0793226427
MAT1503 Assignment 2 solutions 2026
UNISA
, 0793226427
MAT1503 Assignment 02 — Full Solutions
Question 1
Given: 𝐴3 − 3𝐴2 + 3𝐴 − 𝐼 = 0, where 𝐴is an 𝑛 × 𝑛matrix.
Part (a): Prove that A is invertible
To prove 𝐴is invertible, we need to show det(𝐴) ≠ 0, i.e., find 𝐴−1explicitly, i.e.,
express 𝐼as a product of 𝐴and some matrix.
Rearrange the given equation:
𝐴3 − 3𝐴2 + 3𝐴 − 𝐼 = 0
𝐴3 − 3𝐴2 + 3𝐴 = 𝐼
Factor out 𝐴on the left side:
𝐴(𝐴2 − 3𝐴 + 3𝐼) = 𝐼
This shows that:
𝐴 ⋅ (𝐴2 − 3𝐴 + 3𝐼) = 𝐼
By the definition of invertibility, a matrix 𝐴is invertible if and only if there exists a
matrix 𝐵such that 𝐴𝐵 = 𝐼.
Here, 𝐵 = 𝐴2 − 3𝐴 + 3𝐼satisfies 𝐴𝐵 = 𝐼.
Therefore, 𝐴is invertible. ■
Part (b): Expression for 𝑨−𝟏
From Part (a):
𝐴(𝐴2 − 3𝐴 + 3𝐼) = 𝐼
MAT1503 Assignment 2 solutions 2026
UNISA
, 0793226427
MAT1503 Assignment 02 — Full Solutions
Question 1
Given: 𝐴3 − 3𝐴2 + 3𝐴 − 𝐼 = 0, where 𝐴is an 𝑛 × 𝑛matrix.
Part (a): Prove that A is invertible
To prove 𝐴is invertible, we need to show det(𝐴) ≠ 0, i.e., find 𝐴−1explicitly, i.e.,
express 𝐼as a product of 𝐴and some matrix.
Rearrange the given equation:
𝐴3 − 3𝐴2 + 3𝐴 − 𝐼 = 0
𝐴3 − 3𝐴2 + 3𝐴 = 𝐼
Factor out 𝐴on the left side:
𝐴(𝐴2 − 3𝐴 + 3𝐼) = 𝐼
This shows that:
𝐴 ⋅ (𝐴2 − 3𝐴 + 3𝐼) = 𝐼
By the definition of invertibility, a matrix 𝐴is invertible if and only if there exists a
matrix 𝐵such that 𝐴𝐵 = 𝐼.
Here, 𝐵 = 𝐴2 − 3𝐴 + 3𝐼satisfies 𝐴𝐵 = 𝐼.
Therefore, 𝐴is invertible. ■
Part (b): Expression for 𝑨−𝟏
From Part (a):
𝐴(𝐴2 − 3𝐴 + 3𝐼) = 𝐼