AAMC MCAT Practice Exam 1 Study Guide Questions & Expertly Verified Answers | 2025 | 2026 – Graded A.

AAMC MCAT Practice Exam 1 Study Guide Questions & Expertly Verified Answers | 2025 | 2026 – Graded A. Quiz_________________? *Which two processes best summarize maintenance factors 1 and 2, respectively? "Specifically, patients with high interoceptive awareness are likely to associate mild changes in bodily sensations (such as slightly heightened heartbeat) with the panic they experienced during panic attacks; this leads to conditioned fear in response to changes in bodily sensations (Maintenance Factor 1). Another maintenance factor for PD is the misappraisal of bodily sensations (Maintenance Factor 2), such as interpreting bodily sensations as signs of imminent death or loss of control." A) Operant conditioning and top-down processing B) Classical conditioning and affective processes C) Operant conditioning and physiological processes D) Classical conditioning and cognitive processes - Answer D) Classical conditioning and cognitive processes The answer to this question is D because Maintenance Factor 1 focuses on classical conditioning of a fear response to bodily sensations, whereas Maintenance Factor 2 focuses on cognitive appraisal (interpretation) of bodily sensations. Quiz_________________? A certain bacterium was cultured for several generations in medium containing 15N, transferred to medium containing 14N, and allowed to complete two rounds of cell division. Given that the bacterium's genome mass is 5.4 fg when grown in 14N media and 5.5 fg when grown in 15N medium, individual bacteria with which of the following genome masses would most likely be isolated from this culture? A) 5.4 fg only B) 5.4 fg and 5.45 fg C) 5.4 fg and 5.5 fg D) 5.45 fg only - Answer B) 5.4 fg and 5.45 f The answer to this question is B because DNA replication is semi-conservative. Therefore, after the first round of cell division the genome mass in each bacterium will be 5.45 fg (one DNA strand will contain 15N and the other strand 14N). Following the second round of cell division, half of the bacteria will have a genome mass of 5.4 fg (14N exclusively) and the other half a mass genome of 5.45 fg (14N in one DNA strand and 15N in the other). Quiz_________________? A circuit similar to that in Figure 2 is set up in which X = Pb, Xn+ = Pb2+, Y = Cu, and Ym+ = Cu2+. Will an oxidation-reduction reaction occur spontaneously?* Pb2+(aq) + 2e- → Pb(s) E°red = -0.127 V Cu2+(aq) + 2e- → Cu(s) E°red = +0.339 V A) No; E°cell = -0.212. B) No; E°cell = +0.212. C) Yes; E°cell = -0.466. D) Yes; E°cell = +0.466. - Answer D) Yes; E°cell = +0.466. The answer to this question is D. A spontaneous reaction occurs when E° is greater than zero, and this occurs if the oxidation of Pb(s) is combined with the reduction of Cu2+(aq), resulting in a net E° of +0.466 V. Quiz_________________? A circuit similar to that in Figure 2 is set up. It has a potential of 2.0 V. Assume that the resistance in the circuit is negligible compared to that of the lightbulb. Approximately how much current passes through the lightbulb? Resistance = 0.5 ohms A) 0.5 A B) 1.0 A C) 2.0 A D) 4.0 A - Answer D) 4.0 A The answer to this question is D because according to Ohm's law, current is equal to voltage divided by resistance, hence 2.0 V/0.5 Ω = 4.0 A. Quiz_________________? A man with a CRC mutation that results in the synthesis of HSP110ΔE9 and a woman that does not carry this mutation in any of her tissues have a child. What is the percent chance that the child will inherit the CRC mutation? A) 0% B) 25% C) 50% D) 100% - Answer A) 0% The answer to this question is A. According to the passage, HSP110ΔE9 transcripts are not present in noncancerous tissue of people with MSI CRC. This means that the deletion mutation in the HSP110 T17 microsatellite is a somatic, not germ line, mutation. Therefore, the mutation will not be inherited, and the percent chance that the child of a person with this mutation will inherit it is 0%. Quiz_________________? A person whose eye has a lens-to-retina distance of 2.0 cm, can only clearly see objects that are closer than 1.0 m away. What is the strength S of the person's eye lens? (Note: Use the thin lens formula 1/O + 1/I = S) A) -50 D B) -10 D C) 51 D D) 55 D - Answer C) 51 D The answer to this question is C because the strength of the eye lens is equal to the inverse of the focal length of the eye lens. Its numerical value is given by (1 m)-1+(0.02 m)-1=1 D+50 D=51 D. Quiz_________________? A researcher replicates the experiment with the addition of a physical stressor to the first phase of the experiment. According to Selye's general adaptation syndrome, this change is: A) necessary, because humans respond differently to different types of stressors. B) necessary, because physical stressors cause avoidance-avoidance conflict, whereas social stressors cause approach-approach conflict. C) unnecessary, because the human stress response is not specific to the type of stressor. D) unnecessary, because both physical stressors and social stressors cause avoidance-avoidance conflict. - Answer C) unnecessary, because the human stress response is not specific to the type of stressor. The answer to this question is C because, according to Selye's general adaptation syndrome, people's response to various stressors is similar. Selye's theory does not make claims about avoidance-avoidance or approach-approach conflicts.