MULTIPLE CHOIC HN
E
1. The body’s mechanism for conducting air in and out of the lungs is known as whi
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ch of the following?
HN HN HN
a. External respiration HN
b. Internal respiration HN
c. Spontaneous ventilation HN
d. Mechanical ventilation HN
ANS: H N C
The conduction of air in and out of the body is known as ventilation. Since the quest
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ion asks for the body’s mechanism, this would be spontaneous ventilation. External res
HN HN HN HN HN HN HN HN HN HN HN HN
piration involves the exchange of oxygen (O2) and carbon dioxide (CO2) between the
HN HN HN HN HN HN HN HN HN HN HN HN HN
alveoli and the pulmonary capillaries. Internal respiration occurs at the cellular level an
HN HN HN HN HN HN HN HN HN HN HN HN
d involves movement of oxygen from the systemic blood into the cells.
HN HN HN HN HN HN HN HN HN HN HN
, REF: HNHN pg. 2 HN
2. Which of the following are involved in external respiration?
HN HN HN HN HN HN HN HN
a. Red blood cells and body cells
HN HN HN HN HN
b. Scalenes and trapezius musclesHN HN HN
c. Alveoli and pulmonary capillaries
HN HN HN
d. External oblique and transverse abdominal muscles
HN HN HN HN HN
ANS: H N C
External respiration involves the exchange of oxygen and carbon dioxide (CO2) between
HN HN HN HN HN HN HN HN HN HN HN H
Nthe alveoli and the pulmonary capillaries. Internal respiration occurs at the cellular lev
HN HN HN HN HN HN HN HN HN HN HN HN
el and involves movement of oxygen from the systemic blood into the cells. Scalene a
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
nd trapezius muscles are accessory muscles of inspiration. External oblique and transver
HN HN HN HN HN HN HN HN HN HN HN
se abdominal muscles are accessory muscles of expiration.
HN HN HN HN HN HN HN
REF: HNHN pg. 2 HN
3. The graph that shows intrapleural pressure changes during normal spontaneous breath
HN HN HN HN HN HN HN HN HN HN
ing is depicted by which of the following?
HN HN HN HN HN HN HN
a.
, b.
c.
d.
ANS: H N B
During spontaneous breathing, the intrapleural pressure drops from about 5 cm H2O at e
HN HN HN HN HN HN HN HN HN HN HN HN HN
nd- expiration to about 10 cm H2O at end-
HN HN HN HN HN HN HN HN
inspiration. The graph depicted for answer B shows that change from 5 cm H2O to
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
10 cm H2O.
HN HN
REF: HNHN pg. 3 HN
4. During spontaneous inspiration alveolar pressure (PA) is about:
HN HN HN HN HN HN HN HN .
a. 1 cm H2O HN HN
b. +1 cm H2O
H N H N HN HN
c. 0 cm H2O HN HN
d. 5 cm H2O HN HN
ANS: H N A
1 cm H2O is the lowest alveolar pressure will become during normal spontaneous ven
HN HN HN HN HN HN HN HN HN HN HN HN HN
tilation. During the exhalation of a normal spontaneous breath the alveolar pressure will
HN HN HN HN HN HN HN HN HN HN HN HN H
Nbecome 1 cm H2O. HN HN HN
REF: HNHN pg. 4 HN
5. The pressure required to maintain alveolar inflation is known as which of the following
HN HN HN HN HN HN HN HN HN HN HN HN HN
?
a. Transairway pressure (PTA) HN HN
b. Transthoracic pressure (PTT) HN HN
c. Transrespiratory pressure (PTR) HN HN
d. Transpulmonary pressure (PL) HN HN
ANS: H N D
, The definition of transpulmonary pressure (PL) is the pressure required to maintain alve
HN HN HN HN HN HN HN HN HN HN HN HN
olar inflation. Transairway pressure (PTA) is the pressure gradient required to produce air
HN HN HN HN HN HN HN HN HN HN HN HN
flow in the conducting tubes. Transrespiratory pressure (PTR) is the pressure to inflate t
HN HN HN HN HN HN HN HN HN HN HN HN HN
he lungs and airways during positive-
HN HN HN HN HN
pressure ventilation. Transthoracic pressure (PTT) represents the pressure required to exp
HN HN HN HN HN HN HN HN HN HN
and or contract the lungs and the chest wall at the same time.
