with Lab Exam 3 Practice Test Actual 2026/2027 with
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SECTION 1: MICROBIAL GENETICS & GENE REGULATION (12 Questions)
Q1: During DNA replication in bacteria, which enzyme is responsible for synthesizing
short RNA primers that provide a 3'-OH group for DNA polymerase to begin
synthesis?
A. DNA ligase
B. DNA helicase
C. Primase [CORRECT]
D. DNA polymerase III
Correct Answer: C
Rationale: Primase is an RNA polymerase that synthesizes short RNA primers
(approximately 10 nucleotides long) on the lagging strand, providing the essential
3'-OH group required for DNA polymerase III to initiate DNA synthesis.
Q2: A researcher observes that when lactose is absent, the genes required for
lactose metabolism are not transcribed in E. coli. Which regulatory mechanism best
explains this observation?
A. Positive feedback activation of RNA polymerase
B. The lac repressor binding to the operator and blocking transcription [CORRECT]
C. Catabolite activator protein (CAP) inhibition of the promoter
D. Attenuation of the mRNA transcript before translation
Correct Answer: B
Rationale: In the absence of lactose, the lac repressor protein binds to the operator
region of the lac operon, physically blocking RNA polymerase from transcribing the
structural genes (lacZ, lacY, lacA), thereby preventing unnecessary lactose
metabolism enzyme production.
Q3: A bacterial culture is exposed to ultraviolet light. Several hours later, researchers
observe that some surviving bacteria have developed resistance to an antibiotic they
,were never exposed to. Which mechanism of genetic transfer most likely explains
this phenomenon?
A. Conjugation involving direct cell-to-cell contact
B. Transformation through uptake of naked DNA from lysed cells
C. Transduction via bacteriophage-mediated gene transfer [CORRECT]
D. Transposition of mobile genetic elements within the chromosome
Correct Answer: C
Rationale: Transduction occurs when bacteriophages accidentally package bacterial
DNA (including antibiotic resistance genes) during the lytic cycle and transfer this
DNA to new host bacteria upon subsequent infection, enabling horizontal gene
transfer without direct cell contact.
Q4: In the process of translation, which component of the ribosome is responsible
for catalyzing the formation of peptide bonds between amino acids?
A. The small ribosomal subunit (30S) that binds mRNA
B. The large ribosomal subunit (50S) containing peptidyl transferase activity
[CORRECT]
C. The A site that receives incoming aminoacyl-tRNA
D. The E site that releases empty tRNA molecules
Correct Answer: B
Rationale: The large ribosomal subunit (50S in prokaryotes, 60S in eukaryotes)
contains the peptidyl transferase center, which is a ribozyme (catalytic RNA) that
catalyzes peptide bond formation between the growing polypeptide chain and the
incoming amino acid.
Q5: A microbiology student is analyzing a point mutation in a bacterial gene. The
mutation changes a single nucleotide but does not alter the amino acid sequence of
the resulting protein. What type of mutation has occurred?
A. Nonsense mutation introducing a premature stop codon
B. Missense mutation changing one amino acid to another
C. Silent mutation due to degeneracy of the genetic code [CORRECT]
D. Frameshift mutation shifting the reading frame
Correct Answer: C
Rationale: A silent mutation occurs when a nucleotide substitution results in a
different codon that specifies the same amino acid due to the degenerate
(redundant) nature of the genetic code, where multiple codons can code for the
same amino acid.
, Q6: During conjugation, which structure is responsible for physically connecting two
bacterial cells and facilitating the unidirectional transfer of genetic material?
A. Flagellum providing motility for cell contact
B. Pili (specifically sex pili) forming a conjugation bridge [CORRECT]
C. Capsule enabling adherence between donor and recipient
D. Cell wall junctions allowing cytoplasmic fusion
Correct Answer: B
Rationale: Sex pili (F pili) are specialized appendages encoded by the F plasmid that
extend from the donor bacterium (F+ cell) and attach to the recipient bacterium (F-
cell), forming a conjugation tube through which single-stranded DNA is transferred
unidirectionally.
Q7: In the tryptophan (trp) operon, attenuation occurs when tryptophan levels are
high. Which molecular event is primarily responsible for causing transcription
termination at the attenuator region?
A. The trp repressor binding to the operator and blocking RNA polymerase
B. Ribosome stalling at tryptophan codons in the leader peptide
C. Formation of a rho-independent terminator hairpin in the mRNA leader region
[CORRECT]
D. Degradation of tryptophan mRNA by ribonucleases
Correct Answer: C
Rationale: When tryptophan is abundant, the ribosome quickly translates the leader
peptide and covers region 2 of the mRNA, allowing regions 3 and 4 to base-pair and
form a rho-independent terminator hairpin (attenuator), which causes RNA
polymerase to dissociate and terminate transcription prematurely.
Q8: A bacterial cell acquires a new plasmid carrying a gene for antibiotic resistance
through direct cell-to-cell contact. Which term best describes this process?
A. Transformation involving uptake of free DNA from the environment
B. Transduction mediated by viral vectors
C. Conjugation requiring physical contact between donor and recipient cells
[CORRECT]
D. Transposition involving movement of genetic elements within the genome
Correct Answer: C
Rationale: Conjugation is the process of genetic transfer that requires direct physical
contact between a donor bacterium (containing a conjugative plasmid like the F
factor) and a recipient bacterium, mediated by sex pili, enabling the transfer of
plasmid DNA.