9/21/25, 2:57 PM Quizzes - MATH302 I004 Summer 2025 - APEI
Attempt Score - 100 %
Overall Grade (Highest Attempt) - 100 %
Question 1 point
The least squares regression line for a data set is yˆ=5+0.3x and the
standard deviation of the residuals is 0.52.
Does a case with the values x = -1.59, y = 5.78 qualify as an outlier?
Cannot be determined with the given information
No
Yes
Hide question 1 feedback
,9/21/25, 2:57 PM Quizzes - MATH302 I004 Summer 2025 - APEI
Feedback
Plug in -1.59 for x.
y = 5 + .3*-1.59
y = 4.523
Residual is y-given - y-predicted.
5.78 - 4.523 = 1.257 -> this is the residual value.
To see if it is an outlier take 2 and multiply it by .52
2*.52 = 1.04
1.257 is greater than 1.04, Yes it is an outlier.
Question 2 point
The least squares regression line for a data set is yˆ= -4.6+1.56x
and the standard deviation of the residuals is .52
Does a case with the values x = -1.12, y = -8 qualify as an outlier?
Cannot be determined with the given information
No
Yes
Hide question 2 feedback
Feedback
Plug in -1.12 for x.
y = -4.6 + 1.56(-1.12)
y = -6.3472
Residual is y-given - y-predicted.
-8 - (-6.3472)
, 9/21/25, 2:57 PM Quizzes - MATH302 I004 Summer 2025 - APEI
-8 + 6.3472 = -1.6528 -> this is the residual value.
To see if it is an outlier take -2 and multiply it by .52
-2*.52 = -1.04
-1.6528 is less than -1.04, Yes, it is an outlier because if it outside of the -2 to 2
range.
Question 3 point
The marketing manager of a large supermarket chain would like to
use shelf space to predict the sales of pet food. For a random sample
of 15 similar stores, she gathered the following information regarding
the shelf space, in feet, devoted to pet food and the weekly sales in
hundreds of dollars. .
Shelf Weekly
Store
Space Sales
1 5 1.3
2 5 1.6
3 5 1.4
4 10 1.7
5 10 1.9
6 10 2.3
7 15 2.2
8 15 2
9 15 1.8
10 20 2.2
11 20 2.4
Attempt Score - 100 %
Overall Grade (Highest Attempt) - 100 %
Question 1 point
The least squares regression line for a data set is yˆ=5+0.3x and the
standard deviation of the residuals is 0.52.
Does a case with the values x = -1.59, y = 5.78 qualify as an outlier?
Cannot be determined with the given information
No
Yes
Hide question 1 feedback
,9/21/25, 2:57 PM Quizzes - MATH302 I004 Summer 2025 - APEI
Feedback
Plug in -1.59 for x.
y = 5 + .3*-1.59
y = 4.523
Residual is y-given - y-predicted.
5.78 - 4.523 = 1.257 -> this is the residual value.
To see if it is an outlier take 2 and multiply it by .52
2*.52 = 1.04
1.257 is greater than 1.04, Yes it is an outlier.
Question 2 point
The least squares regression line for a data set is yˆ= -4.6+1.56x
and the standard deviation of the residuals is .52
Does a case with the values x = -1.12, y = -8 qualify as an outlier?
Cannot be determined with the given information
No
Yes
Hide question 2 feedback
Feedback
Plug in -1.12 for x.
y = -4.6 + 1.56(-1.12)
y = -6.3472
Residual is y-given - y-predicted.
-8 - (-6.3472)
, 9/21/25, 2:57 PM Quizzes - MATH302 I004 Summer 2025 - APEI
-8 + 6.3472 = -1.6528 -> this is the residual value.
To see if it is an outlier take -2 and multiply it by .52
-2*.52 = -1.04
-1.6528 is less than -1.04, Yes, it is an outlier because if it outside of the -2 to 2
range.
Question 3 point
The marketing manager of a large supermarket chain would like to
use shelf space to predict the sales of pet food. For a random sample
of 15 similar stores, she gathered the following information regarding
the shelf space, in feet, devoted to pet food and the weekly sales in
hundreds of dollars. .
Shelf Weekly
Store
Space Sales
1 5 1.3
2 5 1.6
3 5 1.4
4 10 1.7
5 10 1.9
6 10 2.3
7 15 2.2
8 15 2
9 15 1.8
10 20 2.2
11 20 2.4