HN HN HN HN HN HN HN HN HN HN HN HN
REF: HNHN pg. 4 HN
6. Calculate the pressure needed to overcome airway resistance during positive-
HN HN HN HN HN HN HN HN HN
pressure ventilation when the proximal airway pressure (PAw) is 35 cm H2O and the a
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
lveolar pressure (PA) is 5 cm H2O.
HN HN HN HN HN HN
a. 7 cm H2O HN HN
b. 30 cm H2O HN HN
c. 40 cm H2O HN HN
d. 175 cm H2O HN HN
ANS: H N B
The transairway pressure (PTA) is used to calculate the pressure required to overcome air
HN HN HN HN HN HN HN HN HN HN HN HN HN
way resistance during mechanical ventilation. This formula is PTA = Paw - PA.
HN HN HN HN HN HN HN HN HN HN HN HN
REF: HNHN pg. 4 HN
7. The term used to describe the tendency of a structure to return to its original form af
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ter being stretched or acted on by an outside force is which of the following?
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
a. Elastance
b. Compliance
c. Viscous resistance HN
d. Distending pressure HN
ANS: H N A
The elastance of a structure is the tendency of that structure to return to its original sh
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ape after being stretched. The more elastance a structure has, the more difficult it is to
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
stretch. The compliance of a structure is the ease with which the structure distends or
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
stretches.
HN
Compliance is the opposite of elastance. Viscous resistance is the opposition to move
HN HN HN HN HN HN HN HN HN HN HN HN
ment offered by adjacent structures such as the lungs and their adjacent organs. Distend
HN HN HN HN HN HN HN HN HN HN HN HN HN
ing pressure is pressure required to maintain inflation, for example, alveolar distending
HN HN HN HN HN HN HN HN HN HN HN H
Npressure.
REF: HNHN pg. 5 HN
8. Calculate the pressure required to achieve a tidal volume of 400 mL for an intubated
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
HN patient with a respiratory system compliance of 15 mL/cm H2O.
HN HN HN HN HN HN HN HN HN
a. 6 cm H2O
HN HN
b. 26.7 cm H2O HN HN
c. 37.5 cm H2O HN HN
d. 41.5 cm H2O HN HN
ANS: H N B
C =
HN HN V/ P then HN HN P = HN HN V/ C
REF: HNHN pg. 5 HN
E
1. The body’s mechanism for conducting air in and out of the lungs is known as whi
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ch of the following?
HN HN HN
a. External respiration HN
b. Internal respiration HN
c. Spontaneous ventilation HN
d. Mechanical ventilation HN
ANS: H N C
The conduction of air in and out of the body is known as ventilation. Since the quest
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ion asks for the body’s mechanism, this would be spontaneous ventilation. External res
HN HN HN HN HN HN HN HN HN HN HN HN
piration involves the exchange of oxygen (O2) and carbon dioxide (CO2) between the
HN HN HN HN HN HN HN HN HN HN HN HN HN
alveoli and the pulmonary capillaries. Internal respiration occurs at the cellular level an
HN HN HN HN HN HN HN HN HN HN HN HN
d involves movement of oxygen from the systemic blood into the cells.
HN HN HN HN HN HN HN HN HN HN HN
, REF: HNHN pg. 2 HN
2. Which of the following are involved in external respiration?
HN HN HN HN HN HN HN HN
a. Red blood cells and body cells
HN HN HN HN HN
b. Scalenes and trapezius musclesHN HN HN
c. Alveoli and pulmonary capillaries
HN HN HN
d. External oblique and transverse abdominal muscles
HN HN HN HN HN
ANS: H N C
External respiration involves the exchange of oxygen and carbon dioxide (CO2) between
HN HN HN HN HN HN HN HN HN HN HN H
Nthe alveoli and the pulmonary capillaries. Internal respiration occurs at the cellular lev
HN HN HN HN HN HN HN HN HN HN HN HN
el and involves movement of oxygen from the systemic blood into the cells. Scalene a
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
nd trapezius muscles are accessory muscles of inspiration. External oblique and transver
HN HN HN HN HN HN HN HN HN HN HN
se abdominal muscles are accessory muscles of expiration.
HN HN HN HN HN HN HN
REF: HNHN pg. 2 HN
3. The graph that shows intrapleural pressure changes during normal spontaneous breath
HN HN HN HN HN HN HN HN HN HN
ing is depicted by which of the following?
HN HN HN HN HN HN HN
a.
, b.
c.
d.
