TEST BANK FOR Thermodynamics Problem Solving in Physical Chemistry 1st Edition By Kathleen E. Murphy

1.1 A) Calculate the values the equations have in common first: CH 4 = 25.0g 1.00molCH 4 16.0g é ë ê ê ù û ú ú = 1.163mol V m ,CH 4 = 2.0L 1.563mol = 1.28 L mol Given RT = 0.08206 L-atm mol-K (303K) = 24.86 L-atm mol , then calculate the pressure from each equation of state: (a) P ideal = RT V m = 24.86 L-atm mol 1.28 L mol = 19.4atm (b) P VdW ,CH 4 = RT V m - b - a V m 2 = 24.86 L-atm mol (1.28 - 0.04278) L mol - 2.283 L2-atm ...