1. As33(nonmetal=gainelectrons)1s22s22p63s23p64s23d104p3 gain 3 ’As-3
Ge32 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2
lose 4 ’Ge+4: Whatwillbethechargeoftheionformedfromeachoftheseatoms?Explainyouranswer.
As33,Ge32
2. 1) Cl-O bond electronegativity difference = 3.5 - 3.0 = 0.5
(1.6 - 0.5 bond is Polar)
H-O bond electronegativity difference = 3.5 - 2.1 = 1.4 (1.6 - 0.5
bond is Polar)
2) CaN bond electronegativity difference = 3.0 - 2.5 = 0.5
(1.6 - 0.5 bond is Polar)
H-C bond electronegativity difference = 2.5 - 2.1 = 0.4
(< 0.5 bond is Nonpolar): Using theelectronegativity valuesfromthe equation bank,showthe determina-tionofthepolarityofeachditterenttype
ofbondinthefollowingmolecules:
3. YourAnswer:
NH3
N = 5, H = 3, 8 total H
..
H:N:H
.. SO2
S = 6, O = 12, total = 18
.... ..
:O:S::O
....
CH3OH
C = 4, H = 4, O = 6, total = 14 H
, ....
H:C :O:H
....
H
HNO2
H = 1, N = 5, O = 12, total = 18
.... ..
H:O:N::O:
..
N2
N = 10
: N ::: N :
CH2O
C = 4, H = 2, O = 6, total = 12
....
H : C :: O :H:WriteLewisdotstructuresforthefollowingmolecules:
NH3SO2
CH3OH
HNO2N2
CH2O
4. 1.) PH3 4Groupsofelectronsaround P=TetrahedralElectronGeometry Tetrahedral
Electron Geometry = sp3 Hybridization of P
3 atoms around central Tetrahedral atom = Triangular pyramid shape
P-H bond (2.1-2.1) is nonpolar = all nonpolar bonds = Nonpolar molecular polarity
2.)HCN2Groupsofelectronsaround C=LinearElectron Geometry Linear Electron
Geometry = sp Hybridization of C
2 atoms around central Linear atom = Linear shape
Ge32 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2
lose 4 ’Ge+4: Whatwillbethechargeoftheionformedfromeachoftheseatoms?Explainyouranswer.
As33,Ge32
2. 1) Cl-O bond electronegativity difference = 3.5 - 3.0 = 0.5
(1.6 - 0.5 bond is Polar)
H-O bond electronegativity difference = 3.5 - 2.1 = 1.4 (1.6 - 0.5
bond is Polar)
2) CaN bond electronegativity difference = 3.0 - 2.5 = 0.5
(1.6 - 0.5 bond is Polar)
H-C bond electronegativity difference = 2.5 - 2.1 = 0.4
(< 0.5 bond is Nonpolar): Using theelectronegativity valuesfromthe equation bank,showthe determina-tionofthepolarityofeachditterenttype
ofbondinthefollowingmolecules:
3. YourAnswer:
NH3
N = 5, H = 3, 8 total H
..
H:N:H
.. SO2
S = 6, O = 12, total = 18
.... ..
:O:S::O
....
CH3OH
C = 4, H = 4, O = 6, total = 14 H
, ....
H:C :O:H
....
H
HNO2
H = 1, N = 5, O = 12, total = 18
.... ..
H:O:N::O:
..
N2
N = 10
: N ::: N :
CH2O
C = 4, H = 2, O = 6, total = 12
....
H : C :: O :H:WriteLewisdotstructuresforthefollowingmolecules:
NH3SO2
CH3OH
HNO2N2
CH2O
4. 1.) PH3 4Groupsofelectronsaround P=TetrahedralElectronGeometry Tetrahedral
Electron Geometry = sp3 Hybridization of P
3 atoms around central Tetrahedral atom = Triangular pyramid shape
P-H bond (2.1-2.1) is nonpolar = all nonpolar bonds = Nonpolar molecular polarity
2.)HCN2Groupsofelectronsaround C=LinearElectron Geometry Linear Electron
Geometry = sp Hybridization of C
2 atoms around central Linear atom = Linear shape