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As-Level Chemistry_ Paper 1 Most Recent exam COMPLETE (2025) EXAM Questions and Answers (Verified Answers) (Latest Update 2025) UPDATE!!

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As-Level Chemistry_ Paper 1 Most Recent exam COMPLETE (2025) EXAM Questions and Answers (Verified Answers) (Latest Update 2025) UPDATE!!

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AQA A LEVEL CHEMISTRY PAPER 1
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AQA A LEVEL CHEMISTRY PAPER 1











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AQA A LEVEL CHEMISTRY PAPER 1
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10/22/25, 7:04 AM As-Level Chemistry: Paper 1 Most Recent exam COMPLETE (2025) EXAM Questions and Answers (Verified Answers) (Latest Up…




As-Level Chemistry: Paper 1 Most Recent exam
COMPLETE (2025) EXAM Questions and Answers
(Verified Answers) (Latest Update 2025) UPDATE!!

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Terms in this set (298)


Arranged in periods How is the periodic table
(rows) and groups arranged
(columns) by atomic
(proton) number

Have the same number of All elements within a period ...
electrons shells, even if
they are not all parts of
the s or p sub-shells

Have the same number of All elements within a group ...
electrons in their outer
shell, meaning that they all
have similar properties

The trends in the physical and
chemical properties of elements
Periodicity
as you go across the periodic
table.




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,10/22/25, 7:04 AM As-Level Chemistry: Paper 1 Most Recent exam COMPLETE (2025) EXAM Questions and Answers (Verified Answers) (Latest Up…


Atomic radius across period 3
goes as follows:
1) As the number of protons
increases the further down a
period you go, the positive
charge of the nucleus increases
2) And though the amount of
electrons increases across a
period, they are added to the
outer energy level - So their isn't
Atomic radius across
any extra shielding
period 3
3) This means that the electrons
are pulled closer to the nucleus,
causing the atomic radius to
decrease
4) Therefore, that overall the
atomic radius of an atom
decreases across period 3 with
the largest radius being the first
element, Na, and the smallest
being the last element, Ar




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,10/22/25, 7:04 AM As-Level Chemistry: Paper 1 Most Recent exam COMPLETE (2025) EXAM Questions and Answers (Verified Answers) (Latest Up…


The melting point across period
3 goes as follows:
1) At the start with sodium,
magnesium and aluminium their
melting points increase. This is
because they are metals and
have strong electrostatic forces
to overcome - The bonds get
stronger by the time you reach
Al due to having and more
positively charged nucleus,
increased number of
delocalised electrons and a
decreasing radius
2) From Al to Silicon, the melting
point increases further as Si is a
macromolecular substance
Melting points across a
which has very strong covalent
period 3
bonds that take a lot of energy
to break
3) However, the melting point
then drops due to phosphorus,
sulfur, chlorine and argon all
being molecular substances.
The issue with being that kind of
substance is that to break the
bonds apart all you need to do
is to overcome the weak Van der
Waals forces - A very easy task
4) The difference in melting
points between P, S, Cl and Ar is
that some molecules are bigger
than others which leads to
slightly greater Van der Waals
forces




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, 10/22/25, 7:04 AM As-Level Chemistry: Paper 1 Most Recent exam COMPLETE (2025) EXAM Questions and Answers (Verified Answers) (Latest Up…


First ionisation energy across
period 3 goes as follows:
1) As you mover across the
period, the general trend is for
the ionisation energy to increase
- This is due to an increase in
number of protons within an
atom as you go across the
period which leads to a stronger
nuclear attraction
2) The electrons do not counter
this increase in protons due to
the electrons remaining in
roughly the same energy level
which means their is little
shielding affect or extra distance
to lessen the attraction from the
nucleus - Though there is a dip
between elements in Mg and Al,
P and S
First ionisation energy
3) The issue between Mg and Al
across period 3
is that Al has a 3p outer orbital
rather than the 3s on Mg.
Because of this the outer most
electron in Al is further away
from the nucleus and has an
extra layer of shielding in the
form of a 3s
4) As for the drop from P to S,
this is because, though the
ionised electron come out of
the same sub-shell for both P
and S. However, in P case the
electron is being removed from
a single occupied shell whereas
is is being removed from an
orbital containing two in S. The

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