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Exam (elaborations)
Bnu1501 Assignment 4 Of Semester 1 2023
Bnu1501 Assignment 4 Of Semester 1 2023
Exam (elaborations)
Bnu1501 Expected Questions And Answers For Exam Semester 1 2024 Questions And Answers Latest Update Graded A+
PopularBNU1501 EXPECTED QUESTIONS AND ANSWERS FOR EXAM SEMESTER 1 2024 
QUESTIONS AND ANSWERS LATEST UPDATE GRADED A+ 
 
Question 1 
The expression 
35 ÷ 5 + 2 − ((3 × 4 − 2) − (18 − 3 × 4)) 
can be rewritten as 
9 − 6 + 42. 
9 − 10 + 6. 
5 − 6 + 42. 
5 − 10 + 6. 
Question 2 
Subtracting the sum of 2x + x3 and x + 7 from −8 − 5x3 + 4x gives 
−15 − 6x3 + x. 
3x + x3 + 7. 
−x + 6x3 + 15. 
7x − 4x3 + 15. 
Question 3 
The option that has the same value as 
 
is 
23√2 − ...
Exam (elaborations)
BNU1501 Exam Study Guide: GRADED A+. Questions and Verified Answers. Latest 2026 Update
NewBNU1501 Exam Study Guide: 
GRADED A+. Questions and 
Verified Answers. Latest 
2026 Update 
 
BNU1501 Exam Study Guide: 
GRADED A+. Questions and 
Verified Answers. Latest 
2026 Update 
 
BNU1501 Exam Study Guide: 
GRADED A+. Questions and 
Verified Answers. Latest 
2026 Update
Exam (elaborations)
Bnu1501 Final Exam Study Guide. Graded A+. With Questions And 100% Verified Answers. Latest Update Basic Numeracy Department Of Decision Sciences
NewBnu1501 Final Exam Study Guide. Graded A+. With 
Questions And 100% Verified Answers. Latest 
Update 
Basic Numeracy 
Department Of Decision Sciences 
 
Bnu1501 Final Exam Study Guide. Graded A+. With 
Questions And 100% Verified Answers. Latest 
Update 
Basic Numeracy 
Department Of Decision Sciences 
 
Bnu1501 Final Exam Study Guide. Graded A+. With 
Questions And 100% Verified Answers. Latest 
Update 
Basic Numeracy 
Department Of Decision Sciences
Exam (elaborations)
Bnu1501 Assignment 4 Semester 2, 2024-2025. Questions With Correct And Verified Answers. A+ Grade.
Question 1 
If a vertical and horizontal number line intersect perpendicularly, they form right angles (of 90°) with each other and a co-ordinate system of axes is formed, the horizontal line is called: 
[1]	Quadrants 
[2]	
Exam (elaborations)
Bnu1501 Assignment 4 Semester 2, 2024-2025. Questions With Correct And Verified Answers. A+ Grade.
Question 1 
If a vertical and horizontal number line intersect perpendicularly, they form right angles (of 90°) with each other and a co-ordinate system of axes is formed, the horizontal line is called: 
[1]	Quadrants 
[2]	
Exam (elaborations)
BNU1501 2019 Semester 02 Assignment 02 Solutions
Tutorial Letter 202/2/2019 
Basic Numeracy BNU1501 
Semester 2 of 2019 
Department of Decision Sciences 
Solutions to Assignment 02 
 
BNU1501/202/2/2019 
2 
BNU Semester 02 Assignment 02 Solutions 
Here are our correct options to the assignment questions 
Q 1 2 3 4 5 6 7 8 9 10 A 2 4 1 3 2 3 1 2 3 4 3 2 4 1 3 
Question 1 To convert mixed fractions to improper fractions 3 4 7 Multiply the whole number part by the fraction’s denominator. 3 ×7 = 21 Add the product that ...
Exam (elaborations)
BNU1501 Assignment 1 Semester 2 2020 Unique Number: 788360
BNU1501 
Assignment 1 Semester 2 2020 
Unique Number: 
 
