ESE 5760 Memory questions and answers Graded A+

ESE 5760 Memory questions and answers Graded A+ Logical Effort input capacitance of the gate / Input capacitance of an inverter (for equal drive); Quantifies how hard a logic gate is to drive compared to an ideal inverter, assuming the same output drive strength; 2-input NAND: g≈4/3 or 2-input NOR: g≈5/3 Path Logical Effort The products of the logical efforts of each stage along the path; If the path has "hard" gates (like NANDs) instead of simple inverters, G gets bigger and the path is inherently slower. Path Electrical Effort How much load the path has to drive; H = input capacitance of the first gate / output load capacitance Path Effort Path Logical Effort * Path Electrical Effort; How "hard" the entire path is to drive Branching Effort The ratio of the total capacitance seen by a stage to the capacitance on the path γ Internal device parasitics (there is no off-path load) Propagation delay time Maximum time from the input crossing 50% t