Escrito por estudiantes que aprobaron Inmediatamente disponible después del pago Leer en línea o como PDF ¿Documento equivocado? Cámbialo gratis 4,6 TrustPilot
logo-home
Document preview thumbnail
Vista previa 4 fuera de 43 páginas
Examen

HESI RADIOLOGY EXIT EXAM PREP VERSION 3 2026/2027 ELSEVIER EVOLVE – COMPREHENSIVE RADIOLOGIC SCIENCES COMPETENCY ASSESSMENT

Document preview thumbnail
Vista previa 4 fuera de 43 páginas

HESI RADIOLOGY EXIT EXAM PREP VERSION 3 2026/2027 ELSEVIER EVOLVE – COMPREHENSIVE RADIOLOGIC SCIENCES COMPETENCY ASSESSMENT

Vista previa del contenido

HESI RADIOLOGY EXIT EXAM PREP VERSION 3 2026/2027
ELSEVIER EVOLVE – COMPREHENSIVE RADIOLOGIC SCIENCES
COMPETENCY ASSESSMENT

SECTION 1: RADIATION PHYSICS (QUESTIONS 1-10)


Question 1
What is the primary source of radiation used in diagnostic radiography?


A) Alpha particles
B) Beta particles
C) X-rays produced by an X-ray tube
D) Gamma rays from radioactive isotopes



Answer: C) X-rays produced by an X-ray tube


Rationale: Diagnostic radiography uses X-rays produced by an X-ray tube. X-rays are a
form of electromagnetic radiation produced when high-speed electrons collide with a
metal target (tungsten) in the X-ray tube. Alpha particles (A) and beta particles (B) are
particulate radiation used in nuclear medicine but not in general radiography. Gamma
rays (D) are used in nuclear medicine (gamma cameras) but not in general radiography.
X-rays have high energy and short wavelength, allowing them to penetrate tissue.


Question 2
Which component of the X-ray tube is the source of electrons?


A) Anode
B) Cathode
C) Stator
D) Glass envelope

,Answer: B) Cathode


Rationale: The cathode is the negative electrode in the X-ray tube and contains the
filament (usually tungsten) that emits electrons when heated (thermionic emission). The
anode (A) is the positive electrode that receives the electrons and produces X-rays (the
target). The stator (C) is part of the induction motor that rotates the anode. The glass
envelope (D) encloses the tube and maintains a vacuum. The cathode current controls
the number of electrons (tube current, mA), which determines the quantity of X-rays
produced.


Question 3
The quantity of X-rays produced is primarily controlled by:


A) Kilovoltage peak (kVp)
B) Milliamperage (mA) and exposure time (seconds)
C) Focal spot size
D) Added filtration



Answer: B) Milliamperage (mA) and exposure time (seconds)


Rationale: The quantity of X-rays (number of X-ray photons) is directly proportional to
the milliamperage (mA) and exposure time (seconds). The product of mA and time is mAs
(milliampere-seconds). mAs controls the total number of electrons striking the anode,
which determines the number of X-ray photons produced. Kilovoltage peak (kVp) (A)
controls the quality (energy/penetrating power) of X-rays, not the quantity. Focal spot
size (C) affects spatial resolution but not quantity. Added filtration (D) removes low-
energy X-rays (beam hardening) but does not increase quantity.


Question 4
The quality (energy/penetrating power) of X-rays is primarily controlled by:


A) Milliamperage (mA)
B) Exposure time (seconds)
C) Kilovoltage peak (kVp)

,D) Focal spot size



Answer: C) Kilovoltage peak (kVp)


Rationale: Kilovoltage peak (kVp) controls the maximum energy of X-ray photons (peak
energy in kiloelectron volts, keV). Higher kVp produces X-rays with higher energy (more
penetrating power), which affects the quality of the image (contrast). Lower kVp
produces lower energy X-rays (less penetrating), which increases subject contrast. kVp
also affects the quantity of X-rays proportionally to the square of kVp. mA (A) and
exposure time (B) control quantity, not quality. Focal spot size (D) affects spatial
resolution, not X-ray quality.


