ADVANCED NUTRITION AND HUMAN
METABOLISM ALL CHAPTERS CERTIFICATION
ASSESSMENT 2026 VERIFIED ANSWERS
GRADED A+
◉ sucrose.
Answer: composed of glucose and fructose
connected by an alpha bond
◉ maltose.
Answer: 2 glucose connected by an alpha glycosidic bond
◉ lactose.
Answer: galactose and glucose connected by an beta bond
◉ polysaccharides.
Answer: more than 10 carbs unit put together
◉ starch.
Answer: plant
amylose + amylopectin
,◉ glycogen.
Answer: animal
liver and skeletal muscle
◉ cellulose.
Answer: we do not have the enzyme to break down cellulose
a dietary fiber and not an energy source
does not yield energy
major component of plant cell walls - provides structure for plants
- glycosidic bonds are B 1-4 = beta bonds
- resistant to mammalian a-amylase
- defined as dietary fiber
◉ amylose.
Answer: is a linear chain of glucose molecules bonded together by
a(1-4) glycosidic bonds
connected by alpha bonds - results in a linear chain
there are 2 initial points - two end glucose units
◉ Amylopectin.
, Answer: more than 2 ends (5 ends); rate of glucose release is greater
because we have more ends; more points for the enzyme to work;
has alpha 1-4 bonds = linear portions, connected to another linear
portion via the alpha 1-6 bonds, 1-6 are the branch points
◉ glycogen.
Answer: stores extra carbs, help maintain blood glucose; has many
end points and branch points which then means faster glucose
release
◉ why can we not break down cellulose.
Answer: because we lack the enzyme to break apart the beta 1-4
bond because this bond is resistance to the alpha amylase
◉ digestion.
Answer: polysaccharides
- salivary a-amylase mouth
- pancreatic a-amylase: small intestine
- resistant starches
- a-amylase inhibitors can be used to impede digestion of dietary
starch and combat the overweight and obesity problem
◉ resistant starch.
METABOLISM ALL CHAPTERS CERTIFICATION
ASSESSMENT 2026 VERIFIED ANSWERS
GRADED A+
◉ sucrose.
Answer: composed of glucose and fructose
connected by an alpha bond
◉ maltose.
Answer: 2 glucose connected by an alpha glycosidic bond
◉ lactose.
Answer: galactose and glucose connected by an beta bond
◉ polysaccharides.
Answer: more than 10 carbs unit put together
◉ starch.
Answer: plant
amylose + amylopectin
,◉ glycogen.
Answer: animal
liver and skeletal muscle
◉ cellulose.
Answer: we do not have the enzyme to break down cellulose
a dietary fiber and not an energy source
does not yield energy
major component of plant cell walls - provides structure for plants
- glycosidic bonds are B 1-4 = beta bonds
- resistant to mammalian a-amylase
- defined as dietary fiber
◉ amylose.
Answer: is a linear chain of glucose molecules bonded together by
a(1-4) glycosidic bonds
connected by alpha bonds - results in a linear chain
there are 2 initial points - two end glucose units
◉ Amylopectin.
, Answer: more than 2 ends (5 ends); rate of glucose release is greater
because we have more ends; more points for the enzyme to work;
has alpha 1-4 bonds = linear portions, connected to another linear
portion via the alpha 1-6 bonds, 1-6 are the branch points
◉ glycogen.
Answer: stores extra carbs, help maintain blood glucose; has many
end points and branch points which then means faster glucose
release
◉ why can we not break down cellulose.
Answer: because we lack the enzyme to break apart the beta 1-4
bond because this bond is resistance to the alpha amylase
◉ digestion.
Answer: polysaccharides
- salivary a-amylase mouth
- pancreatic a-amylase: small intestine
- resistant starches
- a-amylase inhibitors can be used to impede digestion of dietary
starch and combat the overweight and obesity problem
◉ resistant starch.
