100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached 4.2 TrustPilot
logo-home
Other

3D Coordinate System Homework Exercises

Rating
-
Sold
-
Pages
4
Uploaded on
14-10-2025
Written in
2025/2026

This document presents 10 homework exercises on the 3D coordinate system for Calculus III (Math 250) at California State University, Northridge, taught by Dr. Michael Johnson (with a submission date of August 01, 2025), covering topics such as point projection, distance calculation between points, sphere equation construction and identification, equation graph recognition, coordinate plane equations, distance from a point to coordinate planes, midpoint and distance to the origin, sphere and coordinate plane intersection, and graph comparison in R, R², and R³ coordinate systems, each including questions, solutions, and answers.

Show more Read less
Institution
Math
Course
Math








Whoops! We can’t load your doc right now. Try again or contact support.

Written for

Institution
Math
Course
Math

Document information

Uploaded on
October 14, 2025
Number of pages
4
Written in
2025/2026
Type
Other
Person
Unknown

Content preview

California State University, Northridge - Northridge, CA
Course Name: Calculus III (Math 250)
Professor Name: Dr. Michael Johnson
Assignment Title: 3D Coordinate System Homework Exercises
Submission Date: August 01, 2025


Math 250 3D Coordinate System Homework Exercises
Exercises
1. Point Projection Problem

Question: In a 3D coordinate system, what are the projection points of point P(4, -2,
5) onto the xy-plane, yz-plane, and xz-plane respectively?
Solution:
• The projection onto the xy-plane has z-coordinate 0: (4, -2, 0)
• The projection onto the yz-plane has x-coordinate 0: (0, -2, 5)
• The projection onto the xz-plane has y-coordinate 0: (4, 0, 5)
Answer: Projection onto xy-plane: (4, -2, 0); onto yz-plane: (0, -2, 5); onto xz-plane:
(4, 0, 5)


2. Distance Calculation Between Two Points
Question: Calculate the distance between points A(1, 2, 3) and B(4, 6, 8).
Solution:
Using the distance formula in 3D space:

�(�, �) = (�2 − �1)2 + (�2 − �1)2 + (�2 − �1)2
Substituting the coordinates:

�(�, �) = (4 − 1)2 + (6 − 2)2 + (8 − 3)2 = 32 + 42 + 52 = 9 + 16 + 25 = 50 = 5 2
≈ 7.07

Answer: 5 2 (or approximately 7.07)
$2.99
Get access to the full document:

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached

Get to know the seller
Seller avatar
enricowintheiser

Get to know the seller

Seller avatar
enricowintheiser All Types of Notes
View profile
Follow You need to be logged in order to follow users or courses
Sold
1
Member since
5 months
Number of followers
0
Documents
16
Last sold
5 months ago

0.0

0 reviews

5
0
4
0
3
0
2
0
1
0

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Frequently asked questions