NEIEP 600 Final Exam – National Elevator
Industry Educational Program (NEIEP)
Assessment – 2026/2027 Edition – Verified
Questions and Answers
Section 1: Electronic Components & Theory
1. What does a diode allow?
A) Two-way current flow
B) One-way current flow
C) Voltage amplification
D) Current multiplication
Answer: B) One-way current flow
Rationale: A diode is a semiconductor device that permits current flow in only one
direction (forward bias) while blocking it in the opposite direction (reverse bias). This
property makes it essential for rectification in power supplies.
2. Which of the following statements is correct about a forward biased silicon
diode?
A) The anode is 0.3 volts higher than the cathode
B) The anode is 0.7 volts higher than the cathode
C) The cathode is 0.7 volts higher than the anode
D) The voltage drop is 1.4 volts
, Answer: B) The anode is 0.7 volts higher than the cathode
Rationale: A silicon diode requires approximately 0.7 volts forward voltage to conduct. The
anode must be more positive than the cathode by this amount for current to flow.
3. The voltage required to cause conduction across the junction in a germanium
diode is:
A) 0.3V
B) 0.7V
C) 1.0V
D) 1.5V
Answer: A) 0.3V
Rationale: Germanium diodes have a lower forward voltage drop than silicon diodes,
typically around 0.3V. This is due to the different energy band gap characteristics of
germanium compared to silicon.
4. What does a bridge rectifier use?
A) Two diodes
B) Four diodes
C) Six diodes
D) Eight diodes
Answer: B) Four diodes
Rationale: A bridge rectifier uses four diodes arranged in a bridge configuration to convert
both halves of the AC waveform into pulsating DC. This provides full-wave rectification
without requiring a center-tapped transformer.
5. How many rectifier diodes are required to make a full wave bridge rectifier?
A) 2
B) 3
C) 4
, D) 6
Answer: C) 4
Rationale: Full-wave bridge rectification requires four diodes. Two diodes conduct during
the positive half-cycle and two conduct during the negative half-cycle, producing a
pulsating DC output.
6. What is the peak value of an AC voltage whose RMS value is 120 volts?
A) 120 VAC
B) 84.8 VAC
C) 169.7 VAC
D) 240 VAC
Answer: C) 169.7 VAC
Rationale: The peak value is calculated by multiplying the RMS value by the square root of
2 (1.414). Vpeak = VRMS × 1.414 = 120 × 1.414 = 169.7 volts.
7. What is the binary equivalent of 17₁₀?
A) 10001
B) 10010
C) 10011
D) 10100
Answer: A) 10001
Rationale: Binary 10001 equals 16 + 1 = 17 in decimal. This is calculated by converting
decimal to base-2 representation.
8. What numbering system uses one of two digits to represent each positional
value?
A) Decimal
B) Octal
Industry Educational Program (NEIEP)
Assessment – 2026/2027 Edition – Verified
Questions and Answers
Section 1: Electronic Components & Theory
1. What does a diode allow?
A) Two-way current flow
B) One-way current flow
C) Voltage amplification
D) Current multiplication
Answer: B) One-way current flow
Rationale: A diode is a semiconductor device that permits current flow in only one
direction (forward bias) while blocking it in the opposite direction (reverse bias). This
property makes it essential for rectification in power supplies.
2. Which of the following statements is correct about a forward biased silicon
diode?
A) The anode is 0.3 volts higher than the cathode
B) The anode is 0.7 volts higher than the cathode
C) The cathode is 0.7 volts higher than the anode
D) The voltage drop is 1.4 volts
, Answer: B) The anode is 0.7 volts higher than the cathode
Rationale: A silicon diode requires approximately 0.7 volts forward voltage to conduct. The
anode must be more positive than the cathode by this amount for current to flow.
3. The voltage required to cause conduction across the junction in a germanium
diode is:
A) 0.3V
B) 0.7V
C) 1.0V
D) 1.5V
Answer: A) 0.3V
Rationale: Germanium diodes have a lower forward voltage drop than silicon diodes,
typically around 0.3V. This is due to the different energy band gap characteristics of
germanium compared to silicon.
4. What does a bridge rectifier use?
A) Two diodes
B) Four diodes
C) Six diodes
D) Eight diodes
Answer: B) Four diodes
Rationale: A bridge rectifier uses four diodes arranged in a bridge configuration to convert
both halves of the AC waveform into pulsating DC. This provides full-wave rectification
without requiring a center-tapped transformer.
5. How many rectifier diodes are required to make a full wave bridge rectifier?
A) 2
B) 3
C) 4
, D) 6
Answer: C) 4
Rationale: Full-wave bridge rectification requires four diodes. Two diodes conduct during
the positive half-cycle and two conduct during the negative half-cycle, producing a
pulsating DC output.
6. What is the peak value of an AC voltage whose RMS value is 120 volts?
A) 120 VAC
B) 84.8 VAC
C) 169.7 VAC
D) 240 VAC
Answer: C) 169.7 VAC
Rationale: The peak value is calculated by multiplying the RMS value by the square root of
2 (1.414). Vpeak = VRMS × 1.414 = 120 × 1.414 = 169.7 volts.
7. What is the binary equivalent of 17₁₀?
A) 10001
B) 10010
C) 10011
D) 10100
Answer: A) 10001
Rationale: Binary 10001 equals 16 + 1 = 17 in decimal. This is calculated by converting
decimal to base-2 representation.
8. What numbering system uses one of two digits to represent each positional
value?
A) Decimal
B) Octal
