Test Bank — Fundamentals of Electric Circuits, 7th Edition (Alexander & Sadiku, 2020) | Chapters 1–19 Covered

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, TABLE OF CONTENTS
Test Bank: Fundamentals of Electric Circuits 7th Edition
Authors: Charles Alexander, Matthew Sadiku
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Part One - DC Circuits
1) Basic Concepts
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2) Basic Laws
3) Methods of Analysis
Chapter 4: Circuit Theorems
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5) Operational Amplifiers
6) Capacitors and Inductors
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7) First-Order Circuits
8) Second-Order Circuits

Part Two - AC Circuits
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9) Sinusoids and Phasors
10) Sinusoidal Steady-State Analysis
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11) AC Power Analysis
12) Three-Phase Circuits
13) Magnetically Coupled Circuits
14) Frequency Response
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Part Three - Advanced Circuit Analysis
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15) Introduction to the Laplace Transform
16) Applications of the Laplace Transform
17) The Fourier Series
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18) Fourier Transform
19) Two-Port Networks

, Chapter 1
1. Award: 10.00 points
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How much charge is represented by the given amount of electrons?

a. For 6.482 × 1017 electrons, the charge q = -103.84 ± 3% mC
b. For 3.24 × 1018 electrons, the charge q = -519.05 ± 3% mC
c. For 3.46 × 1019 electrons, the charge q = -5.54 ± 3% C
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d. For 2.628 × 10 electrons, the charge q = -42.10 ± 3% C




Explanation:
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The coulomb representations of the given electrons are calculated as shown below:
a. q = 6.482 × 1017 × [–1.602 × 10–19 C] = - 103.84 mC
b. q = 3.24 × 1018 × [–1.602 × 10–19 C] = - 519.05 mC
c. q = 3.46 × 1019 × [–1.602 × 10–19 C] = - 5.54 C
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d. q = 2.628 × 1020 × [–1.602 × 10–19 C] = - 42.10 C

The coulomb representations of the given electrons are shown below.
a. q = 6.482 × 1017 = - 103.84 mC
b. q = 3.24 × 1018 = - 519.05 mC
c. q = 3.46 × 1019 = - 5.54 C
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d. q = 2.628 × 1020 = - 42.10 C


References

Numeric Response Difficulty: Medium Learning Objective: Understand the different units with
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which engineers work.
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Determine the current flowing through an element if the charge flow is given by the following equation.
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References

Section Break Difficulty: Easy Learning Objective: Understand the relationship
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between charge and current and how to use both in a
variety of applications.

, 2. Award: 10.00 points




q(t) = (8t + 8) mC

The current i flowing through the element for the given charge flow is 8 ± 2% mA.


Explanation:
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For the charge flow q(t) = (8t + 8) mC, the current flowing through the element can be calculated as
dq
i= = 8 mA
dt
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The current i flowing through the element for the given charge flow is 8 mA.


References
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Numeric Response Difficulty: Easy Learning Objective: Understand the relationship
between charge and current and how to use both in a
variety of applications.
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3. Award: 10.00 points
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q(t) = (16t2 + 9t – 2) C
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The current i flowing through the element is ( 32 ± 2% t + 9 ± 2% ) A.


Explanation:


For the charge flow q(t) = (16t2 + 9t – 2) C, the current flowing through the element can be calculated as
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dq
i= = (32t + 9) A
dt



The current i flowing through the element is (9t + 9) A.
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References
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Numeric Response Difficulty: Easy Learning Objective: Understand the relationship
between charge and current and how to use both in a
variety of applications.




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