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After experiencing extreme fatigue and polyuria, a patient's basic metabolic panel is analyzed in the laboratory. The result of the glucose is too high for the instrument to read. The laboratorian performs a dilution using 0.25 mL of patient sample to 750 microliters of diluent. The result now reads 325 mg/dL. How should the techologist report this patient's glucose result? A. 325 mg/dL B. 1300 mg/dL C. 975 mg/dL D. 1625 mg/dL : B; The correct answer for this question is 1300 mg/...

Standard precautions apply to all of the following except: a. Blood b. Cerebrospinal fluid c. Semen d. Concentrated acids : d. Concentrated acids The most important practice in preventing the spread of disease is: a. Wearing masks during patient contact b. Proper hand washing c. Wearing disposable laboratory coats d. Identifying specimens from known or suspected HIV- and HBV-infected patients with a red label : b. Proper hand washing The appropriate dilution of bleach to use in lab...

MLT ASCP EXAM QUESTIONS AND CORRECT ANSWERS 2024 LATEST UPDATE GRADED A+

MLT ASCP EXAM QUESTIONS AND CORRECT ANSWERS 2024 LATEST UPDATE GRADED A+

A & C; The indicator(s) used in the pH test region are methyl red and bromothymol blue. Typically on most chemical reagent strips for urine pH, with an increase in urinary pH, the indicators bromothymol blue and methyl red, changes from orange to green and blue.

MLS ASCP ASCPI EXAM Questions With 100% Correct Answers Latest Updates

MLT Ascp exam Questions and Answers Latest Updates

MLT Ascp exam Questions and Answers Latest Updates

MLS ASCP ASCPI EXAM Questions With 100% Correct Answers Latest Updates

MLT ASCP Practice Test Questions board practice B; The correct answer for this question is 1300 mg/dL. The laboratorian performed a 1:4 dilution by adding 0.25 mL (or 250 microliters) of patient sample to 750 microliters of diluent. This creates a total volume of 1000 microliters. So, the patient sample is 250 microliters of the 1000 microliter mixed sample, or a ratio of 1:4. Therefore, the result given by the chemistry analyzer must be multiplied by a dilution factor of 4. 325 mg/dL x 4 = ...