Question 5
The primary function of the grid in radiography is to:


A) Increase the X-ray beam intensity
B) Reduce scatter radiation reaching the image receptor
C) Increase patient dose
D) Decrease image contrast



Answer: B) Reduce scatter radiation reaching the image receptor


Rationale: The grid is placed between the patient and the image receptor. Its primary
function is to absorb scatter radiation (Compton scatter) produced within the patient,
which reduces image fog and improves image contrast. Scatter radiation degrades image
quality by adding unwanted exposure to the image receptor without diagnostic
information. Grids are typically used for body parts thicker than 10-12 cm and for higher
kVp techniques. Option A: grids do not increase beam intensity; they reduce it (grid
factor). Option C: grids increase patient dose because the technique must be increased
to compensate for grid absorption. Option D: grids improve contrast, not decrease it.


Question 6
Which of the following is a characteristic of X-rays?

, A) They are visible light
B) They are a form of ionizing radiation
C) They are produced by radioactive decay
D) They have a long wavelength



Answer: B) They are a form of ionizing radiation


Rationale: X-rays are a form of ionizing radiation, meaning they have enough energy to
remove electrons from atoms (ionization), which can cause biological damage (DNA
damage). X-rays are invisible (A) and cannot be seen by the human eye. They are
produced by an X-ray tube (C), not by radioactive decay (gamma rays are produced by
radioactive decay). X-rays have short wavelengths (D) (0.01-10 nanometers), shorter than
visible light. The ionizing nature of X-rays requires radiation protection measures (time,
distance, shielding).


Question 7
The inverse square law states that the intensity of radiation is:


A) Directly proportional to the square of the distance from the source
B) Inversely proportional to the square of the distance from the source
C) Directly proportional to the distance from the source
D) Inversely proportional to the distance from the source


Answer: B) Inversely proportional to the square of the distance from the source


Rationale: The inverse square law states that the intensity of radiation (I) is inversely
proportional to the square of the distance (d) from the source: I1/I2 = (d2)2/(d1)2. As
distance doubles, the intensity decreases to one-quarter (1/4). As distance triples,
intensity decreases to one-ninth (1/9). This principle is used in radiation protection to
reduce exposure (increasing distance from the source). It applies to point sources of
radiation (X-ray tube, radioactive source). For example, if the distance from the X-ray
tube is doubled, the exposure to the patient or technologist decreases by a factor of 4.


Question 8

Información del documento

Subido en
3 de junio de 2026
Número de páginas
43
Escrito en
2025/2026
Tipo
Examen
Contiene
Preguntas y respuestas
$18.98

¿Documento equivocado? Cámbialo gratis Dentro de los 14 días posteriores a la compra y antes de descargarlo, puedes elegir otro documento. Puedes gastar el importe de nuevo.
Escrito por estudiantes que aprobaron
Inmediatamente disponible después del pago
Leer en línea o como PDF

Seller avatar
Los indicadores de reputación están sujetos a la cantidad de artículos vendidos por una tarifa y las reseñas que ha recibido por esos documentos. Hay tres niveles: Bronce, Plata y Oro. Cuanto mayor reputación, más podrás confiar en la calidad del trabajo del vendedor.
DoctorDee
3.5
(6)
Vendido
34
Seguidores
7
Artículos
5282
Última venta
1 día hace


Por qué los estudiantes eligen Stuvia

Creado por compañeros estudiantes, verificado por reseñas

Calidad en la que puedes confiar: escrito por estudiantes que aprobaron y evaluado por otros que han usado estos resúmenes.

¿No estás satisfecho? Elige otro documento

¡No te preocupes! Puedes elegir directamente otro documento que se ajuste mejor a lo que buscas.

Paga como quieras, empieza a estudiar al instante

Sin suscripción, sin compromisos. Paga como estés acostumbrado con tarjeta de crédito y descarga tu documento PDF inmediatamente.

Student with book image

“Comprado, descargado y aprobado. Así de fácil puede ser.”

Alisha Student

Preguntas frecuentes