1 of 35
Term
Describe how the products of the light-dependent reaction are used in
the light-independent reaction to produce triose phosphate.
Do not include the role of ribulose bisphosphate (RuBP) in your answer
Give this one a go later!
Correct answer of 71 = 2 marks;;
1. ATP and reduced NADP; Answer of 142 = 1 mark
2. ATP provides energy; OR
3. GP reduced to triose 80 OR 9 in working = 1 mark
phosphate; OR
79.99 OR 8.93 in working = 1 mark;
1. Restriction
endonucleases/enzymes cuts
, If sex-linked) grey/male fly would not plasmid
have / pass on black/recessive allele Ligase joins 'sticky ends' and forms
phosphodiester bonds
Don't know?
2 of 35
Term
In fruit flies, a gene for body colour has a dominant allele for grey
body, G, and a recessive allele for black body, g.
Explain how you would determine if the genotype of a grey fly is
homozygous or heterozygous for body colour.
Give this one a go later!
If sex-linked) grey/male fly would not have / pass on black/recessive allele
1. RrGG and Rrgg;
1. Curly(-winged), grey(-bodied) and
Normal(-winged),grey(-bodied)andratio2:1
1. Interspecific (competition);
2. Less/no light (for potato plant) so less/no photosynthesis;
3. Less nitrates/nitrogen to produce amino acids/protein/DNA/RNA/ATP
Cross with a black (fly)
1. Black offspring/flies then is heterozygous/Gg
, or Compare base sequence with known alleles/Compare position/banding
with known alleles
Don't know?
3 of 35
Term
How many DNA fragments would be produced in experiment 2 if the
original DNA molecule was a plasmid?
Give this one a go later!
6 or six; 2 or two;
4 or four; 8 or eight;
Don't know?
4 of 35
Definition
1. Percentage/number in remission and percentage/number with weight
loss is higher for group P;
2. High percentage with weight loss (≥15 kg) in both groups achieved
remission;
3. Some with weight gain achieved remission;
4. Less than 50% in group P achieved remission;
, 5.Only shows results for volunteers with less than 5 years of diabetes;
6. No results for those over 60 years (of age)
OR
No results for those under 25 years of age;
7. No statistical test to see if significant difference (in results);
8. (Only shows remission) not cure
OR
Remission not (necessarily) long term;
Mass/weight(ofvolunteers)atbeginningnot known;
Give this one a go later!
10.3 The scientists concluded that it was probable that disruptive selection was
leading to sympatric speciation in the wall gecko.
Use the information in the passage to evaluate this conclusion.
10.1 The wall gecko shows phenotypic diversity (lines 1-2).
Suggest two factors that have resulted in this phenotypic diversity.
Use all the information to evaluate whether a weight-loss programme is an
effective treatment for type II diabetes.
A biologist investigated photosynthesis. They:
· measured the percentage of light absorbed by a plant when it was exposed to
different wavelengths
measured the rate of photosynthesis at each wavelength of light
Using Figure 3, what can you conclude about the relationship between:
Term
Describe how the products of the light-dependent reaction are used in
the light-independent reaction to produce triose phosphate.
Do not include the role of ribulose bisphosphate (RuBP) in your answer
Give this one a go later!
Correct answer of 71 = 2 marks;;
1. ATP and reduced NADP; Answer of 142 = 1 mark
2. ATP provides energy; OR
3. GP reduced to triose 80 OR 9 in working = 1 mark
phosphate; OR
79.99 OR 8.93 in working = 1 mark;
1. Restriction
endonucleases/enzymes cuts
, If sex-linked) grey/male fly would not plasmid
have / pass on black/recessive allele Ligase joins 'sticky ends' and forms
phosphodiester bonds
Don't know?
2 of 35
Term
In fruit flies, a gene for body colour has a dominant allele for grey
body, G, and a recessive allele for black body, g.
Explain how you would determine if the genotype of a grey fly is
homozygous or heterozygous for body colour.
Give this one a go later!
If sex-linked) grey/male fly would not have / pass on black/recessive allele
1. RrGG and Rrgg;
1. Curly(-winged), grey(-bodied) and
Normal(-winged),grey(-bodied)andratio2:1
1. Interspecific (competition);
2. Less/no light (for potato plant) so less/no photosynthesis;
3. Less nitrates/nitrogen to produce amino acids/protein/DNA/RNA/ATP
Cross with a black (fly)
1. Black offspring/flies then is heterozygous/Gg
, or Compare base sequence with known alleles/Compare position/banding
with known alleles
Don't know?
3 of 35
Term
How many DNA fragments would be produced in experiment 2 if the
original DNA molecule was a plasmid?
Give this one a go later!
6 or six; 2 or two;
4 or four; 8 or eight;
Don't know?
4 of 35
Definition
1. Percentage/number in remission and percentage/number with weight
loss is higher for group P;
2. High percentage with weight loss (≥15 kg) in both groups achieved
remission;
3. Some with weight gain achieved remission;
4. Less than 50% in group P achieved remission;
, 5.Only shows results for volunteers with less than 5 years of diabetes;
6. No results for those over 60 years (of age)
OR
No results for those under 25 years of age;
7. No statistical test to see if significant difference (in results);
8. (Only shows remission) not cure
OR
Remission not (necessarily) long term;
Mass/weight(ofvolunteers)atbeginningnot known;
Give this one a go later!
10.3 The scientists concluded that it was probable that disruptive selection was
leading to sympatric speciation in the wall gecko.
Use the information in the passage to evaluate this conclusion.
10.1 The wall gecko shows phenotypic diversity (lines 1-2).
Suggest two factors that have resulted in this phenotypic diversity.
Use all the information to evaluate whether a weight-loss programme is an
effective treatment for type II diabetes.
A biologist investigated photosynthesis. They:
· measured the percentage of light absorbed by a plant when it was exposed to
different wavelengths
measured the rate of photosynthesis at each wavelength of light
Using Figure 3, what can you conclude about the relationship between:
