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Exam (elaborations)

Examen de computadores

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Examen resuelto entero

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Enero 24 FC

1) .
Representa en LEEE-754 SP . Expresa el resultado en
Binario Hexadecimal empaquetado
y
N1 = 0. 05 . 2-125 .
0, 05 ,
0
- pasar a binario

0.03.2 = 0.1 0.000#o ORIOOLIO ... 2 - 1,100 /100 11 . .. . 2
O 1 2 O, 2
. 38
.
. =



0 2 2
.




O, 4 2 .
.




=
= 0, 4

0, 8
Nr = (1 10010011
, .
25) .



200100M = número en binario

0, 8 2 . = L, 6

0, 6 て =
れ2
0 .
2 . 2 = O, u




Paso 1 - determinar si es normalizado o denormalizado:

Exp mín. para que normalizado
denormalizadoSigno=0noa
-
sea = -
126

como
exp = -130-ano 000 (pq es denormalizado
+리


antisa:
* 1 100110011.
, 2-138-0 80001100110011
. ....
2-1s
_
mantisa


7 IEEE
oอ
23 bits.

⑥ exp.sesgado I 100 11 00 /100 /100 11ออ
>
-

ㅣ binario

00 occcco

L nexadecimal pactado.

)
_ Signo
= 1 (no

ozu onnolllollls
-



10 Za
.
-




N2 68 .
oon
- =
-
> 136 = -



noooc - .)
256 ,
( -
8)


Pasar a decimal para calcular:

100 n = 1.16 = 256 10

1000cz = -
8 ,0

On NIOMMONNAS = - 136 10



-
6810 -
binario = -
1000100 = -1, 000100 . Número normalizado 6) -126
z




signo = 127 + 6 = 133 -binario : 10000101




n00on00n0 . YIEEE
exp. sesg
S
(binario)
.


~ 000 nexadeciset
s




pactaclo




มื้

, 2) . Opera .
pasar ambos no a C2 .
hacer su
negativo .

Et
"




X
ㅣ a) .
-
Y-X

111111010c2
en (min .
no bits) .



X
Onlll 0 lOs 00000110
>
- -
=
-
0
=




Y =
1011/10ISM >
- 11000011c2 = for1101c2 - -

Y
ooin in or
7 bits
como pasar entre ellos .
+
00000110
/8 .




= 00011
c2



b) Expresa
.
este resultado como SM con 12 bits

como empieza por o es
igual , pero debo añadir 0 ...
0

_
000 010000 11
SM

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