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BIOCHEMISTRY MODULE 3 EXAM 2026 – 300 REAL QUESTIONS WITH CORRECT DETAILED ANSWERS

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Ace your Biochemistry Module 3 exam with this complete 2026 test bank! Featuring 300 actual exam-style questions and step-by-step rationales covering bioenergetics, ATP, glycolysis, gluconeogenesis, TCA cycle, oxidative phosphorylation, PPP, glycogen metabolism, fatty acid oxidation, ketogenesis, and integrated clinical scenarios. Each answer is explained so you understand the “why” – not just memorize. Perfect for medical, pre-med, nursing, and health science students. Stop stressing and start passing. Get your A+ today!

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Biochemistry Module 3 Exam Newest

Questions and Answers (Verified Answers).




1. The standard free energy change (ΔG°') for ATP hydrolysis

is approximately:

a) +7.3 kcal/mol

b) –7.3 kcal/mol

c) –3.0 kcal/mol

d) 0 kcal/mol

Answer: b) –7.3 kcal/mol

Rationale: ATP → ADP + Pi releases 7.3 kcal/mol under

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standard conditions; actual cellular ΔG is more negative (~ –

12 to –14).

Q2. Which of the following reactions is most likely to be

coupled to ATP hydrolysis in the cell?

a) Glucose + fructose → sucrose (ΔG°' = +5.5 kcal/mol)

b) Creatine phosphate → creatine + Pi (ΔG°' = –10.3

kcal/mol)

c) CO2 + H2O → H2CO3 (ΔG°' = +2.0 kcal/mol)

d) Pyruvate → lactate (ΔG°' = –3.0 kcal/mol)

Answer: a) Glucose + fructose → sucrose

Rationale: Endergonic reactions (positive ΔG) require coupling

to exergonic ones like ATP hydrolysis.

Q3. A reaction has ΔG°' = –5.0 kcal/mol. At equilibrium, the

Keq will be:

a) <1

b) =1

c) >1

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d) Cannot be determined

Answer: c) >1

Rationale: ΔG°' = –RT ln Keq. Negative ΔG°' means ln Keq

positive → Keq > 1.

Q4. Scenario: A researcher measures ΔG for a reaction in a

cell and finds it to be –8.0 kcal/mol, but the ΔG°' for the same

reaction is +2.0 kcal/mol. What explains this?

a) The reaction is at equilibrium

b) The cellular concentrations of products are very low

c) The cellular concentrations of reactants are very low

d) Temperature is higher than 25°C

Answer: b) The cellular concentrations of products are very

low

Rationale: ΔG = ΔG°' + RT ln([products]/[reactants]). Low

product concentration makes the ratio small, driving ΔG

negative despite positive ΔG°'.

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Q5. Which of the following has the highest phosphoryl transfer

potential?

a) ATP

b) Glucose-6-phosphate

c) Phosphoenolpyruvate (PEP)

d) AMP

Answer: c) Phosphoenolpyruvate (PEP)

Rationale: PEP hydrolysis ΔG°' ≈ –14.8 kcal/mol, higher than

ATP's –7.3.

Q6. The term "high-energy bond" in ATP refers to:

a) The hydrogen bonds between adenine and ribose

b) The phosphoanhydride bonds between phosphates

c) The glycosidic bond between ribose and adenine

d) The ester bond between ribose and first phosphate

Answer: b) The phosphoanhydride bonds between phosphates

Rationale: These bonds have large negative ΔG of hydrolysis

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