Minnesota Journeyman Sprinkler Fitter
ACTUAL EXAM 2026/2027 | Verified Q&A |
Pass Guaranteed - A+ Graded
Section A: Plans & Drawings – Hydraulic Calculations, Pipe Sizing, Hangers & Supports, System Layout
(Q1–Q20)
Q1. A light hazard office building requires a wet pipe sprinkler system. Using NFPA 13 density/area
method, what is the minimum design area of operation for a hydraulically calculated system assuming a
density of 0.10 gpm/sq ft?
A. 1,200 sq ft
B. 1,500 sq ft [CORRECT]
C. 1,800 sq ft
D. 2,000 sq ft
Correct Answer: B
Rationale: NFPA 13 requires a minimum design area of 1,500 sq ft for light hazard when using the
density/area method for hydraulically calculated systems, regardless of density selected.
Q2. What is the maximum horizontal distance between hangers for a 2-inch schedule 40 steel pipe in a
sprinkler system?
A. 10 ft
B. 12 ft
C. 15 ft [CORRECT]
D. 20 ft
Correct Answer: C
Rationale: NFPA 13 Table 17.4.2.1 specifies hanger spacing for steel pipe. For 2-inch pipe, maximum
spacing is 15 feet.
,Q3. A sprinkler system requires a flow of 500 gpm at a residual pressure of 65 psi at the base of the
riser. The available water supply provides 500 gpm at 75 psi. What is the available pressure margin?
A. 5 psi
B. 10 psi [CORRECT]
C. 15 psi
D. 20 psi
Correct Answer: B
Rationale: The available pressure margin is the difference between available supply pressure (75 psi)
and required system pressure (65 psi): 75 − 65 = 10 psi. This margin accounts for elevation losses,
friction losses, and safety factors.
Q4. A 4-inch schedule 10 steel pipe carries water at 250 gpm. Using the Hazen-Williams formula with C =
120, what is the approximate friction loss per 100 feet?
A. 0.5 psi
B. 1.2 psi [CORRECT]
C. 2.5 psi
D. 4.0 psi
Correct Answer: B
Rationale: Using the Hazen-Williams formula for 4-inch schedule 10 pipe at 250 gpm with C = 120, the
friction loss is approximately 1.2 psi per 100 feet. This value is essential for hydraulic calculations to
ensure adequate pressure at remote sprinklers.
Q5. What is the maximum allowable spacing between hangers for a 6-inch schedule 40 steel pipe?
A. 15 ft
B. 18 ft
C. 20 ft [CORRECT]
D. 25 ft
Correct Answer: C
Rationale: NFPA 13 Table 17.4.2.1 specifies that 6-inch and larger steel pipe may have hangers spaced at
a maximum of 20 feet. Proper hanger spacing prevents pipe sagging, joint stress, and ensures system
integrity during water flow.
,Q6. A hydraulic calculation shows that the most remote sprinkler requires 25 gpm at 30 psi. The K-factor
of the sprinkler is 5.6. What is the minimum required pressure at the sprinkler?
A. 20 psi
B. 25 psi
C. 30 psi [CORRECT]
D. 35 psi
Correct Answer: C
Rationale: The K-factor formula (Q = K√P) calculates flow based on pressure. For Q = 25 gpm and K = 5.6:
P = (Q/K)² = (25/5.6)² = 19.9 psi. However, NFPA 13 requires a minimum operating pressure of 7 psi for
standard spray sprinklers, and the hydraulic calculation must verify that 30 psi is available to overcome
elevation and friction losses to the remote sprinkler.
Q7. A branch line in a light hazard system is 100 feet long with four sprinklers spaced 12 feet apart.
What is the total developed length for hydraulic calculation purposes?
A. 100 ft
B. 112 ft
C. 124 ft [CORRECT]
D. 136 ft
Correct Answer: C
Rationale: NFPA 13 requires adding the equivalent length of fittings to the actual pipe length. For four
sprinklers, there are three tees (each approximately 8 ft equivalent for 1-inch pipe), adding 24 ft to the
100 ft actual length, totaling 124 ft developed length.