Solutions, Explanations, workings, and references 
 
+27 67 171 1739 
This study source was downloaded by from CourseH on 08-02-2023 04:40:17 GMT -05:00 

1. 1 22.49258 to three decimal digits = 22.493 
2. 3 250.192 to one decimal digit = 250.2 
3. 1 3.496 to the nearest integer = 3 
4. 4 
5. 1 
6. 2 
7. 4 
8. 1 
9. 3 
This study source was downloaded by from CourseH on 08-02-2023 04:40:17 GMT -05:00 

© Varsity Cube 2020 +27 67 ...
Exam (elaborations)
BNU1501 Assignment 2 Semester 1 2019 Unique Number: 848259 Disclaimer The information presented here have been prepared by specialist who are fully qualified and possess extensive understanding of this module. Prescribed study material have been used to
1. 4 
Improper fraction = (8*3+2)/3 = 26/3 
2. 3 
Mixed fraction = 2001/8 = 250 remainder 1 = 250 1/8 
3. 2 
© CTM Tutoring All rights reserved 
 +19 
4. 1 
5. 2 
© CTM Tutoring All rights reserved 
 +19 
6. 3 
© CTM Tutoring All rights reserved 
 +19 
7.
Exam (elaborations)
Bnu1501 Assignment 1 Of Semester 1 2023
Bnu1501 Assignment 1 Of Semester 1 2023
Exam (elaborations)
Bnu1501 Assignment 2 Of Semester 1 2023
Bnu1501 Assignment 2 Of Semester 1 2023
Exam (elaborations)
Bnu1501 Assignment 3 Of Semester 1 2023
Bnu1501 Assignment 3 Of Semester 1 2023
Exam (elaborations)
Bnu1501 Assignment 4 Of Semester 1 2023
Bnu1501 Assignment 4 Of Semester 1 2023
Exam (elaborations)
Bnu1501 Assignment 3 Of Semester 1 2023
Bnu1501 Assignment 3 Of Semester 1 2023
Exam (elaborations)
Bnu1501 Assignment 2 Of Semester 1 2023
Bnu1501 Assignment 2 Of Semester 1 2023
Exam (elaborations)
Bnu1501 Assignment 1 Of Semester 1 2023
Bnu1501 Assignment 1 Of Semester 1 2023
Exam (elaborations)
BNU1501 Basic Numeracy Department of Decision Sciences
Question 1 
The straight line distance between two points is known as its 
The distance between two points is the length of the line segment that connects them. 
The correct option is: [4] length 
Question 2 
Find the perimeter of the diagram below 
Perimeter = (10 + 15 + 4 + 4 + 6 + 11) m = 50 m 
The correct option is: [3] 50 m 
Question 3 
Find the perimeter of the shaded region in the figure below, if ABCD is a square of side 14 cm 
and APB and CPD are semicircles, rounded off to the nearest ...
Exam (elaborations)
BNU1501_Assignment_03_Semester_2_2022_MEMO
Question 1 
The straight line distance between two points is known as its 
The distance between two points is the length of the line segment that connects them. 
The correct option is: [4] length 
Question 2 
Find the perimeter of the diagram below 
Perimeter = (10 + 15 + 4 + 4 + 6 + 11) m = 50 m 
The correct option is: [3] 50 m 
Question 3 
Find the perimeter of the shaded region in the figure below, if ABCD is a square of side 14 cm 
and APB and CPD are semicircles, rounded off to the nearest ...
Exam (elaborations)
Bnu1501 Assignment-03-Solutions Semester 2 - 2022
BNU1501 ASSIGNMENT-03-SOLUTIONS SEMESTER 2 - 2022 
Perimeter = 14 + 14 + 2π x 7 = 71.98 
1m2 
= 100 x 100 = 10 000cm2 
= 40 x 40/2 
= 800 
= 0.5 x 1 x 1 = 0.5cm2 
area of the remaining sheet 
= (25 x 20) – (π x 102