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Exam (elaborations)

OAR Formulas Questions with Accurate

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Exam of 5 pages for the course OAR at OAR (OAR Formulas)

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OAR
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Institution
OAR
Course
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Uploaded on
November 13, 2025
Number of pages
5
Written in
2025/2026
Type
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OAR Formulas
Volume of a cone - answerV=(1/3)πr²h

Area of a triangle - answerA=(1/2)bh

Area of a circle - answerA=πr²

Volume of a regular prism - answerV=lwh

Volume of a cube - answerV=s³

Volume of a sphere - answerV=(4/3)πr³

Volume of cynlinder - answerV=πr²h

Outlier - answer1.5 x IQR above or below upper or lower bound

Z-score - answerz = (x - mean) / standard deviation

Area of a trapezoid - answerA=1/2h(b1+b2)

Distance formula - answerd = √[( x₂ - x₁)² + (y₂ - y₁)²]

Circumpherence of circle - answerC=2πr

Arc length - answerarc = angle/360 x 2πr

Scale a polygon by "k" - answer(x,y) ---> (kx,ky)

Area of a sphere - answerA=4πr²

Velocity - answerV = distance(including direction) / time

Acceleration - answerA = change in velocity / time

Force - answerF = mass x acceleration

Momentum - answerM = mass x velocity

Work - answerW = force x distance
(newton meters)

Potential energy - answerPE = mass x acceleration of gravity x distance(y)

, (newton meters)

Kinetic energy - answerKE=(1/2)mv²
(newton meters) -- v² = (2 x work output) / mass

Energy - answerEnergy = Work = force x distance

Work (fluids) - answerWork = pressure x piston area x displacement
or
Work = pressure x change in volume

Pressure - answerP = F(force) / A(area)
P = weight of liquid x distance
P = density of liquid x depth x acceleration of gravity

Flow rate - answerQ = v x A
- For a given flow rate, a smaller pipe requires a higher velocity

Effort (lever) - answerF = R(load) x [L2(lever arm btwn. fulcrum and load) / L1 (lever arm
btwn. fulcrum and force/effort)]

Effort (wheels/axles) - answerF = L(load) x [r(radius of axle) / R (radius of wheel)]

Speed of gears - answer(Revolutions of gear B / Revolutions of gear A) = (Number of
teeth gear A / Number of teeth gear B)

Force (ramp) - answerF = (H/D) x W(weight)

Mechanical advantage of a car jack - answerF = L(length of threaded portion) x [p(pitch)
/ 2πR(length of lever)]

Revolution - answerR = 2π radians

Projectile motion (no time) - answerd = [v(f)² - v(i)²] / 2a
v(f)² = v(i)² + 2ad

Projectile motion (no distance) - answerv(f) = v(i) + at

Projectile motion (no acceleration) - answerd = [(v(i) + v(f)) / 2] x t

Projectile motion (no final velocity) - answerd = v(i)t + (1/2)at²

Density - answerd = mass / volume

Liters ---> meters cubed (conversion) - answer1,000L = 1m³

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