OAT Optometry Admissions Test Physics Biology
ACTUAL EXAM Prep 2026/2027 | Complete
Exam-Style Q&A | Verified Q&A | Pass
Guaranteed - A+ Graded
Total Questions: 80
Physics: 35 questions (90 minutes)
Biology: 45 questions (90 minutes)
Format: Multiple choice (A–D), single best answer
PHYSICS SECTION
SECTION 1: MECHANICS & KINEMATICS (Q1–Q15)
Q1: A car accelerates uniformly from rest to 30 m/s in 6 seconds. What is the magnitude of its
acceleration?
A. 3 m/s²
B. 5 m/s²
C. 6 m/s²
D. 10 m/s²
Correct Answer: B
Rationale: Using the kinematic equation v = v₀ + at, where v₀ = 0, v = 30 m/s, and t = 6 s, acceleration a =
(30 − 0)/6 = 5 m/s².
Q2: A ball is thrown vertically upward with an initial velocity of 20 m/s. What is the maximum height
reached? (Assume g = 10 m/s²)
A. 10 m
B. 20 m
,C. 40 m
D. 80 m
Correct Answer: B
Rationale: At maximum height, final velocity v = 0. Using v² = v₀² + 2aΔy, with v₀ = 20 m/s and a = −10
m/s², maximum height Δy = (0 − 400)/(−20) = 20 m.
Q3: A 5 kg block slides down a frictionless incline angled at 30° to the horizontal. What is the
acceleration of the block?
A. 4.9 m/s²
B. 5.0 m/s²
C. 8.5 m/s²
D. 10.0 m/s²
Correct Answer: B
Rationale: The component of gravitational acceleration parallel to the incline is g sin(θ) = 10 × sin(30°) =
10 × 0.5 = 5.0 m/s².
Q4: A 10 kg object moving at 4 m/s collides with a stationary 6 kg object. After the collision, the two
objects stick together. What is their final velocity?
A. 1.5 m/s
B. 2.5 m/s
C. 3.5 m/s
D. 4.0 m/s
Correct Answer: B
Rationale: Using conservation of momentum: m₁v₁ + m₂v₂ = (m₁ + m₂)v_f. Thus (10 × 4) + (6 × 0) =
(16)v_f, so v_f = 40/16 = 2.5 m/s.
Q5: A force of 20 N acts on a 4 kg object for 3 seconds. What is the impulse delivered to the object?
A. 20 N·s
B. 40 N·s
C. 60 N·s
D. 80 N·s
Correct Answer: C
Rationale: Impulse equals force multiplied by time: J = F × Δt = 20 N × 3 s = 60 N·s.
, Q6: A satellite orbits Earth at a distance of 2R from Earth's center, where R is Earth's radius. What is the
gravitational acceleration at this orbit compared to the surface value g?
A. g/2
B. g/4
C. g/8
D. g/16
Correct Answer: B
Rationale: Gravitational acceleration follows the inverse-square law: g' = g(R/r)² = g(R/2R)² = g(1/2)² =
g/4.
Q7: A 50 kg crate is pushed across a horizontal floor at constant velocity. The coefficient of kinetic
friction is 0.3. What is the magnitude of the applied force?
A. 50 N
B. 100 N
C. 150 N
D. 200 N
Correct Answer: C
Rationale: At constant velocity, applied force equals friction force: F = μ_k × N = 0.3 × (50 kg × 10 m/s²) =
0.3 × 500 = 150 N.
Q8: A wheel of radius 0.4 m rotates with an angular velocity of 10 rad/s. What is the linear speed of a
point on the rim?
A. 2 m/s
B. 4 m/s
C. 8 m/s
D. 16 m/s
Correct Answer: B
Rationale: Linear speed v = rω = 0.4 m × 10 rad/s = 4 m/s.
Q9: A 2 kg object is lifted vertically at constant speed to a height of 5 m. How much work is done by the
lifting force?
