Solutions Manual
to accompany
Communication
Systems
N us
U
An Introduction to Signals and Noise in
Electrical Communication
Tr
R ted
Fourth Edition
SE s
A. Bruce Carlson
Rensselaer Polytechnic Institute
D ch
Paul B. Crilly
University of Tennessee
O o
Janet C. Rutledge
University of Maryland at Baltimore
C la
S r
Trustedscholar
,N us
U
Tr
R ted
SE s
D ch
O o
Solutions Manual to accompany
COMMUNICATION SYSTEMS: AN INTRODUCTION TO SIGNALS AND NOISE IN ELECTRICAL COMMUNICATION,
C la
FOURTH EDITION
A. BRUCE CARLSON, PAUL B. CRILLY, AND JANET C. RUTLEDGE
Published by McGraw-Hill Higher Education, an imprint of The McGraw-Hill Companies, Inc., 1221 Avenue of the Americas,
New York, NY 10020. Copyright © The McGraw-Hill Companies, Inc., 2002, 1986, 1975, 1968. All rights reserved.
S
The contents, or parts thereof, may be reproduced in print form solely for classroom use with COMMUNICATION SYSTEMS: AN
INTRODUCTION TO SIGNALS AND NOISE IN ELECTRICAL COMMUNICATION, provided such reproductions bear copyright
notice, but may not be reproduced in any other form or for any other purpose without the prior written consent of The McGraw-Hill
Companies, Inc., including, but not limited to, in any network or other electronic storage or transmission, or broadcast for distance
learning.
www.mhhe.com
r
Trustedscholar
, Chapter 2
2.1-1
Ae jφ Ae jφ n = m
∫− T
T
j 2 π ( m−n )f 0t jφ
cn = e dt = Ae sinc( m − n ) =
T0 0 otherwise
2.1-2
N us
c0 v (t ) = 0
2 T 2π nt T 2π nt 2A πn
cn = ∫ dt + ∫ ( − A)cos dt =
U
A cos sin
T0 0 T0 T T0 πn 2
Tr
n 0 1 2 3 4 5 6 7
R ted
cn 0 2A/π 0 2 A / 3π 0 2 A / 5π 0 2 A / 7π
arg cn 0 ±180° 0 ±180°
SE s
2.1-3
D ch
c0 = v (t ) = A / 2
2 T0 /2 2 At 2π nt A A
∫
O o
cn = A− cos dt = sin π n − (cos π n − 1)
T0 0
T0 T0 πn (π n) 2
n 0 1 2 3 4 5 6
C la
cn 0.5A 0.2A 0 0.02A 0 0.01A 0
arg cn 0 0 0 0
S
2.1-4
2 T 2π t
c0 =
T0 ∫
0
A cos
T0
=0 (cont.)
2-1
r
Trustedscholar
, 2 A sin (π − π n ) 2t / T0 sin (π + π n ) 2t / T0
T
2 T 2π t 2π nt
cn =
T0 ∫0
A cos
T0
cos
T0
dt =
T0 4(π − π n) / T0
+
4(π + π n ) / T0 0
A/2 n = ±1
[ sinc(1 − n) + sinc(1 + n )] =
A
=
2 0 otherwise
2.1-5
N us
c0 = v (t ) = 0
2π nt
U
2 T A
cn = − j
T0 ∫0
A sin
T0
dt = − j
πn
(1 − cos π n )
Tr
R ted
n 1 2 3 4 5
cn 2A/π 0 2 A / 3π 2 A / 5π
arg cn −90° −90° −90°
SE s
2.1-6
D ch
c0 = v(t ) = 0
2 A sin (π − π n ) 2t / T0 sin ( π + π n ) 2t / T0
T
2π t 2π nt
O o
2 T
cn = − j
T0 ∫0
A sin
T0
sin
T0
dt = − j
T0 4(π − π n ) / T0
−
4(π + π n )/ T0 0
m jA / 2 n = ±1
[sinc(1 − n ) − sinc(1 + n ) ] =
A
= −j
C la
2 0 otherwise
2.1-7
S
1 T
v ( t) e− jnω0 t dt + ∫ v(t )e − jnω 0t dt ]
T0
cn = ∫
T0 0 T
T0 T
where ∫T
v(t )e − jnω0 t dt = ∫
0
v (λ + T0 /2) e− jnω 0λ e− jnω 0T d λ
T
= −e jnπ ∫ v (t )e − jnω0 t dt
0
since e jnπ = 1 for even n, cn = 0 for even n
2-2
r
Trustedscholar
to accompany
Communication
Systems
N us
U
An Introduction to Signals and Noise in
Electrical Communication
Tr
R ted
Fourth Edition
SE s
A. Bruce Carlson
Rensselaer Polytechnic Institute
D ch
Paul B. Crilly
University of Tennessee
O o
Janet C. Rutledge
University of Maryland at Baltimore
C la
S r
Trustedscholar
,N us
U
Tr
R ted
SE s
D ch
O o
Solutions Manual to accompany
COMMUNICATION SYSTEMS: AN INTRODUCTION TO SIGNALS AND NOISE IN ELECTRICAL COMMUNICATION,
C la
FOURTH EDITION
A. BRUCE CARLSON, PAUL B. CRILLY, AND JANET C. RUTLEDGE
Published by McGraw-Hill Higher Education, an imprint of The McGraw-Hill Companies, Inc., 1221 Avenue of the Americas,
New York, NY 10020. Copyright © The McGraw-Hill Companies, Inc., 2002, 1986, 1975, 1968. All rights reserved.
