left if pressure is decreased by
increasing volume. -✓✓shift right if stoichiometry is equal. -✓✓no shift from pressure or volume
changes quadratic formula -✓✓x = -b ± √(b² - 4ac)/2a x is small conditions -✓✓small Keq value
(<0.01), large concentration or pressure values (>0.01) 5% test -✓✓(x/neighbor term)x100 < 5%
Keq is large -✓✓move reactants to products, reverse reaction acid -✓✓H+ donor base -✓✓H+
acceptor acids form. -✓✓conjugate base bases form. -✓✓conjugate acid Ka -✓✓acid dissociation
constant [A-]eq[H3O+]eq/[HA]eq acidic solutions -✓✓[H30+]eq > [OH-]eq basic solutions
-✓✓[H30+]eq < [OH-]eq P-value -✓✓alt form of expressing concentration (-log) pH -✓✓-log[H+]
= -log[H3O+] ion product of water -✓✓Kw = [H3O+][OH-] = 1x10^-14 pKw -✓✓pH + pOH =
14.000 % ionization -✓✓[H3O+]/[HA] x 100 Kb -✓✓base association constant
[HA]eq[OH-]eq/[A-]eq
PLUS
CHEM 104 Exam12 Questions and Answers Verified
Solutions Latest Update 2026/2027
Question:
HBr (hydrobromic)
Answer:
Strong acid HI (Hydriodic) -✓✓strong acid HNO3 (nitric) -✓✓strong acid HClO4 (perchloric)
-✓✓strong acid H2SO4 (sulfuric) -✓✓strong acid HOCl (hypochlorous) -✓✓weak acid HF
(hydrofluoric) -✓✓weak acid HCN (hydrocyanic) -✓✓weak acid HNO2 (nitrous) -✓✓weak acid
HC2H3O2 (acetic) -✓✓weak acid HC7H5O2 (benzoic) -✓✓weak acid NaOH (sodium hydroxide)
-✓✓strong base KOH (potassium hydroxide) -✓✓strong base NH3 (ammonia) -✓✓weak base
CH3NH2 (methylamine) -✓✓weak base weaker acids produce. -✓✓stronger conjugate bases
stronger acids produce. -✓✓weaker conjugate bases weaker bases produce. -✓✓stronger conjugate
acids Keq > 1 -✓✓strong, product-favored Keq < 1 -✓✓weak, reactant-favored reversal of reaction
-✓✓1/K multiplying stoichiometry -✓✓K to the power of multiplier adding reactions -✓✓K x K
Change in n -✓✓sum (coefficients of the gaseous products) - sum (coefficients of the gaseous
reactants) Converting concentration to pressure -✓✓Kp=Kc(RT)^change in n Keq
-✓✓[products]^stoich./[reactants]^stoich. Le Chatelieu's Principle -✓✓equilibrium systems always
respond to disturbances by working in the opposite direction, establishing a new eq. adding product
shifts new eq. -✓✓left removing product shifts new eq. -✓✓right adding reactant shifts new eq.
-✓✓right removing reactant shifts new eq. -✓✓left if Q>Keq -✓✓shift left if Q<Keq -✓✓shift right
Q is dependent on. -✓✓concentration and pressure Keq is dependent on. -✓✓temperature adding
heat to an exothermic reaction. -✓✓shift left adding heat to an endothermic reaction. -✓✓shift right
removing heat from an exothermic reaction -✓✓shift right removing heat from an endothermic
reaction -✓✓shift left exothermic reaction -✓✓heat is a product endothermic reaction -✓✓heat is a
reactant if pressure is increased by decreasing volume. -✓✓shift left if pressure is decreased by
increasing volume. -✓✓shift right if stoichiometry is equal. -✓✓no shift from pressure or volume
changes quadratic formula -✓✓x = -b ± √(b² - 4ac)/2a x is small conditions -✓✓small Keq value
(<0.01), large concentration or pressure values (>0.01) 5% test -✓✓(x/neighbor term)x100 < 5%
Keq is large -✓✓move reactants to products, reverse reaction acid -✓✓H+ donor base -✓✓H+
acceptor acids form. -✓✓conjugate base bases form. -✓✓conjugate acid Ka -✓✓acid dissociation
constant [A-]eq[H3O+]eq/[HA]eq acidic solutions -✓✓[H30+]eq > [OH-]eq basic solutions
-✓✓[H30+]eq < [OH-]eq P-value -✓✓alt form of expressing concentration (-log) pH -✓✓-log[H+]
= -log[H3O+] ion product of water -✓✓Kw = [H3O+][OH-] = 1x10^-14 pKw -✓✓pH + pOH =
14.000 % ionization -✓✓[H3O+]/[HA] x 100 Kb -✓✓base association constant
[HA]eq[OH-]eq/[A-]eq
