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CSMLS REVIEW TRANSFUSION with correct answers 100%

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CSMLS REVIEW TRANSFUSION with correct answers 100% ABO Blood Group - Correct Answer Landsteiner - we have Ab against Ag we lack ABO Ab are naturally occurring, stimulated by nature - low # until 3-6 months Ag are codominant one locus Chr 9 has ⅓ A,B,O each person has 2 Chr 9 with one allele Genes at 3 loci control presence and location of the A,B,H Ag = ABO, Hh, Se A and B genes encode glycosyltransferases which transfers immunodominant sugar specificity of A and B Ag Group O = silent allele (no gene product) Hh and Se on CHr 19 closely links h and se = amorph (no detectable product = no glycosyl tranferase) H makes glycosyltransferase acting on 2 chains on H Ag on RBCs (H on RBC) Se = glycosyltransferase acts on 1 chains H Ag in secretions ( H in secretions) Bombay Phenotype - Correct Answer hh no H Ag bc no transferase will not react with Anti-A, Anti-B or Anti-H lectin their serum will have anti-A, anti-B, anti-A,B and Anti-H reacts strongly at 37˚C only can be transfused by other Bombay phenotypes O has most H substance then A then AB A Subgroups - Correct Answer A subgroups 80% A1 20% A2 differentiating A1 and A2 based on Anti-A1 lectin Dolichos biflorus A1 react with anti-A1 A2 cells do not Weak A subgroups (A2) A3 = mix field agglutination with Anti-A Ax = stronger reaction with anti-A,B then anti-A weaker ones only detected by elution and adsorption of anti-A Antibodies to A and B Ag - Correct Answer People A and B make IgM Ab (a little IgG) People who are O make IgG (anti-A,B) ABO sugars - Correct Answer H Ag L-fucose A Ag N-acetylgalactosamine B Ag D-galactose ABO testing - Correct Answer Forward reagent = monoclonal Anti-A and Anti-B give strong reactions (/= 3+) Reverse grouping A1 cells and B cells (Rh neg) (/= 2+)- weaker = serum problem other reagents Anti-A,B = subgroups classification or confirm group O units A2 cells (resolve discrepancies) Lectins Anti-A1 D. biflorus Anti-H Ulex europaeus 1/4 Discrepancy resolution (weak or missing Ag reactivity)- cell grouping tests - Correct Answer Subgroups of A and B = - A3 subgroup mixed field pattern with anti -A (from group O or B donors) - Ax subgroup No agglutination with anti-A from group B but agglutinate with anti-A,B from group O donors - Ael subgroup not agglutinated by anti-A or anti-A,B - Ag only shown with elution - B subgroups very rare leukemia and new borns may have weak expression of A / B Ag Chimera = transfusion Hx

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ABO Blood Group - Correct Answer Landsteiner

- we have Ab against Ag we lack



ABO Ab are naturally occurring, stimulated by nature

- low # until 3-6 months



Ag are codominant



each person has 2 Chr 9 with one allele



Genes at 3 loci control presence and location of the A,B,H Ag = ABO, Hh, Se



A and B genes encode glycosyltransferases which transfers immunodominant sugar specificity of A and B
Ag

Group O = silent allele (no gene product)



Hh and Se on CHr 19 closely links

h and se = amorph (no detectable product = no glycosyl tranferase)

H makes glycosyltransferase acting on 2 chains on H Ag on RBCs (H on RBC)

Se = glycosyltransferase acts on 1 chains H Ag in secretions ( H in secretions)



Bombay Phenotype - Correct Answer hh

no H Ag bc no transferase



will not react with Anti-A, Anti-B or Anti-H lectin



their serum will have anti-A, anti-B, anti-A,B and Anti-H

,only can be transfused by other Bombay phenotypes



O has most H substance then A then AB



A Subgroups - Correct Answer A subgroups

80% A1

20% A2



differentiating A1 and A2 based on Anti-A1 lectin Dolichos biflorus



A1 react with anti-A1

A2 cells do not



Weak A subgroups (<A2)

A3 = mix field agglutination with Anti-A

Ax = stronger reaction with anti-A,B then anti-A

weaker ones only detected by elution and adsorption of anti-A



Antibodies to A and B Ag - Correct Answer People A and B make IgM Ab (a little IgG)

People who are O make IgG (anti-A,B)



ABO sugars - Correct Answer H Ag L-fucose



A Ag N-acetylgalactosamine



B Ag D-galactose

,ABO testing - Correct Answer Forward

reagent = monoclonal Anti-A and Anti-B

give strong reactions (>/= 3+)



Reverse grouping

A1 cells and B cells (Rh neg)

(>/= 2+)-> weaker = serum problem



other reagents

Anti-A,B = subgroups classification or confirm group O units

A2 cells (resolve discrepancies)



Lectins

Anti-A1 D. biflorus

Anti-H Ulex europaeus



1/4 Discrepancy resolution (weak or missing Ag reactivity)-> cell grouping tests - Correct Answer
Subgroups of A and B =

- A3 subgroup mixed field pattern with

anti -A (from group O or B donors)

- Ax subgroup No agglutination with

anti-A from group B but agglutinate with anti-A,B from group O donors

- Ael subgroup not agglutinated by anti-A or anti-A,B -> Ag only shown with elution

- B subgroups very rare

leukemia and new borns may have weak expression of A / B Ag



Chimera = transfusion Hx



2/4 Discrepancy resolution (Extra Ag reactivity)

, cell grouping tests - Correct Answer Acquired B

- type as AB, but serum has anti-B

*assoc with GI tract disorder (transient)

Strength of reactivity weakened with decreased pH weakens reactivity (test at pH 6.0 acidified) ->
missing fwd group?

* test cells with monoclonal anti-B reagent (doesn't detect acquired B), autocontrol will also be negative



Pos DAT

- cells agglutinate spontaneously (Rh)

- can be ABO reagents if cold reactive Ab causing pos DAT

* wash cell

OR elute Ab from RBC with DTT



Contaminated cord blood sample

Wharton's Jelly causes

wash 3-4x with saline or get heel stick sample



Unwashed cell suspension

- patient Ab can cause reagent problems

- rouleaux



¾ Discrepancy Resolution (Weak or missing Ab reactivity) -> serum grouping tests - Correct Answer low
Ab levels (newborn or older)

Missing Ab (immunocompromised)

Chimera (tolerance to both cell pop')



Sub groups

A subgroups can type as O

Titre of anti-A higher than anti-B in group O = if weak reactivity with A1 you should investigate

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