CHEMISTRY 104
Cambridge College
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Exam (elaborations)
Exam (elaborations) CHEMISTRY 104
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---9January 20232022/2023A
- Question 1 
9 / 10 pts 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
Show the calculation of the molar solubility (mol/L) of Mg(OH)2, Ksp of Mg(OH)2 = 1.8 x 10-11 
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Your Answer: 
ksp= [ M g + 2 ] [ O H − ] 2 
= (s ) (2s) 2 
s 3 = 1.8 x 10 − 11 / 4 
s= 3 ( 1.8 x 10 − 11 4 ) 
s= 1.65 x 10 − 4 mol/L 
Mg(OH)2 (s) Mg+2 (aq) + 2 OH-1 (aq) 
(s) (s) (2s) 
 1.8 x 10-11 = [Mg+2] x [OH-1] 
2 
 1.8 x 10-11 = [s] x [2s]2 
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