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Exam (elaborations)

Solutions Manual for Structural Dynamics Concepts and Applications 1st Edition by Busby

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Solutions Manual for Structural Dynamics Concepts and Applications 1st Edition by Busby Solutions Manual for Structural Dynamics Concepts and Applications 1st Edition by Busby Solutions Manual for Structural Dynamics Concepts and Applications 1st Edition by Busby Solutions Manual for Structural Dynamics Concepts and Applications 1st Edition by Busby Solutions Manual for Structural Dynamics Concepts and Applications 1st Edition by Busby

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Institution
Structural Dynamics Concepts
Course
Structural Dynamics Concepts











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Institution
Structural Dynamics Concepts
Course
Structural Dynamics Concepts

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Uploaded on
October 9, 2025
Number of pages
208
Written in
2025/2026
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

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AllChaptersCovered
c c




SOLUTIONS

,TableofContents
c c




1. Single-Degree-of-Freedom Systems c




2. Random Vibrations c




3. Dynamic Response of SDOF Systems Using Numerical Methods
c c c c c c c




4. Systems with Several Degrees of Freedom
c c c c c




5. Equations of Motion of Continuous Systems
c c c c c




6. Vibration of Strings and Barsc c c c




7. Beam Vibrations
c




8. Continuous Beams and Frames c c c




9. Vibrations of Plates c c




10. Vibration of Shells c c




11. Finite Elements and Time Integration Numerical Techniques
c c c c c c




12. Shock Spectra c

, Chapter 1 c




1.1 Write the equations of motion for the one-degree-of-freedom systems shown in Figures1.72 (a) … (i). Assume
c c c c c c c c c c c c c c c




that the loading is in the form of a force P(t), a given displacement a(t), or a given rotation
c c c c c c c c c c c c c c c c c c c (t) as indicated in the
c c c c c c




c figure.




Figure 1.72 One-degree-of-freedom systems
c c c




@@SSee
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, Solutions


(a) (b)




spring force = (3EI / L )u 3

( )
c c c c c c




spring force = 48EI / L3 u
c c c c c c
3EI
mu + c
u = P(t)
c c




48EI L3
mu + 3 u = P(t)
c c c c


L c




(c) (d)




spring force = 3EI / L3 u − 3EI / L2 (t)
c c c ( c c ) (
c c c c c )
c




spring force = 3EI / L3
c c c ( c c )(u−a)
c c c mu +c
3EI
c
c


u=
c c
3EI
(t)
c




L3 L2
3EI
mu +
L3
c (u − a)= 0
c
c c c c c




3EI 3EI
mu + u= a(t)
c c


c c c c




L3
L3



(e) (f)




spring force = (EA/ L)u
( ) ( )
c c c c c




EA spring force = 2 3EI / L3 u = 6EI / L3 u
c c c c c c c c c c c



mu + u = P(t)
c c


c c c c
6EI
L mu +c
u = P(t)
c c c



L3




@@SSee
isis
mmiciicsis
oolala
titoionn

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