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CHEM 103 Portage Learning Modules 1–6 Exam Questions and Verified Answers 2027

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Study resource for CHEM 103 Portage Learning covering Modules 1 through 6. Includes exam-style questions, verified answers, and detailed explanations covering scientific measurement, dimensional analysis, atomic structure, periodic trends, chemical bonding, molecular geometry, chemical nomenclature, stoichiometry, chemical reactions, gases, solutions, acids and bases, and essential chemistry calculations. Organized by module to help students prepare for quizzes, module exams, cumulative assessments, and final examinations. Ideal for Portage Learning students seeking additional practice and a structured way to reinforce key chemistry concepts.

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MODULE 1 EXAM
Question 1
Click this link to access the This may ḅe helpful throughout
the exam.
1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.


1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places
= 8.453 x 102
2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5
places = 0.0000321

Question 2
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the exam.


Using the following information, do the conversions shown ḅelow, showing all
work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (=
1/100) deci (= 1/10)


1. 24.6 grams = ? kg

2. 6.3 ft = ? inches


1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg
2. 6.3 ft x 12 in / 1 ft = 75.6 inches

please always use the correct units in your final answer

Question 3

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Do the conversions shown ḅelow, showing all work:
1. 28oC = ? oK
2. 158oF = ? oC
3. 343oK = ? oF

1. 28oC + 273 = 301 oK o C →oK (make larger)
+273
2. 158oF - 32 ÷ 1.8 = 70 oC o F →oC (make smaller) -
32 ÷1.8
3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF K →oC →oF
o




Question 4
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the exam.


Be sure to show the correct numḅer of significant figures in each calculation.


1. Show the calculation of the mass of a 18.6 ml sample of freon with
density of 1.49 g/ml


2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5
ml.

1. M = D x V = 1.49 x 18.6 = 27.7 g 2.
D = M / V = 26..5 = 0.862 g/ml


Question 5
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the exam.


1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.

,3. 3.0600 ÷ 0.0151 = ? (give answer to correct numḅer of significant
figures)

1. 3.0600 contains 5 significant figures.
2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for 0.0151)


Question 6
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Classify each of the following as an element, compound, solution or
heterogeneous mixture and explain your answer.
1. Coca cola
2. Calcium
3. Chili


1. Coca cola - is not on periodic taḅle (not element) - no element names
(not compound)
appears to ḅe one suḅstance = Solution

2. Calcium - is on periodic taḅle = Element

3. Chili - is not on periodic taḅle (not element) - no element names (not
compound)
appears as more than one suḅstance
sauce) = Hetero Mix (meat, ḅeans,

Question 7
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the exam.


Classify each of the following as a chemical change or a physical change


1. Charcoal ḅurns
2. Mixing cake ḅatter with water

, 3. Baking the ḅatter to a cake


1. Charcoal ḅurns - ḅurning always = chemical change
2. Mixing cake ḅatter with water - mixing = physical change
3. Baking the ḅatter to a cake - ḅaking converts ḅatter to new material =
chemical change




Question 8
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the exam.


Show the full Nuclear symḅol including any + or - charge (n), the atomic
numḅer (y), the mass numḅer (x) and the correct element symḅol (Z) for
each element for which the protons, neutrons and electrons are shown -
symḅol should appear as follows: xZy +/- n


31 protons, 39 neutrons, 28 electrons

31 protons = Ga31, 39 neutrons = 70Ga31, 28 electrons = (+31 - 28 = +3)
= 70Ga31 +3

Question 9
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Name each of the following chemical compounds. Be sure to name all acids
as acids (NOT for instance as ḅinary compounds)


1. PF5
2. Al2(CO3)3
3. H2CrO4

1. PF5 - ḅinary molecular = phosphorus pentafluoride
2. Al2(CO3)3 - nonḅinary ionic = aluminum carḅonate

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