ACTUAL EXAM Prep 2026/2027 | Complete
Exam-Style Q&A | Verified Q&A | Pass
Guaranteed - A+ Graded
Total Questions: 80
Physics: 35 questions (90 minutes)
Biology: 45 questions (90 minutes)
Format: Multiple choice (A–D), single best answer
PHYSICS SECTION
SECTION 1: MECHANICS & KINEMATICS (Q1–Q15)
Q1: A car accelerates uniformly from rest to 30 m/s in 6 seconds. What is the magnitude of its
acceleration?
A. 3 m/s²
B. 5 m/s²
C. 6 m/s²
D. 10 m/s²
Correct Answer: B
Rationale: Using the kinematic equation v = v₀ + at, where v₀ = 0, v = 30 m/s, and t = 6 s, acceleration a =
(30 − 0)/6 = 5 m/s².
Q2: A ball is thrown vertically upward with an initial velocity of 20 m/s. What is the maximum height
reached? (Assume g = 10 m/s²)
A. 10 m
B. 20 m
,C. 40 m
D. 80 m
Correct Answer: B
Rationale: At maximum height, final velocity v = 0. Using v² = v₀² + 2aΔy, with v₀ = 20 m/s and a = −10
m/s², maximum height Δy = (0 − 400)/(−20) = 20 m.
Q3: A 5 kg block slides down a frictionless incline angled at 30° to the horizontal. What is the
acceleration of the block?
A. 4.9 m/s²
B. 5.0 m/s²
C. 8.5 m/s²
D. 10.0 m/s²
Correct Answer: B
Rationale: The component of gravitational acceleration parallel to the incline is g sin(θ) = 10 × sin(30°) =
10 × 0.5 = 5.0 m/s².
Q4: A 10 kg object moving at 4 m/s collides with a stationary 6 kg object. After the collision, the two
objects stick together. What is their final velocity?
A. 1.5 m/s
B. 2.5 m/s
C. 3.5 m/s
D. 4.0 m/s
Correct Answer: B
Rationale: Using conservation of momentum: m₁v₁ + m₂v₂ = (m₁ + m₂)v_f. Thus (10 × 4) + (6 × 0) =
(16)v_f, so v_f = 40/16 = 2.5 m/s.
Q5: A force of 20 N acts on a 4 kg object for 3 seconds. What is the impulse delivered to the object?
A. 20 N·s
B. 40 N·s
C. 60 N·s
D. 80 N·s
Correct Answer: C
Rationale: Impulse equals force multiplied by time: J = F × Δt = 20 N × 3 s = 60 N·s.
, Q6: A satellite orbits Earth at a distance of 2R from Earth's center, where R is Earth's radius. What is the
gravitational acceleration at this orbit compared to the surface value g?
A. g/2
B. g/4
C. g/8
D. g/16
Correct Answer: B
Rationale: Gravitational acceleration follows the inverse-square law: g' = g(R/r)² = g(R/2R)² = g(1/2)² =
g/4.
Q7: A 50 kg crate is pushed across a horizontal floor at constant velocity. The coefficient of kinetic
friction is 0.3. What is the magnitude of the applied force?
A. 50 N
B. 100 N
C. 150 N
D. 200 N
Correct Answer: C
Rationale: At constant velocity, applied force equals friction force: F = μ_k × N = 0.3 × (50 kg × 10 m/s²) =
0.3 × 500 = 150 N.
Q8: A wheel of radius 0.4 m rotates with an angular velocity of 10 rad/s. What is the linear speed of a
point on the rim?
A. 2 m/s
B. 4 m/s
C. 8 m/s
D. 16 m/s
Correct Answer: B
Rationale: Linear speed v = rω = 0.4 m × 10 rad/s = 4 m/s.
Q9: A 2 kg object is lifted vertically at constant speed to a height of 5 m. How much work is done by the
lifting force?
