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Summary Logarithms, Advanced Programme Mathematics - Grade 12 (IEB)

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Covers the various sections relating to Logarithms within the Advanced Mathematics programme. Includes notes from the textbook, as well as additional class, video and research information, diagrams and practice questions. Applicable to all IEB Grade 12s.

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Uploaded on
February 15, 2021
Number of pages
10
Written in
2020/2021
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Summary

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Logarithms
ax = b or logab = x
baseexponent = value logbase value = exponent
base > 0
base ≠ 1
value > 0

Laws:
1. logmxa = alogmx (x > 0 ; y > 0 ; 0 < a < 1 or a > 1)

2. logm(xy) = logmx + logmy (x > 0 ; y > 0 ; 0 < a < 1 or a > 1)

𝑥
3. logm( ) = logmx - logmy (x > 0 ; y > 0 ; 0 < a < 1 or a > 1)
𝑦

𝑙𝑜𝑔𝑛 𝑥
4. logmx = (change of base law)
𝑙𝑜𝑔𝑛 𝑚

1
5. logxm =
𝑙𝑜𝑔𝑚 𝑥



Note:
loga(x + y) ≠ logax + logay
loga(x - y) ≠ logax - logay
. (logax)m ≠ mlogax


Common logarithm
= a logarithm to base 10
(Written without showing the base)
Example: log10x = logx



Deductions:
1. logaa = 1

2. loga1 = 0

3. log1/ax = - logax

1
4. log1/a( ) = logax
𝑥

, Log Expressions
Terms with different bases – simplify the terms separately
Terms with the same base – write as a single log

Example: Law 1,3 and Deduction 1

log927 + log93
= log9(27 x 3)
= log981
= log9(9)2
= 2log99
=2x1
=2

Example: Law 2,3 and Deduction 1

log327 + log33
27
= log3( 3 )
= log39
= log3(3)2
= 2log33
=2x1
=2

Example: Law 1,2,3 and Deduction 1,2

log20 + log 30 - log6 + log41
= log20 + log 30 - log6 + 0
= log(20 x 30) - log6
= log(600) - log6
600
= log( 6
)
= log100
= log10100
= log10(10)2
= 2log1010
=2x1

Example:

log3√27
= log3271/2
1
= 2 log327
1
= 2 log3(3)3
3
= 2 log3(3)
3
= x1
2
3
= 2
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