Solution Manual for Molecular Thermodynamics of Fluid-Phase Equilibria (3rd Edition) by John M. Prausnitz, Rudiger N. Lichtenthaler, and Edmundo Gomes de Azevedo

All 12 Chapters Covered




SOLUTION MANUAL






, C O N T E N T S




Preface i

Solutions to Problems Chapter 2 1

Solutions to Problems Chapter 3 17

Solutions to Problems Chapter 4 29

Solutions to Problems Chapter 5 49

Solutions to Problems Chapter 6 81

Solutions to Problems Chapter 7 107

Solutions to Problems Chapter 8 121

Solutions to Problems Chapter 9 133

Solutions to Problems Chapter 10 153

Solutions to Problems Chapter 11 165

Solutions to Problems Chapter 12 177






, S O L U T I O N S T O P R O B L E M S


C H A P T E R 2




1. From problem statement, we want to find b P/

T g . Using the product-rule,
v
F PI F v F PI
Iv
HG T KJ HG vKJ P T

By definition, HG T
KJ
1 F vI
P G J
vH T K P

and
T
F vGI J
1

vH P T

Then, K
FP P

I 1.8 5
D -1


HG KJ
10 33.8 bar C
6
T v T 5.32 10

Integrating the above equation and assuming P and T constant over the temperature
range, we obtain

P  P
T
T

For T = 1 C, we
get
P 33.8 bar




1



, 2 Solutions Manual




2. Given the equation of state,
GFV bJ RT P
Hn K
FS I FP
we find:
nR
I I
HG V KJ HG T KJ V
T V
nb
F S I F V I nR
HG P KJ HG T KJ T P
P
F U I F PI
HG V KJ T G
H T KJ P
T V
0

F UI F U F VI
I
G
H PK J H V KJ HG P KJ
G 0
T T T
F HI F VI
HG P KJ T G
H T T KJ V nb

For an isothermal change,
z
H TK V



V1 nb
S V2 nb
V2 FG dV nR ln


P IJ
1 V


P1

z NMH
P
nR ln
P2


V K PKJ P
P
HG
U
z
P
2 LFG F O dP
VT
0

U IJ I Q
1
T

2L F  O
1 NMMTHG T K P P

V I


J