CHEM219 MODULE 7 2026 ACTUAL EXAM
SCRIPT TESTED QUESTIONS WITH COMPLETE
SOLUTIONS GRADED A+
◉ Classify the bonding between the given pairs of atoms as ionic,
covalent, or polar covalent. Use the table of electronegativities
shown below to help with the classification.
a. Br and Br
b. K and Cl
c. P and Cl
d. C and O
e. Na and Br. Answer: a. Br-Br: Electronegativity difference () = 0 =
COVALENT (or pure covalent)
b. K-Cl: () = 2.2 = IONIC
c. P-Cl: ()= 0.9 = POLAR COVALENT
d. C-O: ()= 1.0 = POLAR COVALENT
e. Na-Br: () = 1.8 = POLAR COVALENT
◉ Define the term constitutional isomer.. Answer: Two (or more)
different chemical compounds with the same molecular formula but
, different connectivity between the atoms in their structural
formulae.
◉ Explain (using specific evidence) what makes the following two
compounds constitutional isomers of one another:. Answer: Both
compounds have a MF of C3H6O - same MF.
Compound "a" has a 3-carbon chain with a C=O in the middle. No H
atom connected to C of C=O.
Compound "b" has a 3-carbon chain with a C=O at the end. There is
an H attached to the C of the C=O.
◉ What is the relationship between the compounds shown? Are
they the same compound, constitutional isomers, or two different
compounds that are not related to one another? Explain.. Answer:
Different compounds that are not related. They have different MF -
(a) C3H8O, (b) C3H6O.
◉ Identify each of the following carbon skeletons as linear
(continuous), branched, or cyclic.. Answer: a) Branched
b) Linear (continuous)
c) Cyclic
◉ On a piece of scratch paper, write out structural formulae for all of
the constitutional isomers possible for the MF C3H6F2. How many
isomers are possible for this formula?. Answer: 4
SCRIPT TESTED QUESTIONS WITH COMPLETE
SOLUTIONS GRADED A+
◉ Classify the bonding between the given pairs of atoms as ionic,
covalent, or polar covalent. Use the table of electronegativities
shown below to help with the classification.
a. Br and Br
b. K and Cl
c. P and Cl
d. C and O
e. Na and Br. Answer: a. Br-Br: Electronegativity difference () = 0 =
COVALENT (or pure covalent)
b. K-Cl: () = 2.2 = IONIC
c. P-Cl: ()= 0.9 = POLAR COVALENT
d. C-O: ()= 1.0 = POLAR COVALENT
e. Na-Br: () = 1.8 = POLAR COVALENT
◉ Define the term constitutional isomer.. Answer: Two (or more)
different chemical compounds with the same molecular formula but
, different connectivity between the atoms in their structural
formulae.
◉ Explain (using specific evidence) what makes the following two
compounds constitutional isomers of one another:. Answer: Both
compounds have a MF of C3H6O - same MF.
Compound "a" has a 3-carbon chain with a C=O in the middle. No H
atom connected to C of C=O.
Compound "b" has a 3-carbon chain with a C=O at the end. There is
an H attached to the C of the C=O.
◉ What is the relationship between the compounds shown? Are
they the same compound, constitutional isomers, or two different
compounds that are not related to one another? Explain.. Answer:
Different compounds that are not related. They have different MF -
(a) C3H8O, (b) C3H6O.
◉ Identify each of the following carbon skeletons as linear
(continuous), branched, or cyclic.. Answer: a) Branched
b) Linear (continuous)
c) Cyclic
◉ On a piece of scratch paper, write out structural formulae for all of
the constitutional isomers possible for the MF C3H6F2. How many
isomers are possible for this formula?. Answer: 4
