Questions & Expertly Verified
Quiz_________________?
[H+] = -
Answer✅
10^-pH
Quiz_________________?
0.0005 kilomorgans to centimorgans -
Answer✅
50 centimorgans
Quiz_________________?
1 joule equals -
Answer✅
1 Nm (newton * meter)
Quiz_________________?
1
, 1 Newton equals -
Answer✅
1 kg m/s^2
Quiz_________________?
1 pascal is equal to -
Answer✅
1 N/m^2
Quiz_________________?
2 ways to form ATP -
Answer✅
1. substrate level phosphorylation
2. oxidative phosphorylation
Quiz_________________?
3 categories of passive transport -
Answer✅
simple diffusion, facilitated diffusion, osmosis
Quiz_________________?
3 major types of organizations -
Answer✅
utilitarian, coercive, normative
2
, Quiz_________________?
3 power formulas -
Answer✅
P = IV
P = I^2R
P = V^2/R
Quiz_________________?
4 colligative properties of solutions -
Answer✅
vapor pressure lowering, boiling point elevation, freezing point depression, osmotic
pressure
Quiz_________________?
4 phases of bacteria growth -
Answer✅
1. lag phase (bacteria adapt to a new environment, growth lags)
2. log phase (exponential growth of population)
3. stationary phase (maximum population size is reached, growth limited by nutrients and
space)
4. death phase (bacteria begin to die off)
3
, Quiz_________________?
a 1 M solution of glucose contains -
Answer✅
6.02 × 1023 molecules of glucose in each liter of solution.
Quiz_________________?
A 5 kg box is resting on a ramp with an incline of 45 degrees. What can we say about the
value of the coefficient of static friction between the ramp and the box? -
Answer✅
For this problem it is crucial to realize that the force parallel along the incline, a component
of gravity, must be equal to the force of static friction currently being exerted. If this were
not the case, the box would not be at rest.
From this we can setup an inequality, knowing that static friction increases in response to an
applied force until the applied force is greater than the maximum possible static friction.
Knowing this we can setup the equations below:
mgsin(theta) <= usN
N = mgcos(theta)
mgsin(theta) <= us mg cos (theta)
tan(theta) =< us
1<= us
And thereby determine that our coefficient of static friction must be greater than or equal
to 1, or the box would be in motion. Notice that although you were provided with the
weight of the box, it turned out to be irrelevant.
Quiz_________________?
A car is continuously driving in a circle of radius 30 meters in a parking lot. How is the
centripetal force for this circular motion being generated? -
4
Quiz_________________?
[H+] = -
Answer✅
10^-pH
Quiz_________________?
0.0005 kilomorgans to centimorgans -
Answer✅
50 centimorgans
Quiz_________________?
1 joule equals -
Answer✅
1 Nm (newton * meter)
Quiz_________________?
1
, 1 Newton equals -
Answer✅
1 kg m/s^2
Quiz_________________?
1 pascal is equal to -
Answer✅
1 N/m^2
Quiz_________________?
2 ways to form ATP -
Answer✅
1. substrate level phosphorylation
2. oxidative phosphorylation
Quiz_________________?
3 categories of passive transport -
Answer✅
simple diffusion, facilitated diffusion, osmosis
Quiz_________________?
3 major types of organizations -
Answer✅
utilitarian, coercive, normative
2
, Quiz_________________?
3 power formulas -
Answer✅
P = IV
P = I^2R
P = V^2/R
Quiz_________________?
4 colligative properties of solutions -
Answer✅
vapor pressure lowering, boiling point elevation, freezing point depression, osmotic
pressure
Quiz_________________?
4 phases of bacteria growth -
Answer✅
1. lag phase (bacteria adapt to a new environment, growth lags)
2. log phase (exponential growth of population)
3. stationary phase (maximum population size is reached, growth limited by nutrients and
space)
4. death phase (bacteria begin to die off)
3
, Quiz_________________?
a 1 M solution of glucose contains -
Answer✅
6.02 × 1023 molecules of glucose in each liter of solution.
Quiz_________________?
A 5 kg box is resting on a ramp with an incline of 45 degrees. What can we say about the
value of the coefficient of static friction between the ramp and the box? -
Answer✅
For this problem it is crucial to realize that the force parallel along the incline, a component
of gravity, must be equal to the force of static friction currently being exerted. If this were
not the case, the box would not be at rest.
From this we can setup an inequality, knowing that static friction increases in response to an
applied force until the applied force is greater than the maximum possible static friction.
Knowing this we can setup the equations below:
mgsin(theta) <= usN
N = mgcos(theta)
mgsin(theta) <= us mg cos (theta)
tan(theta) =< us
1<= us
And thereby determine that our coefficient of static friction must be greater than or equal
to 1, or the box would be in motion. Notice that although you were provided with the
weight of the box, it turned out to be irrelevant.
Quiz_________________?
A car is continuously driving in a circle of radius 30 meters in a parking lot. How is the
centripetal force for this circular motion being generated? -
4
