Solution Manual for Finite Mathematics And Its Applications 13th Edition by Larry J. Goldstein,

SOLUTION MANUAL v




Finite Mathematics & Its Applications
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13th Edition by Larry J. Goldstein,
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Chapters 1 - 12, Complete
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, Contents
Chapter 1: Linear Equations and Straight Lines
v v v v v 1–1
Chapter 2: Matrices
v 2–1

Chapter 3: Linear Programming, A Geometric Approach
v v v v v 3–1

Chapter 4: The Simplex Method
v v v 4–1

Chapter 5: Sets and Counting
v v v 5–1

Chapter 6: Probability
v 6–1

Chapter 7: Probability and Statistics
v v v 7–1

Chapter 8: Markov Processes
v v 8–1

Chapter 9: The Theory of Games
v v v v 9–1

Chapter 10: The Mathematics of Finance
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Chapter 11: Logic
v 11–1

Chapter 12: Difference Equations and Mathematical Models
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, Chapter 1
v




Exercises 1.1 5
v

6. Left 1, down
v v v v




2
1. Right 2, up 3
v v v
y
y


(2, 3)
v



x
x
( –1, – 52 v v )
v




7. Left 20, up 40
2. Left 1, up 4
v v v v


v v v
y
y

(–20, 40)
(–1, 4)
v

v




x
x




8. Right 25, up 30
v v v v


3. Down 2
v v
y
y


(25, 30) v




x
x
(0, –2) v




9. Point Q is 2 units to the left and 2 units up or
4. Right 2
v v v v v v v v v v v v


v



y (—2,2). v




10. Point P is 3 units to the right and 2 units down or
v v v v v v v v v v v v




(3,—2).
x
(2, 0)
v
1 v



11. —2(1)+ (3) =—2+1=—1so yes the point is v v v v v v v v v v v




3
on the line. v v




5. Left 2, up 1 1 v




12. —2(2)+ (6) =—1is false, so no the point is not
v v v
v v v v v v v v v v v v

y
3
on the line v v




(–2, 1) v

x



Copyright © 2023 Pearson Education, Inc.
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, Chapter 1: Linear Equations and Straight Lines
v v v v v v ISM: Finite Math
v v




1 v
24. 0 = 5
v v v




13 —2x + y =—1 Substitute the x and y v v v v v v v v v
no solution v


3
. x-intercept: none v


coordinates of the point into the equation: v v v v v v



f 1 hı f h When x = 0, y = 5
' ,3 →—2 ' 1 ı +1(3)=—1→—1+1=—1 is
v v v v v v v
v
v v


y-intercept: (0, 5)
y' ı 'y ıJ
v v v v v v v v v v
v v v


v

2 J 2 3 vv v v




a false statement. So no the point is not on the
v v v v v v v v v v 25. When y = 0, x = 7 x-
v v v v v v v v




line.
v intercept: (7, 0) 0 v v v




f 1h f1h =7 v v




14 —2 ' ı + ' ı (—1) =—1 is true so yes the point is no solution
.
v v v v v v v v v v




'y3 ıJ 'y3 ıJ y-intercept: none v

v vv




on the line. v v
26. 0 = –8x
v v v




15. m = 5, b = 8
v v v v v v
x=0 v v




x-intercept: (0, 0) v v




16. m = –2 and b = –6
v v v v v v v
y = –8(0) v v




y=0 v v




17. y = 0x + 3; m = 0, b = 3
v v v v v v v v v v v
y-intercept: (0, 0) v v




2 2 1 v




y = x+0; m = , b =0
v v

27 0 = x –1 v v v v


18 v v v v v v v v v v


3
3 3 .
. x=3 v v




19. 14x+7y =21 v v v v v v
x-intercept: (3, 0) v v




1 v



7y =—14x +21v v v v v
y = (0) –1 v v v v




3
y =—2x +3
y = –1
v v v v

v v




y-intercept: (0, –1) v v


20 x — y =3
v v v v
y
. —y =—x +3 v v v v




y = x —3 v v v v




(3, 0)
x
v


21. 3x =5
vv v v v




5 (0, –1) v


x= v v




3
1 2
28. When x = 0, y = 0.
– x+ y =1 0
v v v v v v



22 2
v


3
v v


When x = 1, y = 2.
. v v v v v v




2 v 1 v
y
y = x +10 v v v




3 2
3 v


y = x +15 v v v
(1, 2) v


4 x
(0, 0) v




23. 0 =—4x +8 v v v v




4x = 8 v v




x =2 v v




x-intercept: (2, 0) v v




y = –4(0) + 8
v v v v




y=8 v v




y-intercept: (0, 8) v v




1-2 Copyright © 2023 Pearson Education, Inc. v v v v v