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CHEM 103 Module 4 Exam: Chemical Reactions and Stoichiometry Exam 2026/2027 UPDATE

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CHEM 103 Module 4 Exam: Chemical Reactions and Stoichiometry Exam 2026/2027 UPDATE

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CHEM 103 Module 4 Exam: Chemical Reactions and Stoichiometry
Exam 2026/2027 UPDATE


1. What is the value of Avogadro’s number?

A. 6.022 x 10^22

B. 6.022 x 10^23

C. 3.011 x 10^23

D. 1.000 x 10^24

Answer: B
Rationale: Avogadro’s number is defined as the number of atoms in exactly 12 grams of
Carbon-12, which is 6.022 x 10^23.

2. Which of the following describes a synthesis reaction?

A. Two or more substances combine to form a single product.

B. An element reacts with a compound to produce a new element.

C. A single reactant breaks down into multiple products.

D. Two compounds exchange ions to form new compounds.

Answer: A
Rationale: A synthesis reaction (or combination) occurs when two or more reactants
combine to form one single product (A + B -> AB).

,3. Calculate the molar mass of Calcium Carbonate (CaCO3).

A. 68.09 g/mol

B. 84.00 g/mol

C. 100.09 g/mol

D. 120.12 g/mol

Answer: C
Rationale: Ca (40.08) + C (12.01) + 3*O (16.00) = 100.09 g/mol.

4. In the balanced equation 2H2 + O2 -> 2H2O, what is the mole ratio of H2 to
H2O?

A. 1:2

B. 2:1

C. 1:1

D. 2:3

Answer: C
Rationale: The coefficients for H2 and H2O are both 2, so the ratio is 2:2, which simplifies
to 1:1.

5. What is the mass of 0.500 moles of NaCl?

A. 116.88 g

B. 58.44 g

C. 14.61 g

D. 29.22 g

Answer: D
Rationale: Molar mass of NaCl is 58.44 g/mol. 0.500 moles * 58.44 g/mol = 29.22 g.

, 6. Which type of reaction is 2KClO3 -> 2KCl + 3O2?

A. Decomposition

B. Synthesis

C. Single Replacement

D. Double Replacement

Answer: A
Rationale: A decomposition reaction occurs when a single reactant breaks down into two
or more products.

7. Identify the coefficient of Oxygen when the equation C3H8 + O2 -> CO2 + H2O
is balanced.

A. 3

B. 4

C. 5

D. 10

Answer: C
Rationale: The balanced equation is C3H8 + 5O2 -> 3CO2 + 4H2O.

8. What is the empirical formula for a compound that is 80% Carbon and 20%
Hydrogen by mass?

A. CH

B. CH3

C. CH2

D. C2H5

Answer: B
Rationale: 80g C / 12 = 6.67 mol; 20g H / 1 = 20 mol. .67 = 3. Thus, CH3.

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