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ORGANIC CHEMISTRY EXAM 3 QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) ALREADY GRADED A+

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Hydrogenation: "Reduces Carbon- Carbon bond" - triple to double, double to single Ans"Reduces Carbon- Carbon bond" - triple to double, double to single, **Don't need to know mechanism** Alkenes: Hydrogenation AnsUses metal catalysts (Pt, Pd, Ni2, or RH) -Alkene into alkane -Syn-addition (H's) Alkynes: Hydrogenation AnsUses same metal catalysts, Pt, Pd, Ni2, or RH Abundance of H2 always will take the alkyne to an alkan Lindlar's Pd--CIS alkene - Na & NH3 = TRANS- alkenes -Normal conditions w/ Pd = form alkane - Na & NH AnsTRANS- alkenes

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Organic Chemistry 1
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Institution
Organic Chemistry 1
Course
Organic Chemistry 1

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Uploaded on
December 10, 2025
Number of pages
12
Written in
2025/2026
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Exam (elaborations)
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ORGANIC CHEMISTRY EXAM 3 QUESTIONS AND
CORRECT DETAILED ANSWERS (VERIFIED ANSWERS)
ALREADY GRADED A+
Hydrogenation: "Reduces Carbon- Carbon bond" - triple to double,
double to single Ans✓✓✓"Reduces Carbon- Carbon bond" - triple to
double, double to single, **Don't need to know mechanism**


Alkenes: Hydrogenation Ans✓✓✓Uses metal catalysts (Pt, Pd, Ni2, or
RH)
-Alkene into alkane
-Syn-addition (H's)


Alkynes: Hydrogenation Ans✓✓✓Uses same metal catalysts, Pt, Pd,
Ni2, or RH
Abundance of H2 always will take the alkyne to an alkan
Lindlar's Pd--CIS alkene
- Na & NH3 = TRANS- alkenes
-Normal conditions w/ Pd = form alkane


- Na & NH Ans✓✓✓TRANS- alkenes


Lindlar's Pd Ans✓✓✓CIS alkene


-Normal conditions w/ Pd Ans✓✓✓alkane

, Addition of Hydrogen Halides (H—X) = Hydrohalogenation
Ans✓✓✓**Know Mechanism*


Alkenes Ans✓✓✓add H-X across the double bond
carbocation intermediate
Markovnikov's Rule


-Markovnikov's Rule—"rich get richer" Ans✓✓✓"rich get richer"
H goes to the area with the most H's; least subst C
X goes to the area with the least H's; most subst C


Free Radical Addition of H-Br w/ Peroxides (ROOH) Ans✓✓✓-Anti-
Markovnikov's
-free radical intermediates
1) Initiation: ROOR is broken into 2 RO radicals


1) Initiation: H-BR w/ ROOR Ans✓✓✓ROOR is broken into 2 RO
radicals


2) Propagation: H-Br w/ ROOR Ans✓✓✓3 arrows, 3 electrons travel, 2
coming from a bond & 1 from a free radical

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