PHYS 2002 EXAM 2 QUESTIONS WITH VERIFIED SOLUTIONS LATEST UPDATE 2026
a 1.2 kg rod that has a length of 1.0 m and a resistance of 5.0 omega slides with a constant speed.... a
uniform magnetic field of magnitude 3.0 T is perpendicular... determine the speed of the rod -
Answers (B^2 L^2 V)/R = mg
V= (mg*R)/(B^2 L^2)
a circular copper loop is placed perpendicular to a uniform magnetic field of 0.75T. Due to external
forces the area of the loop decreases at a rate of 7.26*10^-3 m^2/s. Determine the induced emf in
the loop - Answers E=-(B)(da/dt)
E=-(0.75)(7.26*10^-3)
A long, straight wire is in the same plane as a rectangular, conducting loop. The wire carries a
constant current I as shown in the figure. Which one of the following statements is true if the wire is
suddenly moved TOWARD the loop? - Answers There will be an induced current that is
counterclockwise around the loop.
A transformer changes 120 V across the primary to 1200 V across the secondary. If the secondary coil
has 800 turns, how many turns does the primary coil have? - Answers VP/VS=NP/NS(where v is
voltage and n is no of turns)
which of the following statements concerning the wavelength of an electromagnetic wave in a
vacuum is true - Answers the wavelength is inversely proportional to the frequency of the wave
An electromagnetic wave has an electrical field with a peak value of 250 N/C. What is the average
intensity of the wave? - Answers I=1/2cE_OE_max^2
emax = 250 N/C
c=3*10^8 m/s
e_o= 8.85*10^-12
I=1/2*(3*10^8)*(8.85*10^-12)*250^2
C - Answers 3*10^8 m/s
E_0 - Answers 8.85*10^-12
Unpolarized light of intensity S_0 passes through two sheets of polarizing material who's transmission
axes make an angle of 60 degrees with each other as shown in the figure. What is the intensity of the
transmitted beam, ST? - Answers I_2=I_1 cos^2 theta
=S_0/2 *(cos60)^2 =S_0/8
St=I_2
St = S_O/8
intensity of light after second polarizer - Answers I_2=I_1 cos^2 theta
intensity of light after first polarizer - Answers I=S_0/2
The radius of a coil of wire with N turns us r=0.28 m. A clockwise current of Icoil=1.0 A flows in the coil
as shown. A long straight wire carrying a current Iwire=29 A toward the left is located 0.04 m from the
edge of the coil. The magnetic field at the center of the coil is zero tesla. Determine the number of
turns. - Answers ((MoI_2)/2 pi (R+d)) - ((MoNI_1)/2R)
((I_2/Pi(R+d)) = NI_1/R
29/(pi*0.32)=N*1/R
N=8 turns
The radius of a coil of wire with N turns us r=0.28 m. A clockwise current of Icoil=1.0 A flows in the coil
as shown. A long straight wire carrying a current Iwire=29 A toward the left is located 0.04 m from the
edge of the coil. The magnetic field at the center of the coil is zero tesla. Determine the number of
turns. - Answers Bcoil=N(1.0/0.28*2)= (
a single circular loop of wire with radius 0.025 m carries a current of 6.0 A. It is placed at the center of
a solenoid that has a length of 0.60 m, radius 0.075m and 1200 turns. - Answers i= I/2Rxn
i= (6*0.6)/2*0.025*1200
i= 0.06A
A 0.00150 m wire oriented horizontally between the poles of an electromagnetic carries a direct
current of 9.5 A. the angle between the direction of the current and that of the magnetic field is 25
degrees. if the magnetic field strength is 0.845 T, that is the magnitude and direction of the magnetic
force on the wire between the poles? - Answers F = iL * B
F=iLB * sin (given angle/theta)
a 1.2 kg rod that has a length of 1.0 m and a resistance of 5.0 omega slides with a constant speed.... a
uniform magnetic field of magnitude 3.0 T is perpendicular... determine the speed of the rod -
Answers (B^2 L^2 V)/R = mg
V= (mg*R)/(B^2 L^2)
a circular copper loop is placed perpendicular to a uniform magnetic field of 0.75T. Due to external
forces the area of the loop decreases at a rate of 7.26*10^-3 m^2/s. Determine the induced emf in
the loop - Answers E=-(B)(da/dt)
E=-(0.75)(7.26*10^-3)
A long, straight wire is in the same plane as a rectangular, conducting loop. The wire carries a
constant current I as shown in the figure. Which one of the following statements is true if the wire is
suddenly moved TOWARD the loop? - Answers There will be an induced current that is
counterclockwise around the loop.
A transformer changes 120 V across the primary to 1200 V across the secondary. If the secondary coil
has 800 turns, how many turns does the primary coil have? - Answers VP/VS=NP/NS(where v is
voltage and n is no of turns)
which of the following statements concerning the wavelength of an electromagnetic wave in a
vacuum is true - Answers the wavelength is inversely proportional to the frequency of the wave
An electromagnetic wave has an electrical field with a peak value of 250 N/C. What is the average
intensity of the wave? - Answers I=1/2cE_OE_max^2
emax = 250 N/C
c=3*10^8 m/s
e_o= 8.85*10^-12
I=1/2*(3*10^8)*(8.85*10^-12)*250^2
C - Answers 3*10^8 m/s
E_0 - Answers 8.85*10^-12
Unpolarized light of intensity S_0 passes through two sheets of polarizing material who's transmission
axes make an angle of 60 degrees with each other as shown in the figure. What is the intensity of the
transmitted beam, ST? - Answers I_2=I_1 cos^2 theta
=S_0/2 *(cos60)^2 =S_0/8
St=I_2
St = S_O/8
intensity of light after second polarizer - Answers I_2=I_1 cos^2 theta
intensity of light after first polarizer - Answers I=S_0/2
The radius of a coil of wire with N turns us r=0.28 m. A clockwise current of Icoil=1.0 A flows in the coil
as shown. A long straight wire carrying a current Iwire=29 A toward the left is located 0.04 m from the
edge of the coil. The magnetic field at the center of the coil is zero tesla. Determine the number of
turns. - Answers ((MoI_2)/2 pi (R+d)) - ((MoNI_1)/2R)
((I_2/Pi(R+d)) = NI_1/R
29/(pi*0.32)=N*1/R
N=8 turns
The radius of a coil of wire with N turns us r=0.28 m. A clockwise current of Icoil=1.0 A flows in the coil
as shown. A long straight wire carrying a current Iwire=29 A toward the left is located 0.04 m from the
edge of the coil. The magnetic field at the center of the coil is zero tesla. Determine the number of
turns. - Answers Bcoil=N(1.0/0.28*2)= (
a single circular loop of wire with radius 0.025 m carries a current of 6.0 A. It is placed at the center of
a solenoid that has a length of 0.60 m, radius 0.075m and 1200 turns. - Answers i= I/2Rxn
i= (6*0.6)/2*0.025*1200
i= 0.06A
A 0.00150 m wire oriented horizontally between the poles of an electromagnetic carries a direct
current of 9.5 A. the angle between the direction of the current and that of the magnetic field is 25
degrees. if the magnetic field strength is 0.845 T, that is the magnitude and direction of the magnetic
force on the wire between the poles? - Answers F = iL * B
F=iLB * sin (given angle/theta)
