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Case Unit 19 - Practical Chemical Analysis (PCA)

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assignment 6 for unit 19

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M6 Michael Deehan


0.82M concentration of ethanoic acid in vinegar


Therefore 1000cm3 of vinegar contains 0.82M
Therefore 1000cm3 of vinegar contains 0.82 moles x RMM
=0.82x 60
= 49.2g


1000cm3 of vinegar contains 49.2g
Therefore the percentage weight to volume is 4.92%
The percentage format is used because it is more likely that the customer will understand
percentages as opposed to moles.

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