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,chapter 1: arithmetic needed for dosage
multiple choice
1. a patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15
oz. what portion of the water remained?
a. 2/5
b. 3/5
c. 2/25
d. 25/25
answer: a
feedback: subtract the quantity of water the client drank (15 oz) from the total available quantity (25
oz): 10 oz remain. to determine the portion of the water that remains, create a fraction by dividing
10 oz (remaining portion) by 25 oz (total portion). therefore, 10 divided by 25 = 10/25. to reduce
fractions, find the largest number that can be divided evenly into the numerator and the
denominator
(5). ten divided by 5 (10/5) = 2; 25/5 = 5. the fraction 10/25 can be reduced to its lowest terms of 2/5.
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: apply
difficulty: moderate
page and header: 2, dividing whole numbers; 3, fractions
integrated process: teaching/learning
objective: 1, 2
2. a patient/client was prescribed 240w
mwlwo.f etnb
susremb.ywmsouth as a supplement but consumed only 100
ml. what portion of the ensure remained?
a. 5/12
b. 7/12
c. 100/240
d. 240/240
answer: b
feedback: subtract the quantity of ensure the client consumed (100 ml) from the total available
quantity (240 ml): 140 ml remain. to determine the portion of the ensure that remains, create a
fraction by dividing 140 ml (remaining portion) by 240 ml (total portion). therefore, 140 divided by
240 = 7/12. to reduce fractions, find the largest number that can be divided evenly into the
numerator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. the fraction
140/240 can be reduced to its lowest terms of 7/12.
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: apply
difficulty: moderate
page and header: 2, dividing whole numbers; 3, fractions
integrated process: teaching/learning
objective: 1, 2
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, 3. a patient/client consumed oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. what is
the total number of ounces consumed that should be documented for the patient/client?
a. 3 3/4
b. 4 5/12
c. 4 2/3
d. 4 4/9
answer: b
feedback: add the amount of ounces consumed. first, change any mixed number to a fraction by
multiplying the whole number by the denominator and then adding that total to the numerator. for
the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
= 2 + 1 = 3/2. then add: 9/4 + 2/3 (ice cream) + 3/2. when fractions have different denominators, find
the least common denominator (lcd). for 2, 3, and 4, the lcd =
12. rewrite each fraction using the lcd; divide the lcd by the denominator of each fraction and then
multiply that result by the numerator of the fraction. the new fractions to be added are 27/12
(coffee), 8/12 (ice cream), and 18/12 (beef broth). after conversion of the fractions, the numerators
are added together and the fraction is reduced to the lowest terms.
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: analyze
difficulty: difficult
page and header: 2, multiplying whole numbers; 3, fractions
integrated process: communication and documentation
objective: 1, 2
4. a coffee cup holds 180 ml. the patient/client drank 2? cups of coffee. how many milliliters would
the nurse document as
consumed?
a. 360
b. 420
c. 510
d. 600
answer: b
feedback: the coffee cup holds 180 ml. the client drank 2? cups. to estimate the total number of
milliliters consumed, multiply 180 7/3 ( ). when a mixed number is present, change it to an
improper fraction by multiplying the whole number by the denominator and then adding that total to
the numerator: 2 3 = 6 + 1 = 7/3. therefore, 180 ml × 7/3 = 420 ml (180 ÷ 3 = 60 × 7 = 420).
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: analyze
difficulty: difficult
page and header: 2, multiplying whole numbers; 3, fractions
integrated process: communication and documentation
objective: 1, 2
5. a patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. how many kilograms were
gained since admission?
a. 0.78
b. 0.88
4|Pag e
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, 2|Pag e
www.PlusBay.Plus
,chapter 1: arithmetic needed for dosage
multiple choice
1. a patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15
oz. what portion of the water remained?
a. 2/5
b. 3/5
c. 2/25
d. 25/25
answer: a
feedback: subtract the quantity of water the client drank (15 oz) from the total available quantity (25
oz): 10 oz remain. to determine the portion of the water that remains, create a fraction by dividing
10 oz (remaining portion) by 25 oz (total portion). therefore, 10 divided by 25 = 10/25. to reduce
fractions, find the largest number that can be divided evenly into the numerator and the
denominator
(5). ten divided by 5 (10/5) = 2; 25/5 = 5. the fraction 10/25 can be reduced to its lowest terms of 2/5.
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: apply
difficulty: moderate
page and header: 2, dividing whole numbers; 3, fractions
integrated process: teaching/learning
objective: 1, 2
2. a patient/client was prescribed 240w
mwlwo.f etnb
susremb.ywmsouth as a supplement but consumed only 100
ml. what portion of the ensure remained?
a. 5/12
b. 7/12
c. 100/240
d. 240/240
answer: b
feedback: subtract the quantity of ensure the client consumed (100 ml) from the total available
quantity (240 ml): 140 ml remain. to determine the portion of the ensure that remains, create a
fraction by dividing 140 ml (remaining portion) by 240 ml (total portion). therefore, 140 divided by
240 = 7/12. to reduce fractions, find the largest number that can be divided evenly into the
numerator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. the fraction
140/240 can be reduced to its lowest terms of 7/12.
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: apply
difficulty: moderate
page and header: 2, dividing whole numbers; 3, fractions
integrated process: teaching/learning
objective: 1, 2
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, 3. a patient/client consumed oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. what is
the total number of ounces consumed that should be documented for the patient/client?
a. 3 3/4
b. 4 5/12
c. 4 2/3
d. 4 4/9
answer: b
feedback: add the amount of ounces consumed. first, change any mixed number to a fraction by
multiplying the whole number by the denominator and then adding that total to the numerator. for
the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
= 2 + 1 = 3/2. then add: 9/4 + 2/3 (ice cream) + 3/2. when fractions have different denominators, find
the least common denominator (lcd). for 2, 3, and 4, the lcd =
12. rewrite each fraction using the lcd; divide the lcd by the denominator of each fraction and then
multiply that result by the numerator of the fraction. the new fractions to be added are 27/12
(coffee), 8/12 (ice cream), and 18/12 (beef broth). after conversion of the fractions, the numerators
are added together and the fraction is reduced to the lowest terms.
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: analyze
difficulty: difficult
page and header: 2, multiplying whole numbers; 3, fractions
integrated process: communication and documentation
objective: 1, 2
4. a coffee cup holds 180 ml. the patient/client drank 2? cups of coffee. how many milliliters would
the nurse document as
consumed?
a. 360
b. 420
c. 510
d. 600
answer: b
feedback: the coffee cup holds 180 ml. the client drank 2? cups. to estimate the total number of
milliliters consumed, multiply 180 7/3 ( ). when a mixed number is present, change it to an
improper fraction by multiplying the whole number by the denominator and then adding that total to
the numerator: 2 3 = 6 + 1 = 7/3. therefore, 180 ml × 7/3 = 420 ml (180 ÷ 3 = 60 × 7 = 420).
format: multiple choice
chapter: 1
client needs: physiological integrity: basic care and comfort
cognitive level: analyze
difficulty: difficult
page and header: 2, multiplying whole numbers; 3, fractions
integrated process: communication and documentation
objective: 1, 2
5. a patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. how many kilograms were
gained since admission?
a. 0.78
b. 0.88
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