CHEM 1212 - EXPERIMENT #6 QUESTIONS AND ANSWERS | UPDATE | 100% CORRECT | A GRADE 1. Sid Trick titrated an 8.50 mL aliquot of juice. It required 14.87 mL of 0.0981 M NaOH to reach the equivalence point. Analyze his results and answer the questions below. The reaction and the molar mass are given below. H3C6H5O7(aq) + 3 NaOH(aq) ’ Na3C6H5O7(aq) + 3 H2O(ℓ) Molar Mass of H3C6H5O7 = 192.12 g/mL How many grams of citric acid were present in the aliquot?___ g How many mg of citric acid were present per mL of juice? ___ mg/mL: 0.00934 g 11.0 mg/Ml 2. For the error, indicate if the error will affect the mg of citric acid present per mL of juice, and if it does, will it raise or lower the value of the mg citiric acid/ mL of juice? Over-titrating the end point (adding too much titrant) a. Raises the value of mg citric acid/mL juice b. No effect c. Lowers the value of mg citric acid/mL juice: a. Raises the value of mg citric acid/mL juice 3. For the error, indicate if the error will affect the mg of citric acid present per mL of juice, and if it does, will it raise or lower the value of the mg citiric acid/ mL of juice?
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