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ITM207 Midterm Exam Questions and Answers | Latest Update 2026/2027 | Graded A+ | 100% Correct.

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ITM207 Midterm Exam Questions and Answers | Latest Update 2026/2027 | Graded A+ | 100% Correct. 1. What’s the 1’s complement of 1000? a) 0111 b) 1111 c) 111 d) 0001 2. What’s the 2’s complement of the following binary number: 1000 a) 1000 b) 0111 c) 1111 d) 3. What is the binary representation of the decimal number -1 using 3 bits? a) 111 b) 000 c) 110 d) 100 4. What would be the binary representation of the decimal number -1.1 using 4 bits? 2 bits to represent the negative part and 2 bits to represent the fraction part. Total 4 bits. a) 11.00 b) 10.01 c) 11.11 d) Binary representation of the given number using 5 bits is not possible 5. If A=1, B=1, C=0 then what is the value of the following Boolean expression? AA’+BB’+ A’B’C a) 1 b) 0 c) 000001 d) 111110 6. What’s the 2’s complement of the binary number 10 using 8 bits? a) b) c) d) 7. Which of the following Boolean expression will always output 1. a) (X+X’)YY’ b) (XX’)(YY’) c) (X+X’)(Y+Y’) d) (X+X’)’(YY’)’

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ITM207 Midterm Exam Questions and Answers |
Latest Update 2026/2027 | Graded A+ | 100%
Correct.



1. What’s the 1’s complement of 1000?
a) 0111

b) 1111

c) 111

d) 0001



2. What’s the 2’s complement of the following binary number:
1000
a) 1000

b) 0111

c) 1111

d) 0000 0001




3. What is the binary representation of the decimal number -1
using 3 bits? a) 111
b) 000

c) 110

d) 100

, 4. What would be the binary representation of the decimal
number -1.1 using 4 bits? 2 bits to represent the negative part
and 2 bits to represent the fraction part. Total 4 bits. a) 11.00
b) 10.01

c) 11.11
d) Binary representation of the given number using 5 bits is

not possible

5. If A=1, B=1, C=0 then what is the value of the following
Boolean expression?
AA’+BB’+ A’B’C
a) 1

b) 0

c) 000001

d) 111110



6. What’s the 2’s complement of the binary number 10 using 8
bits?
a) 1111 1110

b) 0000 0001

c) 0000 1101

d) 0000 0010



7. Which of the following Boolean expression will always
output 1.
a) (X+X’)YY’

b) (XX’)(YY’)

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