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IB 150 EXAM 3 HOMEWORK QUESTIONS AND CORRECT ANSWERS

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IB 150 EXAM 3 HOMEWORK QUESTIONS AND CORRECT ANSWERS

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IB 150
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Institution
IB 150
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IB 150

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December 10, 2025
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IB 150 EXAM 3 HOMEWORK QUESTIONS AND CORR




The cHardy-Weinberg cequation cis cp2 c+ c2pq c+ cq2 c= c1. cWhat cdoes cthe cfact cthat cthe cgenotype
cdemonstrate?
Select cone:

a. cThat cnatural cselection cis cacting con ca cgene
b. cThat cthe cpopulation cis cevolving
c. cThat cthe cfrequencies cof ceach cgenotype chave cbeen cdetermined ccorrectly
d. cThat callele cfrequencies care cnot cchanging
e. cThat cmutation cis cacting con ca cgene c- cCORRECT cANS✔✔c. cThat cthe cfrequencies cof ceach c
cdetermined ccorrectly


Which cof cthe cfollowing cbest cdefines cbiological cevolution cwithin ca cpopulation?
Select cone:

a. cchange cin callele cfrequencies cover ctime
b. cnatural cselection
c. csurvival cof cthe cfittest
d. cphenotypic cchange cwithin can cindividual's clifetime c- cCORRECT cANS✔✔a. cchange cin callele c

What cgenotype cfrequencies care cexpected cunder cHardy-Weinberg cequilibrium cfor ca cpopulation c
c0.81 cand cq c= c0.19 cfor ca cparticular cgene?
Select cone:

a. cAA c= c0.250, cAa c= c0.500, cand caa c= c0.250
b. cAA c= c0.656, cAa c= c0.308 cand caa c= c0.036
c. cAA c= c0.333, cAa c= c0.333 cand caa c= c0.333
d. cAA c= c0.900, cAa c= c0.785 cand caa c= c0.436
e. cAA c= c0.810, cAa c= c0.154 cand caa c= c0.190 c- cCORRECT cANS✔✔b. cAA c= c0.656, cAa c= c0.30

Use cthe cinformation con callele cfrequencies cin cthree cpopulations cto cselect cthe ccorrect cstatemen
Population cA: cp-1, cq-0
Population cB: cp-0.60, cq-0.40
Population cC: cp-0, cq-1
Select cone:

, What cis cyour cbest cestimate cfor cthe cfrequency cof cthe ccolor-blindness-causing callele cin cthe cUS
Select cone:

a. c0.0064
b. c0.16
c. c0.28
d. c0.08 c
e. c0.1472 c- cCORRECT cANS✔✔d. c0.08 c

because cmen conly creceive ca csingle callele cfor cX-linked ctraits, cthey cactually cshow cthe callele cfre
cpopulation cin ctheir cphenotype calready!


What cdo cyou cpredict cis cthe clikelihood cfor ca cfemale cin cthe cUS cpopulation cto cshow cphenotypic
Select cone:

a. c0.1472
b. c0.0064
c. c0.16
d. c0.08 c- cCORRECT cANS✔✔b. c0.0064

In corder cfor ca cfemale cto cshow csymptoms cof cred-green ccolor cblindness, cshe cwould cneed cto cb
cGiven cthat cthe callele cfrequency cfor cthe crecessive callele, cq, cis c0.08 cin cthe cUS cpopulation, cthe
cfemale chomozygous crecessive cindividuals cis c0.0064, cor cthe cprobability cto cinherit cone crecessiv
cAND ca csecond callele, calso cat cfrequency c0.08. cThat cmeans, cthe cfrequency cto cbe chomozygous
c0.08*0.08 c= c0.0064.


You csampled c1000 cindividuals cfrom ca cpopulation cof cmosquitoes cto ctest cwhether cthey care cin cH
ca cgene cD, cwhere ca crecessive callele c(d) cis cresponsible cfor cconferring cpesticide cresistance.
After cgenotyping cyour c1000 csampled cmosquitoes, cgo cobtain cthe cfollowing cnumber cof cindividua
cgenotypes:
Genotype cdd: c22 cindividuals
Genotype cDd: c188 cindividuals
Genotype cDD: c790 cindividuals


Assuming cthat cthis cpopulation cof cmosquitoes cdoes cNOT cviolate cany cHardy-Weinberg cassumpt
cwhat c% cof cthe cpopulation cdo cyou cpredict cwill cshow cthe crecessive cphenotype cof cbeing cDDT cr
cANS✔✔1.3


Use cthe cHardy-Weinberg cprinciple cto cpredict cexpected cnumbers cof cindividuals cfor ceach cgenoty
ctrue, cand cthis cpopulation cis cNOT cevolving, cthen cuse ca cChi-Square ctest cto cdetermine cthe cp-v
csupport cyour cconclusion.
Select cone:

a. cp<0.05; cconclude cthat cpopulation cis cnot cin cHardy-Weinberg
b. cp<0.01; cconclude cthat cpopulation cis cnot cin cHardy-Weinberg
c. cp>0.05; cconclude cthat cpopulation cis cin cHardy-Weinberg
d. cp<0.05; cconclude cthat cpopulation cis cin cHardy-Weinberg
e. cp<0.01; cconclude cthat cpopulation cis cin cHardy-Weinberg
f. cp>0.01; cconclude cthat cpopulation cis cnot cin cHardy-Weinberg c- cCORRECT cANS✔✔a. cp<0.05;
cnot cin cHardy-Weinberg


1. cDetermine cobserved callele cfrequencies cby ccounting cthem cup cand cdividing cby cthe ctotal cnum
csample c(2000 cin cthis ccase). cIn cthis ccase cp=0.884 cand cq=0.116.
2. cOnce cyou chave cyour cobserved callele cfrequencies cfor cyour csampled cmosquitoes, cdetermine

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