PORTAGE LEARNING EXAM ms ms
Exam Solution ms
Portage Learning Chemistry CHEM 103 Unit 5 Cartes 2 ms ms ms ms ms ms ms ms
026 A+ GRADE ASSURED COMPLETE SOLUTIONS AND V
ms ms ms ms ms ms ms
ERIFIED ANSWERS (EDE7E) ms ms
QUESTION 1 ms
As33 (nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3 gain 3 → As-
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
3 Ge32 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 lose 4 → Ge+4
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
ANSWER
What will be the charge of the ion formed from each of these atoms? Explain your answer. As33, Ge
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
32
QUESTION 2 ms
1) Cl-O bond electronegativity difference = 3.5 - 3.0 = 0.5 (1.6 - 0.5 bond is Polar) H-
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
O bond electronegativity difference = 3.5 - 2.1 = 1.4 (1.6 -
ms ms ms ms ms ms ms ms ms ms ms
0.5 bond is Polar) 2) C≡N bond electronegativity difference = 3.0 - 2.5 = 0.5 (1.6 -
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
0.5 bond is Polar) H-C bond electronegativity difference = 2.5 -
ms ms ms ms ms ms ms ms ms ms ms
2.1 = 0.4 (< 0.5 bond is Nonpolar)
ms ms ms ms ms ms ms ms
ANSWER
Using the electronegativity values from the equation bank, show the determination of the polarity of
ms ms ms ms ms ms ms ms ms ms ms ms ms ms m
each different type of bond in the following molecules:
s ms ms ms ms ms ms ms ms
QUESTION 3 ms
Your Answer: NH3 N = 5, H = 3, 8 total H .. H : N : H .. SO2 S = 6, O = 12, total = 18 .. .
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
. .. : O : S :: O .. .. CH3OH C = 4, H = 4, O = 6, total = 14 H .. .. H : C : O : H .. .. H HNO2
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
H = 1, N = 5, O = 12, total = 18 .. .. .. H : O : N : : O : .. N2 N = 10 : N ::: N : CH2O C = 4,
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
H = 2, O = 6, total = 12 .. .. H : C :: O : H
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
ANSWER
Write Lewis dot structures for the following molecules: NH3 SO2 CH3OH HNO2 N2 CH2O
ms ms ms ms ms ms ms ms ms ms ms ms ms
Exam Solution ms
Portage Learning Chemistry CHEM 103 Unit 5 Cartes 2 ms ms ms ms ms ms ms ms
026 A+ GRADE ASSURED COMPLETE SOLUTIONS AND V
ms ms ms ms ms ms ms
ERIFIED ANSWERS (EDE7E) ms ms
QUESTION 1 ms
As33 (nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3 gain 3 → As-
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
3 Ge32 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 lose 4 → Ge+4
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
ANSWER
What will be the charge of the ion formed from each of these atoms? Explain your answer. As33, Ge
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
32
QUESTION 2 ms
1) Cl-O bond electronegativity difference = 3.5 - 3.0 = 0.5 (1.6 - 0.5 bond is Polar) H-
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
O bond electronegativity difference = 3.5 - 2.1 = 1.4 (1.6 -
ms ms ms ms ms ms ms ms ms ms ms
0.5 bond is Polar) 2) C≡N bond electronegativity difference = 3.0 - 2.5 = 0.5 (1.6 -
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
0.5 bond is Polar) H-C bond electronegativity difference = 2.5 -
ms ms ms ms ms ms ms ms ms ms ms
2.1 = 0.4 (< 0.5 bond is Nonpolar)
ms ms ms ms ms ms ms ms
ANSWER
Using the electronegativity values from the equation bank, show the determination of the polarity of
ms ms ms ms ms ms ms ms ms ms ms ms ms ms m
each different type of bond in the following molecules:
s ms ms ms ms ms ms ms ms
QUESTION 3 ms
Your Answer: NH3 N = 5, H = 3, 8 total H .. H : N : H .. SO2 S = 6, O = 12, total = 18 .. .
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
. .. : O : S :: O .. .. CH3OH C = 4, H = 4, O = 6, total = 14 H .. .. H : C : O : H .. .. H HNO2
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
H = 1, N = 5, O = 12, total = 18 .. .. .. H : O : N : : O : .. N2 N = 10 : N ::: N : CH2O C = 4,
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
H = 2, O = 6, total = 12 .. .. H : C :: O : H
ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms ms
ANSWER
Write Lewis dot structures for the following molecules: NH3 SO2 CH3OH HNO2 N2 CH2O
ms ms ms ms ms ms ms ms ms ms ms ms ms