ANS: H N B
During spontaneous breathing, the intrapleural pressure drops from about 5 cm H2O at e
HN HN HN HN HN HN HN HN HN HN HN HN HN
nd- expiration to about 10 cm H2O at end-
HN HN HN HN HN HN HN HN
inspiration. The graph depicted for answer B shows that change from 5 cm H2O to
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
10 cm H2O.
HN HN
REF: HNHN pg. 3 HN
4. During spontaneous inspiration alveolar pressure (PA) is about:
HN HN HN HN HN HN HN HN .
a. 1 cm H2O HN HN
b. +1 cm H2O
H N H N HN HN
c. 0 cm H2O HN HN
d. 5 cm H2O HN HN
ANS: H N A
1 cm H2O is the lowest alveolar pressure will become during normal spontaneous ven
HN HN HN HN HN HN HN HN HN HN HN HN HN
tilation. During the exhalation of a normal spontaneous breath the alveolar pressure will
HN HN HN HN HN HN HN HN HN HN HN HN H
Nbecome 1 cm H2O. HN HN HN
REF: HNHN pg. 4 HN
5. The pressure required to maintain alveolar inflation is known as which of the following
HN HN HN HN HN HN HN HN HN HN HN HN HN
?
a. Transairway pressure (PTA) HN HN
b. Transthoracic pressure (PTT) HN HN
c. Transrespiratory pressure (PTR) HN HN
d. Transpulmonary pressure (PL) HN HN
ANS: H N D
, The definition of transpulmonary pressure (PL) is the pressure required to maintain alve
HN HN HN HN HN HN HN HN HN HN HN HN
olar inflation. Transairway pressure (PTA) is the pressure gradient required to produce air
HN HN HN HN HN HN HN HN HN HN HN HN
flow in the conducting tubes. Transrespiratory pressure (PTR) is the pressure to inflate t
HN HN HN HN HN HN HN HN HN HN HN HN HN
he lungs and airways during positive-
HN HN HN HN HN
pressure ventilation. Transthoracic pressure (PTT) represents the pressure required to exp
HN HN HN HN HN HN HN HN HN HN
and or contract the lungs and the chest wall at the same time.
HN HN HN HN HN HN HN HN HN HN HN HN
REF: HNHN pg. 4 HN
6. Calculate the pressure needed to overcome airway resistance during positive-
HN HN HN HN HN HN HN HN HN
pressure ventilation when the proximal airway pressure (PAw) is 35 cm H2O and the a
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
lveolar pressure (PA) is 5 cm H2O.
HN HN HN HN HN HN
a. 7 cm H2O HN HN
b. 30 cm H2O HN HN
c. 40 cm H2O HN HN
d. 175 cm H2O HN HN
ANS: H N B
The transairway pressure (PTA) is used to calculate the pressure required to overcome air
HN HN HN HN HN HN HN HN HN HN HN HN HN
way resistance during mechanical ventilation. This formula is PTA = Paw - PA.
HN HN HN HN HN HN HN HN HN HN HN HN
REF: HNHN pg. 4 HN
7. The term used to describe the tendency of a structure to return to its original form af
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ter being stretched or acted on by an outside force is which of the following?
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
a. Elastance
b. Compliance
c. Viscous resistance HN
d. Distending pressure HN
ANS: H N A
The elastance of a structure is the tendency of that structure to return to its original sh
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
ape after being stretched. The more elastance a structure has, the more difficult it is to
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
stretch. The compliance of a structure is the ease with which the structure distends or
HN HN HN HN HN HN HN HN HN HN HN HN HN HN HN
stretches.
HN
Compliance is the opposite of elastance. Viscous resistance is the opposition to move
HN HN HN HN HN HN HN HN HN HN HN HN
ment offered by adjacent structures such as the lungs and their adjacent organs. Distend
HN HN HN HN HN HN HN HN HN HN HN HN HN
ing pressure is pressure required to maintain inflation, for example, alveolar distending
HN HN HN HN HN HN HN HN HN HN HN H
Npressure.
REF: HNHN pg. 5 HN
8. Calculate the pressure required to achieve a tidal volume of 400 mL for an intubated
HN HN HN HN HN HN HN HN HN HN HN HN HN HN
HN patient with a respiratory system compliance of 15 mL/cm H2O.
HN HN HN HN HN HN HN HN HN
a. 6 cm H2O
HN HN
b. 26.7 cm H2O HN HN
c. 37.5 cm H2O HN HN
d. 41.5 cm H2O HN HN
ANS: H N B
C =
HN HN V/ P then HN HN P = HN HN V/ C
REF: HNHN pg. 5 HN