Q8. A system requires 750 gpm total flow. The water supply curve shows 750 gpm available at 60 psi.
The system demand at 750 gpm is 55 psi. Is the water supply adequate?
A. No, the supply is insufficient
B. Yes, with a 5 psi margin [CORRECT]
C. Yes, but only with a fire pump
D. Cannot be determined without elevation data
Correct Answer: B
Rationale: The water supply is adequate when available pressure exceeds required pressure at the
design flow. Here, 60 psi available minus 55 psi required equals a 5 psi margin, which is sufficient per
NFPA 13 requirements for light and ordinary hazard occupancies.
, Q9. What is the maximum protection area per sprinkler for a standard upright sprinkler in an ordinary
hazard group 1 occupancy?
A. 100 sq ft
B. 130 sq ft [CORRECT]
C. 168 sq ft
D. 225 sq ft
Correct Answer: B
Rationale: NFPA 13 Table 19.2.3.1.1 limits the protection area per sprinkler to 130 sq ft for standard
spray upright and pendent sprinklers in ordinary hazard group 1 occupancies. This ensures adequate
density coverage for moderate fire challenges.
Q10. A 3-inch grooved pipe is installed in a system. What is the maximum hanger spacing for this pipe?
A. 12 ft
B. 15 ft [CORRECT]
C. 18 ft
D. 20 ft
Correct Answer: B
Rationale: NFPA 13 specifies that 3-inch pipe, whether threaded, grooved, or welded, has a maximum
hanger spacing of 15 feet. Grooved couplings provide flexibility but do not increase allowable hanger
spacing beyond standard limits.
Q11. A hydraulic calculation for a high-piled storage system shows a required density of 0.30 gpm/sq ft
over 2,000 sq ft. What is the total required flow?
A. 500 gpm
B. 600 gpm [CORRECT]
C. 700 gpm
D. 800 gpm
Correct Answer: B
Rationale: Total required flow equals density multiplied by design area: 0.30 gpm/sq ft × 2,000 sq ft =
600 gpm. This flow must be available at the required residual pressure at the base of the system riser.
ACTUAL EXAM 2026/2027 | Verified Q&A |
Pass Guaranteed - A+ Graded
Section A: Plans & Drawings – Hydraulic Calculations, Pipe Sizing, Hangers & Supports, System Layout
(Q1–Q20)
Q1. A light hazard office building requires a wet pipe sprinkler system. Using NFPA 13 density/area
method, what is the minimum design area of operation for a hydraulically calculated system assuming a
density of 0.10 gpm/sq ft?
A. 1,200 sq ft
B. 1,500 sq ft [CORRECT]
C. 1,800 sq ft
D. 2,000 sq ft
Correct Answer: B
Rationale: NFPA 13 requires a minimum design area of 1,500 sq ft for light hazard when using the
density/area method for hydraulically calculated systems, regardless of density selected.
Q2. What is the maximum horizontal distance between hangers for a 2-inch schedule 40 steel pipe in a
sprinkler system?
A. 10 ft
B. 12 ft
C. 15 ft [CORRECT]
D. 20 ft
Correct Answer: C
Rationale: NFPA 13 Table 17.4.2.1 specifies hanger spacing for steel pipe. For 2-inch pipe, maximum
spacing is 15 feet.
,Q3. A sprinkler system requires a flow of 500 gpm at a residual pressure of 65 psi at the base of the
riser. The available water supply provides 500 gpm at 75 psi. What is the available pressure margin?
A. 5 psi
B. 10 psi [CORRECT]
C. 15 psi
D. 20 psi
Correct Answer: B
Rationale: The available pressure margin is the difference between available supply pressure (75 psi)
and required system pressure (65 psi): 75 − 65 = 10 psi. This margin accounts for elevation losses,
friction losses, and safety factors.
Q4. A 4-inch schedule 10 steel pipe carries water at 250 gpm. Using the Hazen-Williams formula with C =
120, what is the approximate friction loss per 100 feet?
