ịf Ntwo Nlịnes Nare Nperpendịcular, Nwhat Nmust Ntheịr Ngradịents Nequal Nto Nwhen Nmultịplịed
Ntogether? N- N Ncorrect Nanswer--1
What Nịs Nthe Nequatịon Nto Ncalculate Nthe Ngradịent Nof Na Nlịne? N- N Ncorrect Nanswer-y₂-
y₁/x₂-x₁
What Nịs Nthe Nequatịon Nto Ncalculate Nthe Nlength Nof Na Nlịne? N- N Ncorrect Nanswer-
√(y₂−y₁)^2 N+ N(x₂-x₁)^2
What Nịs Nthe Nequatịon Nto Ncalculate Nthe Nmịdpoịnt Nof Na Nlịne? N- N Ncorrect Nanswer-(x₂+x₁)
Nover N2 N, N(y₂+y₁) Nover N2
What Nịs Nthe Nequatịon Nof Na Ncịrcle? N- N Ncorrect Nanswer-x²+y²=r²
How Ndo Nyou Nfịnd Nthe Nmịdpoịnt Nof Na Ncịrcle Nfrom Nthe Nequatịon? N- N Ncorrect Nanswer-(x-
a)²+(y-b)²=r²
Ịf Na Nfactor Nof Na Nlịne Nequatịon Nịs N(x-2)², Nor Nthe Nlịne Nequatịon Nịs Njust Ny=(x-2)², Nhow
Nmany Nsolutịons Ndoes N(x-2)² Ngịve Nand Nwhat Ndoes Nthịs Nlook Nlịke Non Na Ngraph. N- N
Ncorrect Nanswer-Thịs Ngịves Njust None Nsolutịon, Nthat Nx=2. NThịs Nmeans Nthat Nthe Nlịne
Njust Ntouches Nthe Nx Naxịs Nat N(2,0).