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MAE 284 FINAL EXAM QUESTIONS WITH VERIFIED ANSWERS. A+ GRADE 2025/2026.

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MAE 284 FINAL EXAM QUESTIONS WITH VERIFIED ANSWERS. A+ GRADE 2025/2026.

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MAE 284 FINAL EXAM QUESTIONS
WITH VERIFIED ANSWERS. A+ GRADE
2025/2026.




All mathematical problems have closed-form solution(i.e. they can be solved for a variable
having to make guesses) (T/F) - ANS False


All variables that have been defined are found in the command window, even empty ones(T/F)
- ANS False



Anonymous functions need to be defined before being used(T/F) - ANS True


Given two vectors a and b, which command would you use to calculate the cross product of a
and b? - ANS cross(a,b)



The bisection algorithm is an open method(T/F) - ANS False


The bisection method is most effective when there are multiple roots inside a bracket (T/F) -
ANS False


A false position method is based on the false assumption that the function can be
approximated by a(n) - ANS straight line


1 @COPYRIGHT 2025/2026 ALLRIGHTS RESERVED

, One disadvantage of the Newton-Raphson method is that it requires the user to analytically
find the derivative of the function(T/F) - ANS True


For the fourth iteration in the Newton-Raphson method, you will use the estimated root
location from the third iteration as the new initial point(T/F) - ANS True


Which one of the following functions can be used to find the list of the lower bound and upper
bound that bracket a root? - ANS incsearch



Quadrature is another name for integration(T/F) - ANS True



The key to Guass Quadrature is to balance the function values(T/F) - ANS False



The trapezoidal rule approximates the function by a: - ANS straight line


The Guass Quadrature formulas we discussed in class are called Guess-Legendre formulas.(T/F)
- ANS True



Romberg's method is NOT a newton-Cotes method.(T/F) - ANS False



Simpsons 3/8 rule approximates the function by a _____ order polynomial - ANS Third



The composite Simpson's 1/3 rule requires the number of segments be: - ANS Even



The key to Guass Quadrature is to balance the positive and negative errors.(T/F) - ANS True



Naive Guass elimination ensures that division by zero is not possible(T/F) - ANS False

2 @COPYRIGHT 2025/2026 ALLRIGHTS RESERVED

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