S
The contents, or parts thereof, may be reproduced in print form solely for classroom use with COMMUNICATION SYSTEMS: AN
INTRODUCTION TO SIGNALS AND NOISE IN ELECTRICAL COMMUNICATION, provided such reproductions bear copyright
notice, but may not be reproduced in any other form or for any other purpose without the prior written consent of The McGraw-Hill
Companies, Inc., including, but not limited to, in any network or other electronic storage or transmission, or broadcast for distance
learning.
www.mhhe.com
r
Trustedscholar
, Chapter 2
2.1-1
Ae jφ Ae jφ n = m
∫− T
T
j 2 π ( m−n )f 0t jφ
cn = e dt = Ae sinc( m − n ) =
T0 0 otherwise
2.1-2
N us
c0 v (t ) = 0
2 T 2π nt T 2π nt 2A πn
cn = ∫ dt + ∫ ( − A)cos dt =
U
A cos sin
T0 0 T0 T T0 πn 2
Tr
n 0 1 2 3 4 5 6 7
R ted
cn 0 2A/π 0 2 A / 3π 0 2 A / 5π 0 2 A / 7π
arg cn 0 ±180° 0 ±180°
SE s
2.1-3
D ch
c0 = v (t ) = A / 2
2 T0 /2 2 At 2π nt A A
∫
O o
cn = A− cos dt = sin π n − (cos π n − 1)
T0 0
T0 T0 πn (π n) 2
n 0 1 2 3 4 5 6
C la
cn 0.5A 0.2A 0 0.02A 0 0.01A 0
arg cn 0 0 0 0
S
2.1-4
2 T 2π t
c0 =
T0 ∫
0
A cos
T0
=0 (cont.)
2-1
r
Trustedscholar
, 2 A sin (π − π n ) 2t / T0 sin (π + π n ) 2t / T0
T
2 T 2π t 2π nt
cn =
T0 ∫0
A cos
T0
cos
T0
dt =
T0 4(π − π n) / T0
+
4(π + π n ) / T0 0
A/2 n = ±1
[ sinc(1 − n) + sinc(1 + n )] =
A
=
2 0 otherwise
2.1-5
N us
c0 = v (t ) = 0
2π nt
U
2 T A
cn = − j
T0 ∫0
A sin
T0
dt = − j
πn
(1 − cos π n )
Tr
R ted
n 1 2 3 4 5
cn 2A/π 0 2 A / 3π 2 A / 5π
arg cn −90° −90° −90°
SE s
2.1-6
D ch
c0 = v(t ) = 0
2 A sin (π − π n ) 2t / T0 sin ( π + π n ) 2t / T0
T
2π t 2π nt
O o
2 T
cn = − j
T0 ∫0
A sin
T0
sin
T0
dt = − j
T0 4(π − π n ) / T0
−
4(π + π n )/ T0 0
m jA / 2 n = ±1
[sinc(1 − n ) − sinc(1 + n ) ] =
A
= −j
C la
2 0 otherwise
2.1-7
S
1 T
v ( t) e− jnω0 t dt + ∫ v(t )e − jnω 0t dt ]
T0
cn = ∫
T0 0 T
T0 T
where ∫T
v(t )e − jnω0 t dt = ∫
0
v (λ + T0 /2) e− jnω 0λ e− jnω 0T d λ
T
= −e jnπ ∫ v (t )e − jnω0 t dt
0
since e jnπ = 1 for even n, cn = 0 for even n
2-2
r
Trustedscholar