A. 0.5 psi
B. 1.2 psi [CORRECT]
C. 2.5 psi
D. 4.0 psi
Correct Answer: B
Rationale: Using the Hazen-Williams formula for 4-inch schedule 10 pipe at 250 gpm with C = 120, the
friction loss is approximately 1.2 psi per 100 feet. This value is essential for hydraulic calculations to
ensure adequate pressure at remote sprinklers.
Q5. What is the maximum allowable spacing between hangers for a 6-inch schedule 40 steel pipe?
A. 15 ft
B. 18 ft
C. 20 ft [CORRECT]
D. 25 ft
Correct Answer: C
Rationale: NFPA 13 Table 17.4.2.1 specifies that 6-inch and larger steel pipe may have hangers spaced at
a maximum of 20 feet. Proper hanger spacing prevents pipe sagging, joint stress, and ensures system
integrity during water flow.
,Q6. A hydraulic calculation shows that the most remote sprinkler requires 25 gpm at 30 psi. The K-factor
of the sprinkler is 5.6. What is the minimum required pressure at the sprinkler?
A. 20 psi
B. 25 psi
C. 30 psi [CORRECT]
D. 35 psi
Correct Answer: C
Rationale: The K-factor formula (Q = K√P) calculates flow based on pressure. For Q = 25 gpm and K = 5.6:
P = (Q/K)² = (25/5.6)² = 19.9 psi. However, NFPA 13 requires a minimum operating pressure of 7 psi for
standard spray sprinklers, and the hydraulic calculation must verify that 30 psi is available to overcome
elevation and friction losses to the remote sprinkler.
Q7. A branch line in a light hazard system is 100 feet long with four sprinklers spaced 12 feet apart.
What is the total developed length for hydraulic calculation purposes?
A. 100 ft
B. 112 ft
C. 124 ft [CORRECT]
D. 136 ft
Correct Answer: C
Rationale: NFPA 13 requires adding the equivalent length of fittings to the actual pipe length. For four
sprinklers, there are three tees (each approximately 8 ft equivalent for 1-inch pipe), adding 24 ft to the
100 ft actual length, totaling 124 ft developed length.
Q8. A system requires 750 gpm total flow. The water supply curve shows 750 gpm available at 60 psi.
The system demand at 750 gpm is 55 psi. Is the water supply adequate?
A. No, the supply is insufficient
B. Yes, with a 5 psi margin [CORRECT]
C. Yes, but only with a fire pump
D. Cannot be determined without elevation data
Correct Answer: B
Rationale: The water supply is adequate when available pressure exceeds required pressure at the
design flow. Here, 60 psi available minus 55 psi required equals a 5 psi margin, which is sufficient per
NFPA 13 requirements for light and ordinary hazard occupancies.
, Q9. What is the maximum protection area per sprinkler for a standard upright sprinkler in an ordinary
hazard group 1 occupancy?
A. 100 sq ft
B. 130 sq ft [CORRECT]
C. 168 sq ft
D. 225 sq ft
Correct Answer: B
Rationale: NFPA 13 Table 19.2.3.1.1 limits the protection area per sprinkler to 130 sq ft for standard
spray upright and pendent sprinklers in ordinary hazard group 1 occupancies. This ensures adequate
density coverage for moderate fire challenges.
Q10. A 3-inch grooved pipe is installed in a system. What is the maximum hanger spacing for this pipe?
A. 12 ft
B. 15 ft [CORRECT]
C. 18 ft
D. 20 ft
Correct Answer: B
Rationale: NFPA 13 specifies that 3-inch pipe, whether threaded, grooved, or welded, has a maximum
hanger spacing of 15 feet. Grooved couplings provide flexibility but do not increase allowable hanger
spacing beyond standard limits.
Q11. A hydraulic calculation for a high-piled storage system shows a required density of 0.30 gpm/sq ft
over 2,000 sq ft. What is the total required flow?
A. 500 gpm
B. 600 gpm [CORRECT]
C. 700 gpm
D. 800 gpm
Correct Answer: B
Rationale: Total required flow equals density multiplied by design area: 0.30 gpm/sq ft × 2,000 sq ft =
600 gpm. This flow must be available at the required residual pressure at the base of the system riser.
