CHEM 12 Chemistry 12
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Lab 13G Analysis of Results: Part 1) a) Mass of oxalic acid dihydrate H2C2O4 * 2H2O = 126g/mol b) Number of mol of oxalic acid measured 0.58g x =4.6x10 -3 mol 126g 1 mol c) Concentration of oxalic dihydrate Conc = = 4.6x10 -2 .1L 4.6x10 −3 Part 2) a) Number of mol of oxalic acid 4.6x10 -2M x 0.025L = 1.2x10 -3 mol b) Diprotic so 2x the number of mol of acid. 1.2x10 -3mol x 2 = 2.4x10 -3 mol NaOH c) Average mL of NaOH used = 23.70mL Conc = 0.02370L = 0.10M NaOH 2,4x10...
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Lab 13G Analysis of Results: Part 1) a) Mass of oxalic acid dihydrate H2C2O4 * 2H2O = 126g/mol b) Number of mol of oxalic acid measured 0.58g x =4.6x10 -3 mol 126g 1 mol c) Concentration of oxalic dihydrate Conc = = 4.6x10 -2 .1L 4.6x10 −3 Part 2) a) Number of mol of oxalic acid 4.6x10 -2M x 0.025L = 1.2x10 -3 mol b) Diprotic so 2x the number of mol of acid. 1.2x10 -3mol x 2 = 2.4x10 -3 mol NaOH c) Average mL of NaOH used = 23.70mL Conc = 0.02370L = 0.10M NaOH 2,4x10...